{"id":1164,"date":"2026-03-10T06:32:18","date_gmt":"2026-03-10T06:32:18","guid":{"rendered":"https:\/\/cn-hawe.com\/?p=1164"},"modified":"2026-03-09T06:37:27","modified_gmt":"2026-03-09T06:37:27","slug":"brake-press-calculator","status":"publish","type":"post","link":"https:\/\/cn-hawe.com\/tr\/brake-press-calculator\/","title":{"rendered":"Abkant Pres Hesaplay\u0131c\u0131 Tuza\u011f\u0131: Neden Tonaj Tahminleri Katlama D\u00fczeltmesi Olmadan Par\u00e7alar\u0131 Mahvediyor"},"content":{"rendered":"

Ge\u00e7en bahar bir \u00e7ocuk, 11 gauge paslanmaz \u00e7elikten 10 fitlik bir \u015feridi \u2014yakla\u015f\u0131k 312 dolarl\u0131k malzeme\u2014 tamamen \u201cg\u00fcvenli\u201d bir kurulumdan ge\u00e7irdi. Hesap makinesi 74 ton diyordu. 135 tonluk presimiz g\u0131k\u0131n\u0131 bile \u00e7\u0131karmad\u0131.<\/p>\n\n\n\n

Her iki bacak da 1\/8 in\u00e7 k\u0131sa \u00e7\u0131kt\u0131.<\/p>\n\n\n\n

Makine sa\u011flamd\u0131. Par\u00e7a ise \u00e7\u00f6p oldu. \u201cG\u00fcvenli vuru\u015f\u201d ile \u201cdo\u011fru par\u00e7a\u201d aras\u0131ndaki o bo\u015fluk, \u00e7o\u011fu gen\u00e7 operat\u00f6r\u00fcn fark\u0131nda olmadan ya\u015fad\u0131\u011f\u0131 yerdir.<\/p>\n\n\n\n

Rahatlat\u0131c\u0131 Yalan: \u201cHesap Makinesi G\u00fcvenli Diyorsa, Sorun Yoktur\u201d<\/h2>\n\n\n\n

Kal\u0131nl\u0131\u011f\u0131, \u00e7ekme dayan\u0131m\u0131n\u0131, kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131n\u0131, b\u00fck\u00fcm uzunlu\u011funu girersiniz. Hesap makinesi temiz bir say\u0131 verir; ye\u015fil \u0131\u015f\u0131k yanar. Matematik arkan\u0131zdaym\u0131\u015f gibi hissedersiniz.<\/p>\n\n\n\n

Size asl\u0131nda \u015funu s\u00f6yledi: E\u011fer bu kadar \u00e7eli\u011fe, bu kadar in\u00e7 boyunca bu kadar kuvvet uygularsan\u0131z, g\u00f6vde b\u00fck\u00fclmez ve hidrolik sistem a\u015f\u0131r\u0131 y\u00fcklenmez. Bir makine sorusunu yan\u0131tlad\u0131.<\/p>\n\n\n\n

M\u00fc\u015fteriniz makine g\u00fcvenli\u011fini sat\u0131n alm\u0131yor. Kumpas kapand\u0131\u011f\u0131nda tam 2,000 in\u00e7 \u00f6l\u00e7en iki bacak sat\u0131n al\u0131yor.<\/p>\n\n\n\n

Peki bu iki soru birbirinden uzakla\u015ft\u0131\u011f\u0131nda ne olur?<\/p>\n\n\n\n

M\u00fckemmel bir tonaj de\u011feri yine de hurda bir par\u00e7a \u00fcretti\u011finde<\/h3>\n\n\n\n
\"M\u00fckemmel<\/figure>\n\n\n\n

0,125 in\u00e7lik yumu\u015fak \u00e7elik bir sac\u0131, 36 in\u00e7 uzunlu\u011funda, 1 in\u00e7lik V kal\u0131b\u0131nda hava b\u00fck\u00fcm\u00fcyle b\u00fck\u00fcld\u00fc\u011f\u00fcn\u00fc hayal edin. Standart form\u00fcl \u2014malzeme dayan\u0131m\u0131 \u00d7 kal\u0131nl\u0131\u011f\u0131n karesi \u00f7 kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131, hepsi b\u00fck\u00fcm uzunlu\u011fuyla \u00e7arp\u0131l\u0131r\u2014 yakla\u015f\u0131k 30 tona ihtiyac\u0131n\u0131z oldu\u011funu s\u00f6yler. 90 tonluk presiniz bunu kolayca halleder.<\/p>\n\n\n\n

30 tona ula\u015f\u0131rs\u0131n\u0131z. B\u00fck\u00fcm temiz olu\u015fur. A\u00e7\u0131 do\u011fru g\u00f6r\u00fcn\u00fcr.<\/p>\n\n\n\n

Ancak i\u00e7 yar\u0131\u00e7ap, teknik resminizin varsayd\u0131\u011f\u0131 gibi de\u011fildir. Malzeme, d\u00fcz sac a\u00e7\u0131l\u0131m\u0131n\u0131z\u0131n hesaba katt\u0131\u011f\u0131ndan daha fazla esner. Bu esneme \u2014b\u00fck\u00fcm pay\u0131\u2014 kuvvettir de\u011fil, geometridir. E\u011fer d\u00fcz sac a\u00e7\u0131l\u0131m\u0131n\u0131z, o 1 in\u00e7lik V kal\u0131b\u0131na ve o z\u0131mba yar\u0131\u00e7ap\u0131na uygun bir b\u00fck\u00fcm d\u00fc\u015f\u00fcm\u00fc yerine genel bir b\u00fck\u00fcm d\u00fc\u015f\u00fcm\u00fc ile hesapland\u0131ysa, flan\u015f uzunlu\u011funuz kayar.<\/p>\n\n\n\n

Tonaj say\u0131s\u0131 m\u00fckemmeldi.<\/p>\n\n\n\n

Par\u00e7an\u0131z hala bacak ba\u015f\u0131na 0,060 in\u00e7 k\u0131sa.<\/p>\n\n\n\n

Hurda Kutusu Uyar\u0131s\u0131: Bu, dramatik g\u00f6r\u00fcnmeyen bir hata t\u00fcr\u00fcd\u00fcr. \u00c7atlak yok. Alet izi yok. Sadece kaynakta hizalanmayan bir par\u00e7a y\u0131\u011f\u0131n\u0131 ve \u201cmatematik do\u011fruydu\u201d denilerek k\u0131rm\u0131z\u0131 kutuya at\u0131lan 480 dolarl\u0131k lazer s\u00fcresi ve paslanmaz \u00e7elik var.\u201d<\/p>\n\n\n\n

Peki kuvvet do\u011fruysa, asl\u0131nda hangi soruyu yan\u0131tlad\u0131k?<\/p>\n\n\n\n

Tonaj, \u201cMakine bunu yapabilir mi?\u201d sorusunu yan\u0131tlar, ancak \u201cPar\u00e7a uyacak m\u0131?\u201d sorusunu de\u011fil.\u201d<\/h3>\n\n\n\n
\"Tonaj<\/figure>\n\n\n\n

Tonaj\u0131 bir kamyonun a\u011f\u0131rl\u0131k kapasitesi olarak d\u00fc\u015f\u00fcn\u00fcn. Aks\u0131n y\u00fck alt\u0131nda k\u0131r\u0131l\u0131p k\u0131r\u0131lmayaca\u011f\u0131n\u0131 size s\u00f6yler. Y\u00fck\u00fcn, i\u015f sahas\u0131na ula\u015fmadan \u00f6nce kay\u0131p kendini ezip ezmeyece\u011fini s\u00f6ylemez.<\/p>\n\n\n\n

B\u00fck\u00fcm terimleriyle, tonaj z\u0131mba ucundaki bas\u0131n\u00e7la ilgilidir. Geometri \u2014b\u00fck\u00fcm d\u00fc\u015f\u00fcm\u00fc, b\u00fck\u00fcm pay\u0131, i\u00e7 yar\u0131\u00e7ap\u2014 ise bu bas\u0131n\u00e7 a\u00e7\u0131y\u0131 olu\u015ftururken malzemenin nas\u0131l ak\u0131p esnedi\u011fiyle ilgilidir.<\/p>\n\n\n\n

Hava b\u00fck\u00fcm\u00fcnden (y\u00f6ntem fakt\u00f6r\u00fc yakla\u015f\u0131k 1,0) taban b\u00fck\u00fcm\u00fcne (5,0 veya daha fazla) ge\u00e7ti\u011finizde, gereken kuvvet be\u015f kat\u0131na \u00e7\u0131kabilir. Hesap makinesi tonaj\u0131 bu y\u00f6ntem fakt\u00f6r\u00fcne g\u00f6re ayarlar. G\u00fczel. Pres hayatta kal\u0131r.<\/p>\n\n\n\n

Ancak b\u00fck\u00fcm pay\u0131n\u0131z da de\u011fi\u015fir, \u00e7\u00fcnk\u00fc alt b\u00fck\u00fcm kuvvetleri malzemeyi kal\u0131b\u0131n i\u00e7ine daha s\u0131k\u0131 bir \u015fekilde iter. Daha k\u00fc\u00e7\u00fck i\u00e7 yar\u0131\u00e7ap. Farkl\u0131 malzeme esnemesi. Pedala dokunmadan \u00f6nce gereken farkl\u0131 d\u00fcz uzunluk.<\/p>\n\n\n\n

E\u011fer kuvveti g\u00fcnceller ve geometriyi g\u00f6rmezden gelirseniz, ko\u00e7u korumu\u015f ancak \u00f6l\u00e7\u00fcleri sabote etmi\u015f olursunuz.<\/p>\n\n\n\n

Uzun vadede hangi hata daha maliyetlidir?<\/p>\n\n\n\n

Geometriyi g\u00f6rmezden gelip kuvvete g\u00fcvenmenin gizli maliyeti<\/h3>\n\n\n\n
\"Geometriyi<\/figure>\n\n\n\n

Baz\u0131 at\u00f6lye sahipleri tonaj\u0131 bilerek y\u00fcksek tahmin eder. Bir makineyi \u00e7atlatmaktansa biraz daha h\u0131zl\u0131 a\u015f\u0131nd\u0131rmay\u0131 tercih ederler. Bu i\u00e7g\u00fcd\u00fcy\u00fc anl\u0131yorum. \u00c7atlak bir pres yan plakas\u0131 alt\u0131 haneli bir kabustur.<\/p>\n\n\n\n

Ancak 85 dolardan yirmi adet 4 fitlik paslanmaz paneli hurdaya ay\u0131rmak, bir vardiyada 1.700 dolar\u0131n gitmesi demektir. Buna saatte 120 dolardan lazer s\u00fcresini, kurulum i\u015f\u00e7ili\u011fini ve birisi \u201cuydurmaya\u201d \u00e7al\u0131\u015ft\u0131\u011f\u0131nda ortaya \u00e7\u0131kan kaynak d\u00fczeltme maliyetini ekleyin. Dramatik bir \u015fekilde de\u011fil, sessizce nakit kaybediyorsunuz.<\/p>\n\n\n\n

Rahatlat\u0131c\u0131 yalan \u015fudur: E\u011fer hesap makinesi vuru\u015fun g\u00fcvenli oldu\u011funu s\u00f6yl\u00fcyorsa, i\u015f kontrol alt\u0131ndad\u0131r.<\/p>\n\n\n\n

Tonaj tahmini, kal\u0131ba \u00f6zel b\u00fck\u00fcm pay\u0131 ile birle\u015ftirilene kadar kontrol alt\u0131nda de\u011fildir; yani tam z\u0131mba yar\u0131\u00e7ap\u0131, tam V a\u00e7\u0131kl\u0131\u011f\u0131 ve tam malzeme partisi d\u00fcz sac a\u00e7\u0131l\u0131m\u0131n\u0131za yans\u0131t\u0131lmal\u0131d\u0131r.<\/p>\n\n\n\n

Bu de\u011fi\u015fimi yapana kadar \u2014\u201cPres hayatta kalacak m\u0131?\u201d sorusundan \u201cBacaklar \u00f6l\u00e7\u00fcye uygun mu?\u201d sorusuna ge\u00e7ene kadar\u2014 yanl\u0131\u015f problemi m\u00fckemmel bir \u015fekilde \u00e7\u00f6z\u00fcyorsunuz demektir.<\/p>\n\n\n\n

Ve bu da as\u0131l soruyu ortaya \u00e7\u0131kar\u0131yor: O kadar g\u00fcvendi\u011finiz tonaj form\u00fcl\u00fcn\u00fcn i\u00e7inde tam olarak ne var?<\/p>\n\n\n\n

Form\u00fcl\u00fcn \u0130\u00e7inde: B\u00fckme Kuvveti Malzeme Esnemesini Nas\u0131l Gizlice De\u011fi\u015ftirir?<\/h2>\n\n\n\n

Standart hava b\u00fckme form\u00fcl\u00fc ve onun yerle\u015fik basitle\u015ftirmeleri<\/h3>\n\n\n\n

\u00c7o\u011fu at\u00f6lye hesap makinesine d\u00f6rt \u015fey girersiniz: malzeme \u00e7ekme dayan\u0131m\u0131, kal\u0131nl\u0131k, kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131, b\u00fck\u00fcm uzunlu\u011fu. Enter tu\u015funa bas\u0131n. Kar\u015f\u0131n\u0131za bir tonaj rakam\u0131 \u00e7\u0131kar.<\/p>\n\n\n\n

Arka planda, bu \u201cstandart\u201d hava b\u00fckme form\u00fcl\u00fc basit bir \u015fey yapar: Fit ba\u015f\u0131na kuvvet = (malzeme dayan\u0131m\u0131 \u00d7 kal\u0131nl\u0131k\u00b2) \u00f7 kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131<\/strong>, ard\u0131ndan uzunluk ile \u00e7arp\u0131l\u0131r. Kal\u0131nl\u0131\u011f\u0131n karesi al\u0131n\u0131r. Kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131 paydada yer al\u0131r. \u00c7ekme dayan\u0131m\u0131 ise t\u00fcm sonucu \u00f6l\u00e7eklendirir.<\/p>\n\n\n\n

\u015eimdi bunu at\u00f6lye uygulamalar\u0131na \u00e7evirelim.<\/p>\n\n\n\n

    \n
  • Kal\u0131nl\u0131\u011f\u0131 iki kat\u0131na \u00e7\u0131kard\u0131\u011f\u0131n\u0131zda, sadece direnci art\u0131rmazs\u0131n\u0131z; karesini al\u0131rs\u0131n\u0131z. Bu y\u00fczden 0,250 sac, 0,125'ten tamamen farkl\u0131 bir evren gibi hissettirir.<\/li>\n\n\n\n
  • V-kal\u0131b\u0131 geni\u015fletti\u011finizde, gereken kuvveti b\u00f6lersiniz. Daha b\u00fcy\u00fck a\u00e7\u0131kl\u0131k, daha az tonaj demektir.<\/li>\n\n\n\n
  • 36 ksi yumu\u015fak \u00e7elikten 70 ksi paslanmaz \u00e7eli\u011fe ge\u00e7ti\u011finizde, ko\u00e7a neredeyse iki kat\u0131 bask\u0131 uygulamas\u0131 gerekti\u011fini s\u00f6yl\u00fcyorsunuz demektir.<\/li>\n<\/ul>\n\n\n\n

    Bu temiz bir matematik. \u00c7er\u00e7eveyi korur.<\/p>\n\n\n\n

    Ancak neyin eksik oldu\u011funa bak\u0131n. O denklemde z\u0131mba yar\u0131\u00e7ap\u0131 yok. N\u00f6tr eksen konumu yok. Geri yaylanma terimi yok. K-fakt\u00f6r\u00fc yok; yani metalin kal\u0131nl\u0131\u011f\u0131n\u0131n ne kadar derininde ger\u00e7ekten esnedi\u011fini size s\u00f6yleyen o oran. Form\u00fcl, i\u00e7 yar\u0131\u00e7ap\u0131n V-a\u00e7\u0131kl\u0131\u011f\u0131n\u0131n tahmin edilebilir bir kesri olarak olu\u015ftu\u011fu ve n\u00f6tr eksenin uslu durdu\u011fu \u201ctipik\u201d bir hava b\u00fck\u00fcm\u00fcn\u00fc varsayar.<\/p>\n\n\n\n

    Varsayar.<\/p>\n\n\n\n

    Bu, bir kamyonu sadece a\u011f\u0131rl\u0131k kapasitesine g\u00f6re y\u00fcklemek gibidir. Aks k\u0131r\u0131lmaz. G\u00fczel. Ancak form\u00fcl, y\u00fck\u00fcn nas\u0131l ba\u011fland\u0131\u011f\u0131n\u0131 asla sormaz.<\/p>\n\n\n\n

    Hurda Kutusu Uyar\u0131s\u0131: Tonaj \u00e7\u0131kt\u0131s\u0131n\u0131 ayn\u0131 zamanda i\u00e7 yar\u0131\u00e7ap\u0131 da tahmin ediyormu\u015f gibi ele ald\u0131\u011f\u0131n\u0131zda, flan\u015f ba\u015f\u0131na s\u00fcrekli olarak 0,040\u20130,090 k\u0131sa par\u00e7alar g\u00f6r\u00fcrs\u00fcn\u00fcz. Temiz g\u00f6r\u00fcn\u00fcrler. A\u00e7\u0131lar kontrol edilir. Ancak d\u00fcz par\u00e7a, form\u00fcl\u00fcn size asla vaat etmedi\u011fi bir yar\u0131\u00e7ap \u00fczerine in\u015fa edilmi\u015ftir.<\/p>\n\n\n\n

    Peki, kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131 paydada yer al\u0131yorsa, onu de\u011fi\u015ftirdi\u011finizde metale ger\u00e7ekte ne olur?<\/p>\n\n\n\n

    V-Kal\u0131p mekanizmas\u0131: Kal\u0131b\u0131 geni\u015fletmek tonaj\u0131 d\u00fc\u015f\u00fcr\u00fcr, ancak n\u00f6tr ekseni kayd\u0131r\u0131r<\/h3>\n\n\n\n

    Bir keresinde bir ustaba\u015f\u0131n\u0131n, pres konfor alan\u0131na yakla\u015ft\u0131\u011f\u0131 i\u00e7in 10 ayar yumu\u015fak \u00e7elikte 1 in\u00e7lik bir V kal\u0131b\u0131n\u0131 1,5 in\u00e7lik bir V kal\u0131b\u0131 ile de\u011fi\u015ftirdi\u011fini izledim. Hesap makinesi tonaj\u0131n \u00fc\u00e7te bir oran\u0131nda d\u00fc\u015fece\u011fini s\u00f6yl\u00fcyordu.<\/p>\n\n\n\n

    \u00d6yle de oldu.<\/p>\n\n\n\n

    Ko\u00e7 daha hafif hissettirdi. Pompa daha so\u011fuk \u00e7al\u0131\u015ft\u0131. Herkes rahatlad\u0131.<\/p>\n\n\n\n

    Fiziksel olarak ne de\u011fi\u015fti? Daha geni\u015f bir V-kal\u0131b\u0131 ile sac, akmaya ba\u015flamadan \u00f6nce daha uzun bir bo\u015flu\u011fu kapsar. Z\u0131mba, malzeme daha geni\u015f bir taban \u00fczerinde b\u00fck\u00fcld\u00fc\u011f\u00fc i\u00e7in ayn\u0131 a\u00e7\u0131ya ula\u015fmak ad\u0131na daha derine inmek zorundad\u0131r. Bu, ortaya \u00e7\u0131kan i\u00e7 yar\u0131\u00e7ap\u0131 art\u0131r\u0131r; hava b\u00fck\u00fcm\u00fcnde i\u00e7 yar\u0131\u00e7ap genellikle V-a\u00e7\u0131kl\u0131\u011f\u0131n\u0131n belirli bir kesridir. Kal\u0131b\u0131 daha geni\u015f a\u00e7arsan\u0131z, yar\u0131\u00e7ap da onunla birlikte b\u00fcy\u00fcr.<\/p>\n\n\n\n

    \u015eimdi kuvveti de\u011fil, esnemeyi d\u00fc\u015f\u00fcn\u00fcn. B\u00fck\u00fcm\u00fcn d\u0131\u015f lifleri, o daha b\u00fcy\u00fck yar\u0131\u00e7ap etraf\u0131nda daha uza\u011fa gitmek zorundad\u0131r. Bu, flan\u015flardan b\u00fck\u00fcm b\u00f6lgesine ne kadar malzeme \u00e7ekildi\u011fini de\u011fi\u015ftirir. Ve n\u00f6tr eksen \u2014 kal\u0131nl\u0131\u011f\u0131n i\u00e7inde ne esneyen ne de s\u0131k\u0131\u015fan hayali katman \u2014 gerinim da\u011f\u0131l\u0131m\u0131 de\u011fi\u015ftik\u00e7e konum de\u011fi\u015ftirir.<\/p>\n\n\n\n

    Sadece \u201ctonaj\u0131 d\u00fc\u015f\u00fcrmediniz.\u201d Esneme geometrisini de\u011fi\u015ftirdiniz.<\/p>\n\n\n\n

    Peki ya d\u00fcz par\u00e7a a\u00e7\u0131l\u0131m\u0131n\u0131z? Eski kal\u0131ba ba\u011fl\u0131 bir b\u00fck\u00fcm pay\u0131 ile hesaplanm\u0131\u015ft\u0131. Bu pay, daha k\u00fc\u00e7\u00fck bir i\u00e7 yar\u0131\u00e7ap ve belirli bir n\u00f6tr eksen konumu varsay\u0131yordu. Daha geni\u015f kal\u0131pla, daha fazla malzeme bacaklarda kal\u0131r ve yay i\u00e7inde daha az\u0131 t\u00fcketilir \u2014 veya kal\u0131nl\u0131k-yar\u0131\u00e7ap oran\u0131na ba\u011fl\u0131 olarak tam tersi olur. Her iki durumda da sonu\u00e7 farkl\u0131d\u0131r.<\/p>\n\n\n\n

    Hesap makinesi pres hayatta kald\u0131\u011f\u0131 i\u00e7in kutlama yapt\u0131. Kaynak masas\u0131 ise d\u00f6rt b\u00fck\u00fcm boyunca kutu 0,125 geni\u015fledi\u011fi i\u00e7in lanet okudu.<\/p>\n\n\n\n

    Hurda Kutusu Uyar\u0131s\u0131: Bu hata, d\u00fcz bir masada sallanan montaj par\u00e7alar\u0131 olarak kendini g\u00f6sterir. K\u00f6\u015fegenler e\u015fle\u015fmez. Ger\u00e7ek hatan\u0131n, biri b\u00fck\u00fcm pay\u0131n\u0131 g\u00fcncellemeden V kal\u0131b\u0131n\u0131 geni\u015fletti\u011finde yap\u0131ld\u0131\u011f\u0131n\u0131 fark etmeyerek, bunu k\u0131ska\u00e7lar ve \u0131s\u0131yla d\u00fczeltmeye \u00e7al\u0131\u015f\u0131rs\u0131n\u0131z.<\/p>\n\n\n\n

    Peki, kal\u0131p geni\u015fli\u011fi esnemeyi sessizce de\u011fi\u015ftiriyorsa, t\u00fcm b\u00fck\u00fcm y\u00f6ntemini de\u011fi\u015ftirdi\u011finizde ne olur?<\/p>\n\n\n\n

    Hava b\u00fck\u00fcm\u00fc ve tabana oturtma (bottoming): Hesap makinesi hangi fizi\u011fi uygulad\u0131\u011f\u0131n\u0131z\u0131 biliyor mu?<\/h3>\n\n\n\n

    Hava b\u00fck\u00fcm\u00fc ve tabana oturtma ayn\u0131 malzemeyi, kal\u0131nl\u0131\u011f\u0131 ve kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131n\u0131 payla\u015fabilir; ancak tamamen farkl\u0131 fizik kurallar\u0131 gerektirebilir.<\/p>\n\n\n\n

    Hava b\u00fck\u00fcm\u00fc k\u0131smi temas kullan\u0131r. Z\u0131mba sac\u0131 V i\u00e7ine bast\u0131r\u0131r, ancak malzeme kal\u0131p duvarlar\u0131na tam olarak uyum sa\u011flamaz. A\u00e7\u0131, z\u0131mba derinli\u011fi ile kontrol edilir. Geri yaylanma ger\u00e7ektir ve telafi edilmelidir. Tonaj nispeten d\u00fc\u015f\u00fckt\u00fcr.<\/p>\n\n\n\n

    Dip b\u00fckme, sac\u0131n kal\u0131p y\u00fczeylerine daha tam temas etmesini sa\u011flar. Malzeme, kal\u0131p a\u00e7\u0131s\u0131na daha yak\u0131n bir \u015fekilde zorlan\u0131r. Geri yaylanma d\u00fc\u015fer. Hassasiyet artar. Tonaj, ayn\u0131 kal\u0131nl\u0131ktaki hava b\u00fckmeye k\u0131yasla be\u015f ila otuz kat daha y\u00fcksek olabilir.<\/p>\n\n\n\n

    Hesap makinesi bunu genellikle bir \u201cy\u00f6ntem fakt\u00f6r\u00fc\u201d ile halleder. Hava b\u00fckme tonaj\u0131n\u0131 dip b\u00fckme i\u00e7in be\u015f veya daha fazla ile \u00e7arp\u0131n. Makine korunur. G\u00f6vde sa\u011flam kal\u0131r.<\/p>\n\n\n\n

    Ancak gen\u00e7 operat\u00f6rlerin g\u00f6zden ka\u00e7\u0131rd\u0131\u011f\u0131 k\u0131s\u0131m \u015fudur: dip b\u00fckme ayn\u0131 zamanda daha s\u0131k\u0131, kal\u0131p kontroll\u00fc bir i\u00e7 yar\u0131\u00e7ap olu\u015fumunu zorlar. Malzemenin V-a\u00e7\u0131kl\u0131\u011f\u0131na dayal\u0131 do\u011fal bir hava b\u00fckme yar\u0131\u00e7ap\u0131 se\u00e7mesine izin vermezsiniz; z\u0131mba ve kal\u0131p geometrisine daha yak\u0131n bir yar\u0131\u00e7ap dayat\u0131rs\u0131n\u0131z. Bu, d\u0131\u015f liflerin ne kadar \u015fiddetli esnedi\u011fini ve n\u00f6tr eksenin nerede sabitlendi\u011fini de\u011fi\u015ftirir.<\/p>\n\n\n\n

    E\u011fer a\u00e7\u0131n\u0131m\u0131n\u0131z bir hava b\u00fckme K-fakt\u00f6r\u00fcne g\u00f6re olu\u015fturulduysa ve eski bir preste a\u00e7\u0131 tutars\u0131zl\u0131\u011f\u0131n\u0131 d\u00fczeltmek i\u00e7in par\u00e7ay\u0131 dip b\u00fckme yap\u0131yorsan\u0131z, b\u00fck\u00fcm d\u00fc\u015f\u00fcm\u00fcn\u00fcze haber vermeden malzeme ak\u0131\u015f\u0131n\u0131 de\u011fi\u015ftirmi\u015f olursunuz.<\/p>\n\n\n\n

    Hesap makinesinin umurunda de\u011fildir. Sordu\u011funuz kuvvet sorusunu yan\u0131tlam\u0131\u015ft\u0131r.<\/p>\n\n\n\n

    Hurda Kutusu Uyar\u0131s\u0131: Bu hata, a\u00e7\u0131 olarak tam isabet eden ancak flan\u015f uzunlu\u011funda s\u00fcrekli hata veren par\u00e7alar olarak ortaya \u00e7\u0131kar; parti parti, tutarl\u0131 bir hata. B\u00fck\u00fcm y\u00f6nteminin esnemeyi de\u011fi\u015ftirdi\u011fini kabul etmeden \u00f6nce arka dayamay\u0131 su\u00e7lars\u0131n\u0131z.<\/p>\n\n\n\n

    Kal\u0131p geni\u015fli\u011fini ve y\u00f6ntemi sabitleseniz bile, form\u00fcl\u00fcn kibar bir \u00f6neri gibi ele ald\u0131\u011f\u0131 bir de\u011fi\u015fken vard\u0131r.<\/p>\n\n\n\n

    Ger\u00e7ek d\u00fcnyadaki \u00e7ekme dayan\u0131m\u0131 de\u011fi\u015fimleri ders kitab\u0131 matemati\u011fini ne kadar \u015fiddetli bir \u015fekilde bozar<\/h3>\n\n\n\n

    \u201cA36 yumu\u015fak \u00e7elik\u201d etiketli iki sac levha al\u0131n. Biri 58 ksi \u00e7ekme dayan\u0131m\u0131 testinden ge\u00e7er. Bir sonraki parti 72 ksi ile gelir. Her ikisi de yasal olarak ayn\u0131 kalitede sat\u0131l\u0131r.<\/p>\n\n\n\n

    Hesap makinesine 60 ksi girerseniz rahat bir tonaj de\u011feri al\u0131rs\u0131n\u0131z. Ancak daha y\u00fcksek dayan\u0131ml\u0131 sac, akmaya kar\u015f\u0131 daha uzun s\u00fcre direnir. Z\u0131mba, b\u00fck\u00fcm ayn\u0131 a\u00e7\u0131ya ula\u015fmadan \u00f6nce daha derine iner. Hava b\u00fckmede daha derin penetrasyon genellikle biraz daha k\u00fc\u00e7\u00fck bir efektif i\u00e7 yar\u0131\u00e7ap ve farkl\u0131 bir geri yaylanma davran\u0131\u015f\u0131 anlam\u0131na gelir.<\/p>\n\n\n\n

    Ayn\u0131 kal\u0131p. Ayn\u0131 strok ayar\u0131. Farkl\u0131 esneme.<\/p>\n\n\n\n

    Daha y\u00fcksek \u00e7ekme dayan\u0131m\u0131, malzeme akma \u00f6ncesinde daha y\u00fcksek gerilime dayanabildi\u011fi i\u00e7in n\u00f6tr ekseni b\u00fck\u00fcm\u00fcn i\u00e7 k\u0131sm\u0131na do\u011fru kayd\u0131r\u0131r. Bu, kal\u0131nl\u0131\u011f\u0131n \u00e7ekme ve basma alt\u0131ndaki oran\u0131n\u0131 de\u011fi\u015ftirir. B\u00fck\u00fcm pay\u0131 de\u011fi\u015fir; her durumda dramatik olmasa da, birden fazla b\u00fck\u00fcmde hata birikir.<\/p>\n\n\n\n

    Form\u00fcl, kuvveti \u00e7ekme dayan\u0131m\u0131 ile do\u011frusal olarak \u00f6l\u00e7eklendirir. Geometriyi ayn\u0131 hassasiyetle \u00f6l\u00e7eklendirmez.<\/p>\n\n\n\n

    Ge\u00e7en bahar bir gen\u00e7, 11-gauge paslanmaz \u00e7elikten 10 fitlik bir \u015feridi\u2014de\u011feri 312 dolar olan bir malzeme\u2014tamamen \u201cg\u00fcvenli\u201d bir kurulumdan ge\u00e7irdi. Hesap makinesi 74 ton dedi. Presin kapasitesi fazlas\u0131yla yeterliydi. Ancak paslanmaz \u00e7elik partisi bir \u00f6nceki \u00e7al\u0131\u015fmadan daha sertti. Ayn\u0131 program. Ayn\u0131 kal\u0131p. Flan\u015flar k\u0131sa kald\u0131.<\/p>\n\n\n\n

    Makine kuvvet talebine yan\u0131t verdi. Metal ise farkl\u0131 bir esneme ile yan\u0131t verdi.<\/p>\n\n\n\n

    Hurda Kutusu Uyar\u0131s\u0131: A\u00e7\u0131 olarak \u00f6l\u00e7\u00fcm\u00fc d\u00fczg\u00fcn olan ancak bir \u00f6nceki partiye k\u0131yasla flan\u015f ba\u015f\u0131na 0,020\u20130,030\u201cluk bir arka dayama ayar\u0131 gerektiren ilk numune par\u00e7alara dikkat edin. E\u011fer bunu, \u00e7ekme dayan\u0131m\u0131na ba\u011fl\u0131 b\u00fck\u00fcm d\u00fc\u015f\u00fcm\u00fcn\u00fc g\u00fcncellemeden \u201dd\u00fczeltirseniz\u201d, gelecekteki her \u00fcretimde istikrars\u0131zl\u0131\u011f\u0131 kal\u0131c\u0131 hale getirirsiniz.<\/p>\n\n\n\n

    \u015eimdi modeli g\u00f6r\u00fcyorsunuz. Kal\u0131nl\u0131\u011f\u0131n karesi. Kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131n\u0131n b\u00f6l\u00fcnmesi. \u00c7ekme dayan\u0131m\u0131n\u0131n \u00e7arp\u0131lmas\u0131. Y\u00f6ntem fakt\u00f6r\u00fcn\u00fcn uygulanmas\u0131. Hepsi demirin k\u0131r\u0131lmas\u0131n\u0131 \u00f6nlemek i\u00e7in tasarland\u0131.<\/p>\n\n\n\n

    Ancak bu girdilerin her biri, metalin nas\u0131l esnedi\u011fini, n\u00f6tr eksenin nerede durdu\u011funu ve b\u00fck\u00fcm i\u00e7ine ne kadar d\u00fcz uzunlu\u011fun kayboldu\u011funu da etkiler.<\/p>\n\n\n\n

    Yani as\u0131l soru hesap makinesinin yanl\u0131\u015f olup olmad\u0131\u011f\u0131 de\u011fildir.<\/p>\n\n\n\n

    As\u0131l soru, bir kuvvet denkleminin bir geometri problemini dikte etmesine izin verip vermeyece\u011finizdir.<\/p>\n\n\n\n

    Eksik Entegrasyon: B\u00fck\u00fcm Pay\u0131n\u0131 Tonaj Hesab\u0131n\u0131zla \u0130li\u015fkilendirmek<\/h2>\n\n\n\n

    Abkant presin ba\u015f\u0131nda, 0,250 in\u00e7lik A36 malzemeden iki adet 2,000 in\u00e7lik flan\u015f ve 4,000 in\u00e7lik bir g\u00f6vde gerektiren bir par\u00e7a teknik resmiyle duruyorsunuz. Tonaj tablosunu kontrol ediyorsunuz: 2 in\u00e7lik bir V-kal\u0131p \u00fczerinde ayak ba\u015f\u0131na 19,7 ton, yani 10 feet boyunca 197 ton gerektiriyor. 150 tonluk presiniz bundan ho\u015flanmayacakt\u0131r. Bu y\u00fczden 3 in\u00e7lik bir kal\u0131ba ge\u00e7iyorsunuz. \u015eimdi yakla\u015f\u0131k 139 tondas\u0131n\u0131z. Makine g\u00fcvende. Ye\u015fil \u0131\u015f\u0131k yan\u0131yor.<\/p>\n\n\n\n

    Ancak par\u00e7an\u0131n a\u00e7\u0131n\u0131m\u0131, daha k\u00fc\u00e7\u00fck kal\u0131b\u0131n i\u00e7 yar\u0131\u00e7ap\u0131 varsay\u0131larak olu\u015fturulmu\u015ftu.<\/p>\n\n\n\n

    \u00c7o\u011fu at\u00f6lyenin g\u00f6zden ka\u00e7\u0131rd\u0131\u011f\u0131 an budur. Presi korumak i\u00e7in se\u00e7ti\u011finiz kal\u0131p, b\u00fck\u00fcm pay\u0131n\u0131 (yay i\u00e7inde t\u00fcketilen malzeme uzunlu\u011fu) de\u011fi\u015ftirdi ve hesap makineniz size bunun ger\u00e7ekle\u015fti\u011fini asla s\u00f6ylemedi. E\u011fer tonaj form\u00fcl\u00fc sadece \u201cMakineye a\u015f\u0131r\u0131 y\u00fck bindirecek miyim?\u201d sorusuna cevap veriyorsa, \u201cFlan\u015flar\u0131m tam \u00f6l\u00e7\u00fcs\u00fcnde olacak m\u0131?\u201d sorusuna ne cevap veriyor?\u201d<\/p>\n\n\n\n

    Kuvvet hesaplamalar\u0131 ge\u00e7erli olsa bile boyutsal do\u011fruluk neden ba\u015far\u0131s\u0131z olur?<\/h3>\n\n\n\n

    Bir ustaba\u015f\u0131n\u0131n, orijinal kurulum \u201ca\u011f\u0131r\u201d geldi\u011fi i\u00e7in 0,125 in\u00e7lik paslanmaz \u00e7elikte 1,5 in\u00e7lik V kal\u0131b\u0131 2 in\u00e7lik V kal\u0131pla de\u011fi\u015ftirdi\u011fini izledim. Tonaj d\u00fc\u015ft\u00fc. Presin g\u0131c\u0131rt\u0131s\u0131 durdu. Herkes rahatlad\u0131.<\/p>\n\n\n\n

    Par\u00e7alar b\u00fcy\u00fcd\u00fc.<\/p>\n\n\n\n

    Hava b\u00fckmede i\u00e7 yar\u0131\u00e7ap, teknik resimdeki bir say\u0131 de\u011fil; kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131n\u0131n ve malzemenin bir fonksiyonudur. Daha geni\u015f bir V-kal\u0131p genellikle daha b\u00fcy\u00fck bir i\u00e7 yar\u0131\u00e7ap \u00fcretir. Daha b\u00fcy\u00fck yar\u0131\u00e7ap, d\u0131\u015f liflerin derece ba\u015f\u0131na daha az \u015fiddetli gerilmesi anlam\u0131na gelir ve n\u00f6tr eksen (uzunlu\u011fu de\u011fi\u015fmeyen katman) kal\u0131nl\u0131k i\u00e7inde yer de\u011fi\u015ftirir. B\u00fck\u00fcm pay\u0131 de\u011fi\u015fir \u00e7\u00fcnk\u00fc metalin ne kadar\u0131n\u0131n gerildi\u011fine kar\u015f\u0131 ne kadar\u0131n\u0131n s\u0131k\u0131\u015ft\u0131\u011f\u0131n\u0131 fiziksel olarak de\u011fi\u015ftirmi\u015f olursunuz.<\/p>\n\n\n\n

    Tonaj hesaplaman\u0131z ge\u00e7ti \u00e7\u00fcnk\u00fc sadece kuvveti de\u011ferlendiriyor: kal\u0131nl\u0131\u011f\u0131n karesi, \u00e7ekme dayan\u0131m\u0131 ile \u00e7arp\u0131lm\u0131\u015f, kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131na b\u00f6l\u00fcnm\u00fc\u015f. N\u00f6tr eksenin nereye kayd\u0131\u011f\u0131 hakk\u0131nda hi\u00e7bir fikri yok. D\u00fcz kenar\u0131n yerini ne kadar yay uzunlu\u011funun ald\u0131\u011f\u0131n\u0131 \u00f6nemsemiyor.<\/p>\n\n\n\n

    B\u00f6ylece makine hayatta kal\u0131rken a\u00e7\u0131n\u0131m yalan s\u00f6yl\u00fcyor.<\/p>\n\n\n\n

    Hurda Kutusu Uyar\u0131s\u0131: Bu durum, d\u00f6rt b\u00fck\u00fcml\u00fc bir par\u00e7an\u0131n her aya\u011f\u0131nda 0,030 in\u00e7lik tutarl\u0131 bir flan\u015f b\u00fcy\u00fcmesi olarak ortaya \u00e7\u0131kar. A\u00e7\u0131 m\u00fckemmeldir. Arka dayama tekrarlanabilirdir. Montajlar g\u00f6nyeye gelmez ve operat\u00f6r becerisi yerine kal\u0131p de\u011fi\u015fiminin b\u00fck\u00fcm d\u00fc\u015f\u00fc\u015f\u00fcn\u00fc de\u011fi\u015ftirdi\u011fini kabul etmeden \u00f6nce donan\u0131mda 0 israf edersiniz.<\/p>\n\n\n\n

    E\u011fer kal\u0131p geni\u015fli\u011fi geometriyi de\u011fi\u015ftiriyorsa, bir sonraki soru barizdir: b\u00fck\u00fcm pay\u0131n\u0131z\u0131 belirleyen K-fakt\u00f6r\u00fcn\u00fc ilk etapta nas\u0131l se\u00e7iyorsunuz?<\/p>\n\n\n\n

    K-Fakt\u00f6r\u00fc ikilemi: Tahmin etmek yerine tak\u0131m kurulumunuzdan t\u00fcretmek<\/h3>\n\n\n\n

    \u00c7o\u011fu CAD sistemi varsay\u0131lan olarak 0,33 civar\u0131nda bir K-fakt\u00f6r\u00fc kullan\u0131r. Bu nazik bir tahmindir; b\u00fckme s\u0131ras\u0131nda n\u00f6tr eksenin i\u00e7 y\u00fczeyden yakla\u015f\u0131k \u00fc\u00e7te bir oran\u0131nda i\u00e7eride durdu\u011funu varsayar.<\/p>\n\n\n\n

    \u015eimdi sahada ger\u00e7ekte neler oldu\u011funu hayal edin. 0,187 in\u00e7lik 304 paslanmaz \u00e7eli\u011fi, keskin bir z\u0131mba ucuyla 1,5 in\u00e7lik V-kal\u0131pta \u00e7al\u0131\u015ft\u0131r\u0131yorsunuz. Paslanmaz \u00e7elik, yumu\u015fak \u00e7eli\u011fe g\u00f6re daha y\u00fcksek akma dayan\u0131m\u0131na ve daha fazla geri esnemeye sahiptir. Telafi etmek i\u00e7in fazla b\u00fckersiniz. Z\u0131mba, a\u00e7\u0131 oturmadan \u00f6nce daha derine n\u00fcfuz eder. Malzeme A36'dan farkl\u0131 \u015fekilde akar.<\/p>\n\n\n\n

    Bu fiziksel ger\u00e7eklik n\u00f6tr ekseni kayd\u0131r\u0131r.<\/p>\n\n\n\n

    K-fakt\u00f6r\u00fc sihirli bir malzeme sabiti de\u011fildir. O kal\u0131nl\u0131k, o kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131, o z\u0131mba yar\u0131\u00e7ap\u0131 ve o y\u00f6ntem i\u00e7in n\u00f6tr eksenin nerede bitti\u011finin bir tan\u0131m\u0131d\u0131r. Bunlardan herhangi birini de\u011fi\u015ftirdi\u011finizde onu da hareket ettirmi\u015f olursunuz. Tonaj\u0131 160 tondan 120 tona d\u00fc\u015f\u00fcrmek i\u00e7in daha geni\u015f bir kal\u0131p se\u00e7tiyseniz, i\u00e7 yar\u0131\u00e7ap\u0131 da etkilemi\u015f olursunuz; bu da kal\u0131nl\u0131k boyunca gerinim da\u011f\u0131l\u0131m\u0131n\u0131 de\u011fi\u015ftirir ve bu da K'y\u0131 de\u011fi\u015ftirir.<\/p>\n\n\n\n

    Bu y\u00fczden, kal\u0131plar\u0131 tonaja g\u00f6re se\u00e7erken K'y\u0131 genel bir tablodan t\u00fcretmek, arka dayaman\u0131z\u0131 \u201cyak\u0131n oldu\u011fu i\u00e7in\u201d ge\u00e7en y\u0131lki i\u015fe g\u00f6re ayarlamaya benzer.\u201d<\/p>\n\n\n\n

    Disiplinli yol, sahadan geriye do\u011fru gitmektir: tam tak\u0131mla bir test b\u00fck\u00fcm\u00fc yap\u0131n, ger\u00e7ek i\u00e7 yar\u0131\u00e7ap\u0131 \u00f6l\u00e7\u00fcn, flan\u015f uzunluklar\u0131n\u0131 \u00f6l\u00e7\u00fcn, ger\u00e7ek b\u00fck\u00fcm pay\u0131n\u0131 hesaplay\u0131n ve ard\u0131ndan ger\u00e7ekli\u011fe uyan K'y\u0131 \u00e7\u00f6z\u00fcn. Art\u0131k a\u00e7\u0131n\u0131m\u0131n\u0131z bir yaz\u0131l\u0131m varsay\u0131m\u0131n\u0131 de\u011fil, fiziksel kurulumunuzu yans\u0131t\u0131r.<\/p>\n\n\n\n

    N\u00f6tr ekseni tahmin etmezsiniz. Metalin size nereye gitti\u011fini g\u00f6stermesine izin verirsiniz.<\/p>\n\n\n\n

    K'nin tak\u0131mlamaya ba\u011fl\u0131 oldu\u011funu kabul etti\u011finizde, kuvvet ve geometri aras\u0131nda yaratt\u0131\u011f\u0131n\u0131z d\u00f6ng\u00fcy\u00fc g\u00f6rmeye ba\u015flars\u0131n\u0131z.<\/p>\n\n\n\n

    Gerekli kuvvet, i\u00e7 yar\u0131\u00e7ap ve nihai boyutlar aras\u0131ndaki geri besleme d\u00f6ng\u00fcs\u00fc<\/h3>\n\n\n\n

    1,5 in\u00e7lik V kal\u0131p ile 2 in\u00e7lik V kal\u0131p \u00f6rne\u011fini ele alal\u0131m. Daha dar kal\u0131p, hava b\u00fckmede daha dar bir i\u00e7 yar\u0131\u00e7ap anlam\u0131na gelir. Daha dar yar\u0131\u00e7ap, d\u0131\u015f lifler \u00fczerindeki gerilimi art\u0131r\u0131r. Daha y\u00fcksek gerilim, malzemenin akmas\u0131 i\u00e7in daha fazla kuvvet gerektirir. Kal\u0131p a\u011fz\u0131n\u0131 kapatt\u0131\u011f\u0131n\u0131zda tonaj\u0131n f\u0131rlamas\u0131n\u0131n nedeni budur.<\/p>\n\n\n\n

    Bu y\u00fczden presi korumak i\u00e7in kal\u0131b\u0131 geni\u015fletirsiniz. Malzeme o kadar s\u0131k\u0131 b\u00fck\u00fclmedi\u011fi i\u00e7in kuvvet d\u00fc\u015fer. Ancak ayn\u0131 gev\u015feme, i\u00e7 yar\u0131\u00e7ap\u0131 art\u0131r\u0131r ve bu da derece ba\u015f\u0131na b\u00fck\u00fcm pay\u0131n\u0131 azalt\u0131r.<\/p>\n\n\n\n

    Daha az kuvvet. Farkl\u0131 yar\u0131\u00e7ap. Farkl\u0131 d\u00fcz uzunluk.<\/p>\n\n\n\n

    Bu kapal\u0131 bir d\u00f6ng\u00fcd\u00fcr:<\/p>\n\n\n\n

      \n
    • Kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131, gerekli kuvveti de\u011fi\u015ftirir.<\/li>\n\n\n\n
    • Gerekli kuvvet, hangi kal\u0131b\u0131 kullanabilece\u011finizi s\u0131n\u0131rlar.<\/li>\n\n\n\n
    • O kal\u0131p, i\u00e7 yar\u0131\u00e7ap\u0131 belirler.<\/li>\n\n\n\n
    • \u0130\u00e7 yar\u0131\u00e7ap, n\u00f6tr eksen konumunu belirler.<\/li>\n\n\n\n
    • N\u00f6tr eksen konumu, b\u00fck\u00fcm pay\u0131n\u0131 belirler.<\/li>\n<\/ul>\n\n\n\n

      Kuvvet problemini her \u00e7\u00f6zd\u00fc\u011f\u00fcn\u00fczde, geometri problemine zaten dokunmu\u015f olursunuz.<\/p>\n\n\n\n

      Ve e\u011fer malzeme mukavemetinin bu d\u00f6ng\u00fc i\u00e7inde uslu duraca\u011f\u0131n\u0131 d\u00fc\u015f\u00fcn\u00fcyorsan\u0131z, yan\u0131l\u0131yorsunuz. Bir parti 201 paslanmaz \u00e7elik, ayn\u0131 kal\u0131nl\u0131ktaki 304'e g\u00f6re \u00e7ok daha farkl\u0131 bir kuvvet gerektirebilir. Daha y\u00fcksek akma dayan\u0131m\u0131, \u015fekillendirme \u00f6ncesinde sizi daha derine iter ve hava b\u00fckmede efektif yar\u0131\u00e7ap\u0131 hafif\u00e7e daralt\u0131r. Tonaj form\u00fcl\u00fc, \u00e7ekme mukavemeti ile do\u011frusal olarak \u00f6l\u00e7eklenir. Geometri tepkisi do\u011frusal de\u011fildir, \u00e7\u00fcnk\u00fc kal\u0131nl\u0131k boyunca gerilim da\u011f\u0131l\u0131m\u0131 akma davran\u0131\u015f\u0131yla birlikte de\u011fi\u015fir.<\/p>\n\n\n\n

      \u0130\u015fte bu y\u00fczden, ayn\u0131 kal\u0131nl\u0131kta damgalanm\u0131\u015f iki rulo, hesap makineniz tonaj\u0131n do\u011fru oldu\u011funa yemin etse bile farkl\u0131 arka dayama ayarlar\u0131 gerektirebilir.<\/p>\n\n\n\n

      Peki bu entegrasyon ne zaman \u201colsa iyi olur\u201d olmaktan \u00e7\u0131k\u0131p par\u00e7a m\u0131 yoksa bahane mi g\u00f6nderece\u011finize karar veren \u015feye d\u00f6n\u00fc\u015f\u00fcr?<\/p>\n\n\n\n

      B\u00fck\u00fcm indiriminin tonajdan daha \u00f6nemli hale geldi\u011fi tam o an<\/h3>\n\n\n\n

      Bu, hesaplanan tonaj\u0131n\u0131z makine kapasitesinin rahat\u00e7a alt\u0131na d\u00fc\u015ft\u00fc\u011f\u00fc anda ger\u00e7ekle\u015fir.<\/p>\n\n\n\n

      E\u011fer 150 tonluk abkant presiniz i\u015f i\u00e7in sadece 110 tona ihtiya\u00e7 duyuyorsa, kuvvet art\u0131k bir k\u0131s\u0131t de\u011fildir. Geometri k\u0131s\u0131tt\u0131r. O noktadan itibaren, iyi bir par\u00e7a ile hurda par\u00e7a aras\u0131ndaki fark, tonlarca bas\u0131n\u00e7la de\u011fil, binde birlik b\u00fck\u00fcm paylar\u0131yla \u00f6l\u00e7\u00fcl\u00fcr.<\/p>\n\n\n\n

      \u201cHesap makinesi 74 ton dedi.\u201d Bunu bir onur ni\u015fan\u0131 gibi s\u00f6yledi\u011fini duydum. G\u00fcvenli. Muhafazakar. Onayl\u0131.<\/p>\n\n\n\n

      Ancak i\u00e7 yar\u0131\u00e7ap, teknik resminizin varsayd\u0131\u011f\u0131 gibi de\u011fildir.<\/p>\n\n\n\n

      Makinenin g\u00fcvenli \u00e7al\u0131\u015fma s\u0131n\u0131rlar\u0131 i\u00e7inde oldu\u011funuzda, 5 tonluk bir marj daha i\u00e7in kafa yormak par\u00e7a hassasiyetine hi\u00e7bir katk\u0131 sa\u011flamaz. \u00d6nemli olan, b\u00fck\u00fcm pay\u0131n\u0131z\u0131n \u015fu anda makinede bulunan ger\u00e7ek kal\u0131p, z\u0131mba, malzeme ve y\u00f6ntemi yans\u0131t\u0131p yans\u0131tmad\u0131\u011f\u0131d\u0131r.<\/p>\n\n\n\n

      Hurda Kutusu Uyar\u0131s\u0131: Hata, ancak \u201c\u00fczerinde \u00e7al\u0131\u015f\u0131ld\u0131ktan\u201d sonra birle\u015ftirilebilen par\u00e7alar olarak ortaya \u00e7\u0131kar; yuvalar\u0131n e\u011felenmesi gerekir, c\u0131vata delikleri hizalamaya direnir, kaynak\u00e7\u0131lar ek yerlerini mengenelerle bir araya getirmek zorunda kal\u0131r. Tolerans birikimini su\u00e7lars\u0131n\u0131z. As\u0131l su\u00e7lu, d\u00fcz sac a\u00e7\u0131l\u0131m\u0131n\u0131z\u0131n d\u00fcn\u00fcn b\u00fck\u00fcm pay\u0131 ve bug\u00fcn\u00fcn tonaj odakl\u0131 tak\u0131mlar\u0131 ile hesaplanm\u0131\u015f olmas\u0131d\u0131r.<\/p>\n\n\n\n

      \u0130\u015fte disiplin budur: Makine ve tak\u0131m de\u011ferleri dahilinde kalacak tak\u0131mlar\u0131 se\u00e7in \u2014 do\u011fru birimlerle ve ger\u00e7ek \u00e7ekme mukavemeti de\u011ferleriyle \u2014 ard\u0131ndan d\u00fcz sac a\u00e7\u0131l\u0131m\u0131n\u0131 \u00fcretime g\u00f6ndermeden \u00f6nce o kurulumdan elde edilen b\u00fck\u00fcm pay\u0131n\u0131 hemen do\u011frulay\u0131n ve sabitleyin.<\/p>\n\n\n\n

      Kuvvet, presi hayatta tutar.<\/p>\n\n\n\n

      Entegre b\u00fck\u00fcm pay\u0131, par\u00e7alar\u0131 hayatta tutar.<\/p>\n\n\n\n

      Ve e\u011fer bunun kulaktan dolma bir bilgi olmaktan \u00e7\u0131k\u0131p tekrarlanabilir bir s\u00fcre\u00e7 haline gelmesini istiyorsan\u0131z, bu iki ad\u0131m\u0131 her seferinde birbirine ba\u011flayan bir i\u015f ak\u0131\u015f\u0131na ihtiyac\u0131m\u0131z var.<\/p>\n\n\n\n

      Pratik Bir \u0130\u015f Ak\u0131\u015f\u0131: H\u0131zl\u0131 Tahminden Do\u011frulanm\u0131\u015f Kuruluma<\/h2>\n\n\n\n

      Ge\u00e7en ay bir at\u00f6lye sahibi beni bir \u201cgizemli uzama\u201d sorunu i\u00e7in arad\u0131. 3\/16 in\u00e7 304 paslanmaz \u00e7elik braketler. Teknik resim do\u011fruydu. Lazer kesim tam yerindeydi. Abkant operat\u00f6r\u00fc, hesap makinesi 150 tonluk bir makinede 118 ton dedi\u011fi i\u00e7in kurulumun g\u00fcvenli oldu\u011funa yemin ediyordu. Her flan\u015f .060 in\u00e7 uzun \u00e7\u0131kt\u0131.<\/p>\n\n\n\n

      Tonaj uygundu.<\/p>\n\n\n\n

      Geometri de\u011fildi.<\/p>\n\n\n\n

      \u0130\u015fte her at\u00f6lyeye uygulatt\u0131\u011f\u0131m i\u015f ak\u0131\u015f\u0131. Teori de\u011fil. Presi hayatta tutan ve par\u00e7alar\u0131 do\u011fru k\u0131lan tekrarlanabilir bir s\u0131ra. \u0130\u015fe kuvvetle ba\u015flars\u0131n\u0131z ki demiri k\u0131rmayas\u0131n\u0131z. \u0130\u015fi \u00f6l\u00e7\u00fclm\u00fc\u015f b\u00fck\u00fcm pay\u0131 ile bitirirsiniz ki hurda g\u00f6ndermeyesiniz. \u0130kisinden birini atlarsan\u0131z, dersinizi dolar baz\u0131nda \u00f6deyerek \u00f6\u011frenirsiniz.<\/p>\n\n\n\n

      Hadi inceleyelim.<\/p>\n\n\n\n

      1. Ad\u0131m: G\u00fcvenli bir temel tonaj belirlemek i\u00e7in bir abkant pres hesap makinesi kullan\u0131n<\/h3>\n\n\n\n

      2 in\u00e7lik bir V-kal\u0131p \u00fczerinde 1\/4 in\u00e7lik A36 \u00e7eli\u011fi hayal edin. Standart tablo, fit ba\u015f\u0131na yakla\u015f\u0131k 19,7 ton g\u00f6sterir. 10 fitlik bir b\u00fck\u00fcmde bu 197 ton eder. 150 tonluk bir abkant i\u00e7in \u00e7ok fazla. Kal\u0131b\u0131 3 in\u00e7e a\u00e7t\u0131\u011f\u0131n\u0131zda, ayn\u0131 uzunlukta yakla\u015f\u0131k 139 tona d\u00fc\u015fersiniz. Art\u0131k kapasite dahilindesiniz.<\/p>\n\n\n\n

      Hesap makinesi bunun i\u00e7indir: g\u00fcvenlik s\u0131n\u0131rlar\u0131.<\/p>\n\n\n\n

      Ancak sadece kal\u0131nl\u0131\u011f\u0131 girip i\u015fi b\u0131rakamazs\u0131n\u0131z. Form\u00fcldeki kal\u0131nl\u0131k soyut bir \u201ct\u201d de\u011fildir. O sacdan mikrometre ile al\u0131nan ger\u00e7ek \u00f6l\u00e7\u00fcmd\u00fcr. \u00c7\u00fcnk\u00fc tonaj, kal\u0131nl\u0131\u011f\u0131n karesiyle orant\u0131l\u0131 olarak artar. E\u011fer \u201c.250 plakan\u0131z\u201d .265 \u00f6l\u00e7\u00fcl\u00fcyorsa, bu %6 daha fazla kuvvet demek de\u011fildir. 'ye daha yak\u0131nd\u0131r. \u0130\u015fte alt kal\u0131p omurgas\u0131n\u0131 bu \u015fekilde \u00e7atlat\u0131r ve tak\u0131m\u0131n kusurlu oldu\u011funa yemin edersiniz.<\/p>\n\n\n\n

      Ve uzunluk \u00f6nemlidir. Tablolar fit ba\u015f\u0131na tonaj\u0131 verir. E\u011fer 36 in\u00e7 b\u00fck\u00fcyorsan\u0131z, 3 ile \u00e7arp\u0131n. Operat\u00f6rlerin \u201cfit ba\u015f\u0131na 15 ton\u201d ifadesine bak\u0131p i\u015fin 15 ton gerektirdi\u011fini d\u00fc\u015f\u00fcnd\u00fcklerini g\u00f6rd\u00fcm. Sonra 4 fitlik bir flan\u015f basarlar ve 50 tonluk bir tak\u0131ma 60 ton y\u00fck bindirirler.<\/p>\n\n\n\n

      Hesap makinesi ilk filtrenizdir. \u015eunlar\u0131 do\u011frulay\u0131n:<\/p>\n\n\n\n

        \n
      • Ger\u00e7ek kal\u0131nl\u0131k<\/li>\n\n\n\n
      • Biliniyorsa ger\u00e7ek \u00e7ekme mukavemeti<\/li>\n\n\n\n
      • Ger\u00e7ek b\u00fck\u00fcm uzunlu\u011fu<\/li>\n\n\n\n
      • Ger\u00e7ek kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131<\/li>\n<\/ul>\n\n\n\n

        Art\u0131k makinenin kurulumu kald\u0131r\u0131p kald\u0131rmayaca\u011f\u0131n\u0131 biliyorsunuz.<\/p>\n\n\n\n

        Ancak kapasitenin alt\u0131na d\u00fc\u015fmek i\u00e7in o kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131n\u0131 de\u011fi\u015ftirdi\u011finiz anda, i\u00e7 yar\u0131\u00e7ap\u0131 zaten de\u011fi\u015ftirmi\u015f olursunuz. Ve bu, kabul etseniz de etmeseniz de d\u00fcz sac a\u00e7\u0131n\u0131m\u0131 matemati\u011fini de\u011fi\u015ftirdi\u011finiz anlam\u0131na gelir.<\/p>\n\n\n\n

        Peki, o kal\u0131p de\u011fi\u015fimi geometrinize tam olarak ne yapt\u0131?<\/p>\n\n\n\n

        Ad\u0131m 2: Kal\u0131p geni\u015fli\u011fini hedef i\u00e7 yar\u0131\u00e7ap\u0131n\u0131zla kar\u015f\u0131la\u015ft\u0131r\u0131n<\/h3>\n\n\n\n

        Hava b\u00fck\u00fcm\u00fcnde i\u00e7 yar\u0131\u00e7ap, z\u0131mba ucunun belirtti\u011fi de\u011fer de\u011fildir. V-kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131yla kabaca orant\u0131l\u0131d\u0131r. Yumu\u015fak \u00e7elik genellikle kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131n\u0131n 's\u0131 civar\u0131nda sonu\u00e7 verir. Paslanmaz \u00e7elik daha dar, al\u00fcminyum ise daha geni\u015f sonu\u00e7lar verir. Bu bir \u015fehir efsanesi de\u011fil; akma dayan\u0131m\u0131 ve kal\u0131p geometrisine yan\u0131t veren kal\u0131nl\u0131k boyunca gerinim da\u011f\u0131l\u0131m\u0131d\u0131r.<\/p>\n\n\n\n

        Tonajdan tasarruf etmek i\u00e7in 1\/4 in\u00e7lik A36 sac i\u015fini 2 in\u00e7lik kal\u0131ptan 3 in\u00e7lik kal\u0131ba ge\u00e7irdi\u011finizde, i\u00e7 yar\u0131\u00e7ap\u0131n\u0131z da onunla birlikte b\u00fcy\u00fcr. E\u011fer teknik resminiz .250 i\u00e7 yar\u0131\u00e7ap talep ediyorsa ve yeni kal\u0131b\u0131n\u0131z .480'e yak\u0131n bir de\u011fer \u00fcretiyorsa, b\u00fck\u00fcm pay\u0131n\u0131z de\u011fi\u015fmi\u015f demektir.<\/p>\n\n\n\n

        Sihirle de\u011fil, mekanikle.<\/p>\n\n\n\n

        Daha b\u00fcy\u00fck kal\u0131p:<\/p>\n\n\n\n

          \n
        • Daha b\u00fcy\u00fck i\u00e7 yar\u0131\u00e7ap<\/li>\n\n\n\n
        • Daha d\u00fc\u015f\u00fck d\u0131\u015f lif gerinimi<\/li>\n\n\n\n
        • N\u00f6tr eksen kayar<\/li>\n\n\n\n
        • Derece ba\u015f\u0131na b\u00fck\u00fcm pay\u0131 azal\u0131r<\/li>\n<\/ul>\n\n\n\n

          Bu y\u00fczden o \u201cg\u00fcvenli\u201d tonaj de\u011ferini onaylamadan \u00f6nce \u015funu kontrol edin: Bu kal\u0131p, teknik resimle uyumlu bir i\u00e7 yar\u0131\u00e7ap \u00fcretiyor mu?<\/p>\n\n\n\n

          E\u011fer teknik resim dar toleransl\u0131 ve estetik a\u00e7\u0131dan \u00f6nemliyse, s\u0131rf kuvvetten tasarruf etmek i\u00e7in kal\u0131b\u0131 geni\u015fletme l\u00fcks\u00fcn\u00fcz olmayabilir. Ya da d\u00fcz sac a\u00e7\u0131n\u0131m\u0131n\u0131 yeni yar\u0131\u00e7apa g\u00f6re kas\u0131tl\u0131 olarak yeniden tasarlars\u0131n\u0131z. Yapmaman\u0131z gereken \u015fey, yar\u0131\u00e7ap\u0131n ayn\u0131 kald\u0131\u011f\u0131n\u0131 varsaymakt\u0131r.<\/p>\n\n\n\n

          Ve i\u015fte \u00e7o\u011fu hesaplay\u0131c\u0131n\u0131n sizi uyarmayaca\u011f\u0131 tuzak: Tak\u0131m de\u011ferleri birime duyarl\u0131d\u0131r. \u00dczerinde fit ba\u015f\u0131na 81 ton (k\u0131sa ton) yazan bir tak\u0131m, metre ba\u015f\u0131na 81 metrik ton ile ayn\u0131 de\u011fildir. Keskin z\u0131mbalar kuvveti d\u0131\u015fa do\u011fru yo\u011funla\u015ft\u0131r\u0131r ve g\u00fcvenli s\u0131n\u0131rlar\u0131 azalt\u0131r. Birimleri ve geometriyi uzla\u015ft\u0131rmazsan\u0131z, \u201cg\u00fcvenli\u201d kurulumunuz yine de tak\u0131m omuzlar\u0131n\u0131 a\u015f\u0131r\u0131 zorlayabilir.<\/p>\n\n\n\n

          \u00d6nce kuvvet. Sonra yar\u0131\u00e7ap ger\u00e7eklik kontrol\u00fc.<\/p>\n\n\n\n

          Art\u0131k kal\u0131b\u0131 hem kapasiteye hem de yar\u0131\u00e7apa g\u00f6re sabitledi\u011finize g\u00f6re, as\u0131l kazan\u00e7 karar\u0131 \u00f6n\u00fcn\u00fczde duruyor.<\/p>\n\n\n\n

          Hangi d\u00fcz uzunlu\u011fu keseceksiniz?<\/p>\n\n\n\n

          Ad\u0131m 3: \u00dcretim par\u00e7alar\u0131n\u0131 kesmeden \u00f6nce b\u00fck\u00fcm pay\u0131n\u0131 hesaplay\u0131n<\/h3>\n\n\n\n

          At\u00f6lyelerin ya profesyonel gibi davrand\u0131\u011f\u0131 ya da kumar oynad\u0131\u011f\u0131 yer buras\u0131d\u0131r.<\/p>\n\n\n\n

          Kal\u0131p geni\u015fli\u011fi sabitlendi\u011finde, malzeme ve a\u00e7\u0131kl\u0131\u011fa ba\u011fl\u0131 olarak i\u00e7 yar\u0131\u00e7ap\u0131 tahmin edersiniz. Bu yar\u0131\u00e7aptan, kal\u0131nl\u0131ktan ve b\u00fck\u00fcm a\u00e7\u0131s\u0131ndan b\u00fck\u00fcm pay\u0131n\u0131 hesaplars\u0131n\u0131z. B\u00fck\u00fcm pay\u0131ndan, toplam flan\u015f uzunluklar\u0131ndan \u00e7\u0131kararak a\u00e7\u0131n\u0131m\u0131 elde edece\u011finiz b\u00fck\u00fcm d\u00fc\u015f\u00fc\u015f\u00fcn\u00fc t\u00fcretirsiniz.<\/p>\n\n\n\n

          Bunlar ekrandaki de\u011fi\u015fkenler de\u011fildir. Bunlar \u015funlar\u0131n fiziksel sonu\u00e7lar\u0131d\u0131r:<\/p>\n\n\n\n

            \n
          • Z\u0131mban\u0131n ne kadar derine n\u00fcfuz etti\u011fi<\/li>\n\n\n\n
          • N\u00f6tr eksenin nereye kayd\u0131\u011f\u0131<\/li>\n\n\n\n
          • Malzemenin geri esnemeden \u00f6nce ne kadar akma g\u00f6sterdi\u011fi<\/li>\n<\/ul>\n\n\n\n

            Kal\u0131p de\u011fi\u015fiminiz i\u00e7 yar\u0131\u00e7ap\u0131 .250'den .480'e \u00e7\u0131kard\u0131ysa, 90 derece ba\u015f\u0131na b\u00fck\u00fcm pay\u0131n\u0131z kal\u0131nl\u0131\u011fa ve malzemeye ba\u011fl\u0131 olarak yakla\u015f\u0131k .050 ila .080 oran\u0131nda k\u00fc\u00e7\u00fclebilir. \u0130ki b\u00fck\u00fcml\u00fc bir par\u00e7ada, bu a\u00e7\u0131n\u0131mda .100 ila .160 fark demektir.<\/p>\n\n\n\n

            Paslanmaz \u00e7elikte bu, yerine tam oturan bir par\u00e7a ile kaynak fikst\u00fcr\u00fcyle \u00e7eki\u00e7 kullanarak u\u011fra\u015fmak aras\u0131ndaki farkt\u0131r.<\/p>\n\n\n\n

            Ve bunu \u00fcretim par\u00e7alar\u0131n\u0131 kesmeden \u00f6nce yapars\u0131n\u0131z. \u0130lk palet kesildikten sonra de\u011fil.<\/p>\n\n\n\n

            Ge\u00e7en bahar bir gen\u00e7, 10 fitlik 11 gauge paslanmaz \u00e7elik \u015feridi \u2014$312 de\u011ferinde malzeme\u2014 tamamen \u201cg\u00fcvenli\u201d bir kurulumda i\u015fledi. Tonaj uygundu. Makine sorunsuz \u00e7al\u0131\u015f\u0131yordu. Her par\u00e7a iki flan\u015f boyunca .090 uzundu \u00e7\u00fcnk\u00fc a\u00e7\u0131n\u0131m genel bir K-fakt\u00f6r\u00fcne g\u00f6re programlanm\u0131\u015ft\u0131. \u015eeridi hurdaya \u00e7\u0131kard\u0131lar, geri esnemeyi su\u00e7lad\u0131lar ve arka dayamay\u0131 ayarlad\u0131lar.<\/p>\n\n\n\n

            Buna arka dayama neden olmad\u0131.<\/p>\n\n\n\n

            A\u00e7\u0131n\u0131m neden oldu.<\/p>\n\n\n\n

            Hurda Kutusu Uyar\u0131s\u0131: Bu hata, partideki her par\u00e7ada tutarl\u0131 bir boyutsal sapma olarak ortaya \u00e7\u0131kar \u2014 hepsi ayn\u0131 miktarda uzun veya k\u0131sad\u0131r. Operat\u00f6rler telafi etmek i\u00e7in arka dayamay\u0131 \u201cy\u00fcr\u00fctmeye\u201d ba\u015flar. Art\u0131k bir matematik hatas\u0131n\u0131 kurulum ayar\u0131n\u0131n i\u00e7ine g\u00f6md\u00fcn\u00fcz ve bir sonraki i\u015f bu kaosu devral\u0131r.<\/p>\n\n\n\n

            D\u00fc\u015f\u00fc\u015f\u00fc hesaplad\u0131n\u0131z. Bir adet bo\u015f par\u00e7a kestiniz.<\/p>\n\n\n\n

            Matemati\u011fe mi g\u00fcveniyorsunuz, yoksa metale mi kan\u0131tlat\u0131yorsunuz?<\/p>\n\n\n\n

            Ad\u0131m 4: Teorik say\u0131lar\u0131n\u0131z\u0131 kalibre etmek i\u00e7in kontroll\u00fc bir test b\u00fck\u00fcm\u00fc yap\u0131n<\/h3>\n\n\n\n

            Bir adet bo\u015f par\u00e7a. Tam \u00fcretim kal\u0131b\u0131. Tam b\u00fck\u00fcm uzunlu\u011fu. Kestirme yol yok.<\/p>\n\n\n\n

            B\u00fck\u00fcn.<\/p>\n\n\n\n

            \u00d6l\u00e7\u00fcn:<\/p>\n\n\n\n

              \n
            • Ger\u00e7ek i\u00e7 yar\u0131\u00e7ap (yar\u0131\u00e7ap mastar\u0131 veya optik kar\u015f\u0131la\u015ft\u0131r\u0131c\u0131)<\/li>\n\n\n\n
            • Ger\u00e7ek flan\u015f uzunluklar\u0131<\/li>\n\n\n\n
            • Geri esneme sonras\u0131 ger\u00e7ek a\u00e7\u0131<\/li>\n<\/ul>\n\n\n\n

              \u015eimdi \u00f6l\u00e7\u00fclen flan\u015f toplam\u0131n\u0131, d\u00fcz par\u00e7a eksi teorik b\u00fck\u00fcm pay\u0131 ile kar\u015f\u0131la\u015ft\u0131r\u0131n. E\u011fer 0,015 sapma varsa, pay\u0131 ayarlay\u0131n. E\u011fer 0,060 sapma varsa, yar\u0131\u00e7ap varsay\u0131m\u0131n\u0131zda bir hata vard\u0131r ya da malzeme partiniz kitaptakinden farkl\u0131 davran\u0131yordur.<\/p>\n\n\n\n

              \u0130\u015fte ger\u00e7ek K-fakt\u00f6r\u00fcn\u00fc yaz\u0131l\u0131m varsay\u0131mlar\u0131ndan de\u011fil, ger\u00e7eklikten yola \u00e7\u0131karak burada \u00e7\u00f6zersiniz. Par\u00e7an\u0131n size n\u00f6tr eksenin nereye gitti\u011fini s\u00f6ylemesine izin verin.<\/p>\n\n\n\n

              On dakika s\u00fcrer.<\/p>\n\n\n\n

              Saatlerce zaman kazand\u0131r\u0131r.<\/p>\n\n\n\n

              Rakamlar uyumlu oldu\u011funda \u2014 yani hesaplanan b\u00fck\u00fcm pay\u0131 \u00f6l\u00e7\u00fclen sonu\u00e7la e\u015fle\u015fti\u011finde \u2014 d\u00fcz par\u00e7a modelini kilitleyin ve \u00fcretime ge\u00e7in. Art\u0131k tonaj\u0131n\u0131z g\u00fcvenli, yar\u0131\u00e7ap\u0131n\u0131z bilin\u00e7li ve geometriniz y\u00fck alt\u0131nda kan\u0131tlanm\u0131\u015f durumdad\u0131r.<\/p>\n\n\n\n

              Bu do\u011frulanm\u0131\u015f bir kurulumdur.<\/p>\n\n\n\n

              Ancak bu i\u015f ak\u0131\u015f\u0131yla bile malzeme de\u011fi\u015fkenli\u011fi, lif y\u00f6n\u00fc ve partiler aras\u0131 \u00e7ekme dayan\u0131m\u0131 de\u011fi\u015fimleri sonu\u00e7lar\u0131 hala etkileyebilir. \u0130\u015fte herhangi bir hesap makinesi tabanl\u0131 modelin s\u0131n\u0131rlar\u0131n\u0131n kendini g\u00f6stermeye ba\u015flad\u0131\u011f\u0131 nokta buras\u0131d\u0131r.<\/p>\n\n\n\n

              Ad\u0131m<\/th>Ba\u015fl\u0131k<\/th>Ana Eylemler<\/th>Kritik Hesaplamalar \/ Kontroller<\/th>G\u00f6z Ard\u0131 Edilirse Olu\u015facak Riskler<\/th>Temel Sonu\u00e7<\/th><\/tr><\/thead>
              Ad\u0131m 1<\/td>G\u00fcvenli Temel Tonaj\u0131 Belirleyin<\/td>Kurulumdan \u00f6nce abkant pres hesap makinesini kullan\u0131n<\/td>Ger\u00e7ek kal\u0131nl\u0131\u011f\u0131 (mikrometre okumas\u0131), \u00e7ekme dayan\u0131m\u0131n\u0131 (biliniyorsa), b\u00fck\u00fcm uzunlu\u011funu ve kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131n\u0131 do\u011frulay\u0131n; fit ba\u015f\u0131na tonaj\u0131 ger\u00e7ek b\u00fck\u00fcm uzunlu\u011fu ile \u00e7arp\u0131n; tonaj\u0131n kal\u0131nl\u0131\u011f\u0131n karesiyle (kal\u0131nl\u0131k\u00b2) \u00f6l\u00e7eklendi\u011fini unutmay\u0131n<\/td>Makineyi veya tak\u0131mlar\u0131 a\u015f\u0131r\u0131 y\u00fckleme; \u00e7atlak kal\u0131p omuzlar\u0131; birim kar\u0131\u015f\u0131kl\u0131\u011f\u0131 (k\u0131sa ton ile metrik ton); tak\u0131m kapasitesini a\u015fma<\/td>Makine ve tak\u0131mlar\u0131n g\u00fcvenli kapasite s\u0131n\u0131rlar\u0131 i\u00e7inde \u00e7al\u0131\u015fmas\u0131<\/td><\/tr>
              Ad\u0131m 2<\/td>Kal\u0131p Geni\u015fli\u011fi ile Hedef \u0130\u00e7 Yar\u0131\u00e7ap\u0131 \u00c7apraz Kontrol Edin<\/td>Kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131n\u0131n gerekli i\u00e7 yar\u0131\u00e7ap\u0131 destekledi\u011fini do\u011frulay\u0131n<\/td>\u0130\u00e7 yar\u0131\u00e7ap \u2248 V-kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131 ile orant\u0131l\u0131d\u0131r (\u00f6rne\u011fin, yumu\u015fak \u00e7elik i\u00e7in ~); daha b\u00fcy\u00fck kal\u0131p \u2192 daha b\u00fcy\u00fck yar\u0131\u00e7ap \u2192 n\u00f6tr eksen kaymas\u0131 \u2192 derece ba\u015f\u0131na azalt\u0131lm\u0131\u015f b\u00fck\u00fcm pay\u0131<\/td>Yanl\u0131\u015f b\u00fck\u00fcm pay\u0131; boyutsal hatalar; kozmetik veya uyum sorunlar\u0131; geometri uyumsuzlu\u011fu nedeniyle a\u015f\u0131r\u0131 zorlanan tak\u0131m<\/td>Kal\u0131p se\u00e7imi hem kapasite s\u0131n\u0131rlar\u0131 hem de teknik resim gereksinimleri ile uyumludur<\/td><\/tr>
              Ad\u0131m 3<\/td>Kesimden \u00d6nce B\u00fck\u00fcm \u00c7\u0131kar\u0131m\u0131n\u0131 Hesaplay\u0131n<\/td>Ger\u00e7ek geometriden d\u00fcz uzunlu\u011fu belirleyin<\/td>\u0130\u00e7 yar\u0131\u00e7ap\u0131 kal\u0131p + malzemeden tahmin edin; yar\u0131\u00e7ap, kal\u0131nl\u0131k ve a\u00e7\u0131dan b\u00fck\u00fcm pay\u0131n\u0131 hesaplay\u0131n; b\u00fck\u00fcm \u00e7\u0131kar\u0131m\u0131n\u0131 t\u00fcretin; malzeme davran\u0131\u015f\u0131 ve geri esneme i\u00e7in ayarlama yap\u0131n<\/td>Tutarl\u0131 boyutsal sapma (t\u00fcm par\u00e7alar uzun\/k\u0131sa); hurda malzeme; matematik hatalar\u0131n\u0131 arka dayama ayarlar\u0131yla gizleme<\/td>\u00dcretim kesiminden \u00f6nce do\u011fru d\u00fcz par\u00e7a a\u00e7\u0131n\u0131m\u0131<\/td><\/tr>
              Ad\u0131m 4<\/td>Kontroll\u00fc Test B\u00fck\u00fcm\u00fc Yap\u0131n<\/td>Hesaplamalar\u0131 bir \u00fcretim tasla\u011f\u0131 ile do\u011frulay\u0131n<\/td>Ger\u00e7ek i\u00e7 yar\u0131\u00e7ap\u0131, flan\u015f uzunluklar\u0131n\u0131 ve nihai a\u00e7\u0131y\u0131 \u00f6l\u00e7\u00fcn; \u00f6l\u00e7\u00fclen sonu\u00e7lar\u0131 teorik b\u00fck\u00fcm \u00e7\u0131kar\u0131m\u0131 ile kar\u015f\u0131la\u015ft\u0131r\u0131n; gerekirse K-fakt\u00f6r\u00fcn\u00fc ayarlay\u0131n<\/td>Parti genelinde hatalar; yanl\u0131\u015f K-fakt\u00f6r\u00fc varsay\u0131mlar\u0131; \u00fcretim firesi<\/td>Do\u011frulanm\u0131\u015f kurulum: g\u00fcvenli tonaj, do\u011fru yar\u0131\u00e7ap, y\u00fck alt\u0131nda kan\u0131tlanm\u0131\u015f geometri<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

              S\u0131n\u0131r \u00c7izgisi: Hesaplay\u0131c\u0131n\u0131n Durdu\u011fu ve Ger\u00e7ekli\u011fin Ba\u015flad\u0131\u011f\u0131 Yer<\/h2>\n\n\n\n

              Test b\u00fck\u00fcm\u00fcn\u00fc yapt\u0131n\u0131z. \u00d6l\u00e7t\u00fcn\u00fcz. Flan\u015f uzunluklar\u0131 tam istedi\u011finiz gibi olana kadar b\u00fck\u00fcm \u00e7\u0131kar\u0131m\u0131n\u0131 ayarlad\u0131n\u0131z.<\/p>\n\n\n\n

              \u015eimdi farkl\u0131 bir d\u00f6k\u00fcm numaras\u0131ndan yeni bir \u00e7elik paleti geldi.<\/p>\n\n\n\n

              Her \u015feyi yeniden mi yapacaks\u0131n\u0131z, yoksa d\u00fcn\u00fcn rakamlar\u0131na m\u0131 g\u00fcveneceksiniz?<\/p>\n\n\n\n

              \u0130\u015fte akl\u0131n\u0131za kaz\u0131man\u0131z gereken o \u00e7izgi: hesaplay\u0131c\u0131 ve ilk kalibrasyonunuz, o belirli sac\u0131n o belirli y\u00fck alt\u0131nda ne yapt\u0131\u011f\u0131n\u0131 kan\u0131tlar. Bir sonraki partinin ne yapaca\u011f\u0131n\u0131 kan\u0131tlamazlar. \u00c7elik bir PDF de\u011fildir. S\u0131cak d\u00f6k\u00fclen ve sizin kontrol etmedi\u011finiz bir h\u0131zda so\u011futulan kimyasal bir re\u00e7etedir.<\/p>\n\n\n\n

              Hesaplay\u0131c\u0131 korkuluktur. Kalibrasyon direksiyondur. Ancak yol hala virajl\u0131d\u0131r.<\/p>\n\n\n\n

              Ve virajlar, hesaplay\u0131c\u0131n\u0131z\u0131n hangi rakam\u0131 yazd\u0131rd\u0131\u011f\u0131n\u0131 umursamaz.<\/p>\n\n\n\n

              Geri esneme: Hesap makinenizin g\u00f6remedi\u011fi g\u00f6r\u00fcnmez d\u00fczeltme<\/h3>\n\n\n\n

              Geri esneme sadece elastik toparlanmad\u0131r. Z\u0131mbay\u0131 a\u015fa\u011f\u0131 do\u011fru bast\u0131r\u0131rs\u0131n\u0131z, malzeme akma dayan\u0131m\u0131n\u0131n \u00f6tesine ge\u00e7er, ard\u0131ndan bas\u0131nc\u0131 serbest b\u0131rakt\u0131\u011f\u0131n\u0131zda gerilimin elastik k\u0131sm\u0131 geri yaylan\u0131r ve a\u00e7\u0131y\u0131 geni\u015fletir.<\/p>\n\n\n\n

              Teoride basit.<\/p>\n\n\n\n

              Ancak ne kadar geri yaylanaca\u011f\u0131, t\u0131klad\u0131\u011f\u0131n\u0131z \u201cyumu\u015fak \u00e7elik\u201d d\u00fc\u011fmesine de\u011fil, o sacdaki ger\u00e7ek akma dayan\u0131m\u0131na ba\u011fl\u0131d\u0131r. Bir parti 42 ksi'de, di\u011feri 50 ksi'de ak\u0131yorsa, daha g\u00fc\u00e7l\u00fc olan parti daha fazla geri esner. Ayn\u0131 kal\u0131p. Ayn\u0131 z\u0131mba. Ayn\u0131 programlanm\u0131\u015f derinlik. Farkl\u0131 a\u00e7\u0131.<\/p>\n\n\n\n

              Bu, farkl\u0131 bir efektif i\u00e7 yar\u0131\u00e7ap anlam\u0131na gelir. Ve bu, kurulumunuza hi\u00e7 dokunmasan\u0131z bile b\u00fck\u00fcm pay\u0131n\u0131z\u0131n de\u011fi\u015fti\u011fi anlam\u0131na gelir.<\/p>\n\n\n\n

              Ancak i\u00e7 yar\u0131\u00e7ap, teknik resminizin varsayd\u0131\u011f\u0131 gibi de\u011fildir.<\/p>\n\n\n\n

              Bunun fiziksel olarak ne anlama geldi\u011fini hayal edin. Ko\u00e7un belirli bir derinlikte durmas\u0131n\u0131 emrediyorsunuz; ger\u00e7ek d\u00fcnyadaki de\u011fi\u015fkeniniz budur. Derinlik, V-kal\u0131b\u0131na giri\u015fe e\u015fittir. Giri\u015f, malzemenin ne kadar s\u0131k\u0131 sar\u0131laca\u011f\u0131n\u0131 kontrol eder. Malzeme daha fazla diren\u00e7 g\u00f6sterirse, b\u0131rakt\u0131\u011f\u0131n\u0131zda daha fazla gev\u015fer. N\u00f6tr eksen \u2014 yani esnemeyen veya s\u0131k\u0131\u015fmayan o hayali katman \u2014 kal\u0131nl\u0131k boyunca farkl\u0131 \u015fekilde g\u00f6\u00e7 eder.<\/p>\n\n\n\n

              Siz matemati\u011fi de\u011fi\u015ftirmediniz.<\/p>\n\n\n\n

              Metal de\u011fi\u015ftirdi.<\/p>\n\n\n\n

              Hurda Kutusu Uyar\u0131s\u0131:<\/strong> Geri esneme kaymas\u0131, ayn\u0131 programla bir hafta 89 derece, ertesi hafta 87,5 derece \u00f6l\u00e7\u00fclen a\u00e7\u0131lar olarak ortaya \u00e7\u0131kar. Operat\u00f6rler a\u00e7\u0131y\u0131 yakalamak i\u00e7in ko\u00e7 derinli\u011fini burada 0,010, orada 0,015 art\u0131rmaya ba\u015flar. Art\u0131k b\u00fck\u00fcm d\u00fc\u015f\u00fc\u015f\u00fcn\u00fcz hatal\u0131 ve flan\u015f uzunluklar\u0131 4 flan\u015fl\u0131 bir kutuda 0,030 oran\u0131nda uzay\u0131p k\u0131sal\u0131yor. D\u00fcnk\u00fc fikst\u00fcre uyuyordu. Bug\u00fcn ise sallan\u0131yor.<\/p>\n\n\n\n

              Peki de\u011fi\u015fkenlik sadece dayan\u0131m de\u011fil, yap\u0131 oldu\u011funda ne olur?<\/p>\n\n\n\n

              Malzeme tane y\u00f6n\u00fc ve tutars\u0131z \u00e7elik partileri modeli ge\u00e7ersiz k\u0131ld\u0131\u011f\u0131nda<\/h3>\n\n\n\n

              Bir sac\u0131 haddehanede yuvarlad\u0131\u011f\u0131n\u0131zda, tane yap\u0131s\u0131n\u0131 \u015fekerleme \u00e7eker gibi uzat\u0131rs\u0131n\u0131z. O taneye paralel b\u00fckerseniz, daha sert davran\u0131r. \u00c7apraz b\u00fckerseniz, daha kolay akar.<\/p>\n\n\n\n

              Ayn\u0131 kal\u0131nl\u0131k. Ayn\u0131 ala\u015f\u0131m. Farkl\u0131 tepki.<\/p>\n\n\n\n

              Bir hesap makinesi t\u00fcm bunlar\u0131 tek bir girdide toplar: \u201cMalzeme = A36\u201d veya \u201cMalzeme = 304 paslanmaz.\u201d Bu bir kategoridir. Ger\u00e7eklik ise partiden partiye, bobinden bobine, bazen de levhadan levhaya de\u011fi\u015fir.<\/p>\n\n\n\n

              Ayn\u0131 tedarik\u00e7iden, ayn\u0131 spesifikasyonda iki parti 10-gauge s\u0131cak haddelenmi\u015f \u00e7elik g\u00f6rd\u00fcm; o kadar farkl\u0131yd\u0131lar ki, biri ayn\u0131 1,5 in\u00e7lik V-kal\u0131b\u0131nda 90 dereceyi yakalamak i\u00e7in 0,020 daha fazla ko\u00e7 derinli\u011fine ihtiya\u00e7 duyuyordu. O 0,020 sadece a\u00e7\u0131y\u0131 d\u00fczeltmez. Sarmay\u0131 de\u011fi\u015ftirir. \u0130\u00e7 yar\u0131\u00e7ap\u0131 hafif\u00e7e kayd\u0131r\u0131r. B\u00fck\u00fcm pay\u0131n\u0131 b\u00fck\u00fcm ba\u015f\u0131na birka\u00e7 binde bir oran\u0131nda de\u011fi\u015ftirir.<\/p>\n\n\n\n

              Tek bir brakette kimin umurunda.<\/p>\n\n\n\n

              12 b\u00fck\u00fcml\u00fc bir muhafazada, hatay\u0131 on iki kez \u00fcst \u00fcste bindirdiniz.<\/p>\n\n\n\n

              Ge\u00e7en bahar bir gen\u00e7, 11-gauge paslanmaz \u00e7elikten 10 fitlik bir \u015feridi \u2014 312 dolar de\u011ferinde malzeme \u2014 m\u00fckemmel derecede \u201cg\u00fcvenli\u201d bir kurulumdan ge\u00e7irdi. Tonaj iyiydi. Makine memnundu. Ancak yeni partinin akma dayan\u0131m\u0131 daha y\u00fcksekti, geri esneme a\u00e7\u0131lar\u0131 biraz daha fazla a\u00e7t\u0131 ve her bir geri d\u00f6n\u00fc\u015f flan\u015f\u0131, son montaj 0,080 geni\u015fli\u011finde olacak kadar b\u00fcy\u00fcd\u00fc. Onu bir kaynak aparat\u0131na zorla yerle\u015ftirdiler. So\u011fuduktan sonra muz gibi e\u011fildi.<\/p>\n\n\n\n

              Kaynak\u00e7\u0131y\u0131 su\u00e7lad\u0131lar.<\/p>\n\n\n\n

              Tane yap\u0131s\u0131n\u0131n onlar\u0131n su\u00e7lamas\u0131 umurunda bile de\u011fildi.<\/p>\n\n\n\n

              At\u00f6lye \u00e7evirisi \u015f\u00f6yledir: damar y\u00f6n\u00fc, sac kenar\u0131nda g\u00f6rebilece\u011finiz fiziksel bir y\u00f6nelimdir. Parti varyasyonu ise, ayn\u0131 g\u00f6r\u00fcnen \u015feyin i\u00e7inde gizlenen farkl\u0131 bir gerilme-\u015fekil de\u011fi\u015ftirme e\u011frisidir. \u00d6l\u00e7\u00fcp ayarlamad\u0131\u011f\u0131n\u0131z s\u00fcrece bu de\u011fi\u015fkenlerin hi\u00e7biri hesap makinenizin i\u00e7inde mevcut de\u011fildir.<\/p>\n\n\n\n

              Peki ya malzeme sapma g\u00f6sterebiliyorsa, b\u00fck\u00fcm\u00fc yapan tak\u0131mlar ne olacak?<\/p>\n\n\n\n

              Tak\u0131m a\u015f\u0131nmas\u0131 ve makine bombeli\u011fi: Hi\u00e7bir form\u00fcl\u00fcn bilmedi\u011fi de\u011fi\u015fkenler<\/h3>\n\n\n\n

              V-kal\u0131p omuzlar\u0131n\u0131z \u00f6l\u00fcms\u00fcz de\u011fildir. Her b\u00fck\u00fcm, iki temas hatt\u0131 boyunca yo\u011funla\u015fan bir bas\u0131n\u00e7t\u0131r. Zamanla bu omuzlar d\u00f6v\u00fcl\u00fcr; yani efektif a\u00e7\u0131kl\u0131\u011f\u0131 hafif\u00e7e geni\u015fleten mikroskobik bir deformasyona u\u011frar.<\/p>\n\n\n\n

              Daha geni\u015f a\u00e7\u0131kl\u0131k, daha b\u00fcy\u00fck i\u00e7 yar\u0131\u00e7ap anlam\u0131na gelir.<\/p>\n\n\n\n

              Daha b\u00fcy\u00fck yar\u0131\u00e7ap, derece ba\u015f\u0131na daha az b\u00fck\u00fcm pay\u0131 anlam\u0131na gelir.<\/p>\n\n\n\n

              Bunu ilk g\u00fcn g\u00f6remezsiniz. Par\u00e7alar flan\u015f boyunca .015 k\u0131sa gelmeye ba\u015flad\u0131\u011f\u0131nda ve kimse program\u0131 de\u011fi\u015ftirmedi\u011finde g\u00f6r\u00fcrs\u00fcn\u00fcz.<\/p>\n\n\n\n

              \u015eimdi buna bombeli\u011fi ekleyin; yani y\u00fck alt\u0131ndaki esnemeyi dengelemek i\u00e7in tablaya verilen kas\u0131tl\u0131 yukar\u0131 do\u011fru kavis. E\u011fer bombelik yanl\u0131\u015f ayarlanm\u0131\u015fsa, uzun bir b\u00fck\u00fcm\u00fcn merkezi, u\u00e7lar\u0131ndan farkl\u0131 bir penetrasyon g\u00f6r\u00fcr. Bu teori de\u011fildir. Bu, ram derinli\u011finin uzunluk boyunca fiziksel olarak de\u011fi\u015fmesidir.<\/p>\n\n\n\n

              Farkl\u0131 penetrasyon, farkl\u0131 a\u00e7\u0131ya e\u015fittir.<\/p>\n\n\n\n

              Ayn\u0131 par\u00e7a \u00fczerinde farkl\u0131 a\u00e7\u0131; b\u00fck\u00fclmeye, dalgalanmaya (oil-canning) ve montaj sorunlar\u0131na yol a\u00e7ar.<\/p>\n\n\n\n

              Hi\u00e7bir hesap makinesi kal\u0131b\u0131n\u0131z\u0131n ne kadar a\u015f\u0131nd\u0131\u011f\u0131n\u0131 bilmez. Hi\u00e7bir form\u00fcl, tablan\u0131n o g\u00fcnk\u00fc tonaj\/ayak de\u011feri i\u00e7in m\u00fckemmel \u015fekilde bombelenip bombelenmedi\u011fini bilmez. \u201cHesap makinesi 74 ton dedi\u201d ifadesi, size bu kuvvetin 8 fit boyunca e\u015fit mi da\u011f\u0131t\u0131ld\u0131\u011f\u0131 yoksa esneme nedeniyle merkezde biraz daha m\u0131 yo\u011funla\u015ft\u0131\u011f\u0131 hakk\u0131nda hi\u00e7bir \u015fey s\u00f6ylemez.<\/p>\n\n\n\n

              \u0130\u015fte bu y\u00fczden buras\u0131 s\u0131n\u0131r \u00e7izgisidir.<\/p>\n\n\n\n

              Bir tarafta: form\u00fcller, kategoriler, tahminler. Di\u011fer tarafta: \u00f6l\u00e7\u00fclen a\u00e7\u0131, \u00f6l\u00e7\u00fclen yar\u0131\u00e7ap, \u00f6l\u00e7\u00fclen flan\u015f ve malzeme, tak\u0131m veya uzunluk de\u011fi\u015fti\u011finde bunlar\u0131 tekrar kontrol etme al\u0131\u015fkanl\u0131\u011f\u0131.<\/p>\n\n\n\n

              De\u011fi\u015fkenli\u011fi daha iyi yaz\u0131l\u0131mlara g\u00fcvenerek kontrol edemezsiniz.<\/p>\n\n\n\n

              Bunu, metali size asla iki kez \u015fa\u015f\u0131rtmayacak kadar s\u0131k\u0131 bir geri bildirim d\u00f6ng\u00fcs\u00fc kurarak kontrol edersiniz.<\/p>\n\n\n\n

              De\u011fi\u015fim: \u201cHesap Makinesi Kullan\u0131c\u0131s\u0131\u201dndan \u201cS\u00fcre\u00e7 Sahibi\u201dne\u201d<\/h2>\n\n\n\n

              Kurulumu do\u011frulad\u0131n\u0131z. Test b\u00fck\u00fcm\u00fc iyi. A\u00e7\u0131 90'\u0131 tutturuyor. Flan\u015f tam \u00f6l\u00e7\u00fcs\u00fcnde.<\/p>\n\n\n\n

              Sonra bir sonraki malzeme partisi gelir.<\/p>\n\n\n\n

              Etiketteki \u00f6zellik ayn\u0131. Mikrometredeki kal\u0131nl\u0131k ayn\u0131. Ancak a\u00e7\u0131lar yar\u0131m derece daha fazla a\u00e7\u0131lmaya ba\u015fl\u0131yor ve ikinci flan\u015f\u0131n\u0131z .020 uzunlu\u011fa sap\u0131yor. \u015eimdi, iyi par\u00e7alar\u0131 yava\u015f yava\u015f yeniden i\u015flenmesi gereken par\u00e7alara d\u00f6n\u00fc\u015ft\u00fcren \u201cdo\u011fru\u201d bir programa bak\u0131yorsunuz.<\/p>\n\n\n\n

              Peki, teori kan\u0131tland\u0131ktan sonra parti baz\u0131ndaki de\u011fi\u015fkenli\u011fi nas\u0131l kontrol edersiniz?<\/p>\n\n\n\n

              Say\u0131lar\u0131 giren biri gibi davranmay\u0131 b\u0131rak\u0131p sistemin sahibi gibi davranmaya ba\u015flay\u0131n.<\/p>\n\n\n\n

              Bir hesap makinesi kullan\u0131c\u0131s\u0131 \u201cTonaj nedir?\u201d diye sorar. Bir s\u00fcre\u00e7 sahibi ise \u201cSistemde ne de\u011fi\u015fti?\u201d diye sorar.\u201d<\/p>\n\n\n\n

              Kuvvet, tak\u0131m, damar y\u00f6n\u00fc, ger\u00e7ek akma dayan\u0131m\u0131, tabla esnemesi, hatta y\u00fck\u00fc \u00e7er\u00e7evenin neresine uygulad\u0131\u011f\u0131n\u0131z; bunlar\u0131n hepsi ayr\u0131 konular de\u011fildir. Bunlar, 60, 100, bazen 200 tonluk bas\u0131n\u00e7 alt\u0131nda ger\u00e7ekle\u015fen tek bir mekanik olayd\u0131r. Bir de\u011fi\u015fken sapt\u0131\u011f\u0131nda, geometri de sapar. Bu sapmay\u0131 yakalay\u0131p d\u00fczeltmenin bir yoluna sahip de\u011filseniz, hesap makinesi sahte bir g\u00fcvenlik duygusundan ibaret kal\u0131r.<\/p>\n\n\n\n

              Bariz olmayan k\u0131s\u0131m m\u0131? Makine hassasiyeti genellikle sorun de\u011fildir. Modern abkant presler, di\u011fer her \u015fey sabit oldu\u011funda a\u00e7\u0131y\u0131 yar\u0131m derece civar\u0131nda tutar. Konumland\u0131rma tekrarlanabilirli\u011fi, \u00e7o\u011fu operat\u00f6r\u00fcn \u00f6l\u00e7ebilece\u011finden daha hassast\u0131r. \u0130stikrars\u0131zl\u0131k, ko\u00e7un etraf\u0131ndaki malzeme ve tak\u0131m ekosisteminde ya\u015fan\u0131r.<\/p>\n\n\n\n

              Sahiplik burada ba\u015flar.<\/p>\n\n\n\n

              Abkant pres hesap makinesini bir garanti de\u011fil, bir korkuluk olarak g\u00f6rmek<\/h3>\n\n\n\n

              Bir hesap makinesine say\u0131lar\u0131 girdi\u011finizde tek bir \u015fey yap\u0131yorsunuz: kamyonun k\u00f6pr\u00fc i\u00e7in \u00e7ok a\u011f\u0131r olup olmad\u0131\u011f\u0131n\u0131 kontrol etmek.<\/p>\n\n\n\n

              Hepsi bu.<\/p>\n\n\n\n

              \u201cHesap makinesi 74 ton dedi.\u201d G\u00fczel. Makine a\u015f\u0131r\u0131 y\u00fcklenmeyecek. Ancak bu say\u0131, o 74 tonu 4 fit mi yoksa 10 fit boyunca m\u0131 uygulad\u0131\u011f\u0131n\u0131z, \u00e7er\u00e7eve geni\u015fli\u011finin '\u0131 i\u00e7inde olup olmad\u0131\u011f\u0131n\u0131z veya kal\u0131p \u00fcreticinizin o tak\u0131m\u0131 90 derece yerine 30 derecede fit ba\u015f\u0131na k\u0131sa ton cinsinden derecelendirip derecelendirmedi\u011fi hakk\u0131nda hi\u00e7bir \u015fey s\u00f6ylemez.<\/p>\n\n\n\n

              \u00dczerinde \u201c80 ton\/ft\u201d damgas\u0131 olan ancak tedarik\u00e7iler farkl\u0131 derecelendirme y\u00f6ntemleri kulland\u0131\u011f\u0131 i\u00e7in tamamen farkl\u0131 anlamlara gelen iki kal\u0131p g\u00f6rd\u00fcm. Biri s\u0131\u011f bir b\u00fck\u00fcm\u00fc varsay\u0131yordu. Di\u011feri ise tabana oturtmay\u0131 varsay\u0131yordu. Ayn\u0131 damga. Farkl\u0131 ger\u00e7eklik. Bunu hesap makinesini a\u00e7madan \u00f6nce \u00e7\u00f6zmezseniz, matemati\u011finizi kum \u00fczerine in\u015fa ediyorsunuz demektir.<\/p>\n\n\n\n

              Bir de internette kimsenin konu\u015fmad\u0131\u011f\u0131 o sessiz \u00f6d\u00fcnle\u015fim var: tonaj\u0131 azaltmak i\u00e7in V-kal\u0131b\u0131 a\u00e7\u0131n, evet, kuvvet d\u00fc\u015fer; ancak i\u00e7 yar\u0131\u00e7ap b\u00fcy\u00fcr. Daha b\u00fcy\u00fck yar\u0131\u00e7ap, n\u00f6tr ekseninizi kayd\u0131r\u0131r. N\u00f6tr eksen kaymas\u0131, b\u00fck\u00fcm indirimini de\u011fi\u015ftirir. A\u00e7\u0131n\u0131m\u0131n\u0131z (flat pattern) art\u0131k de\u011fi\u015fti.<\/p>\n\n\n\n

              Makine daha g\u00fcvenli. Par\u00e7a hatal\u0131.<\/p>\n\n\n\n

              \u0130\u015fte bu y\u00fczden hesap makinesi bir korkuluktur. Sizi felaketle sonu\u00e7lanacak bir a\u015f\u0131r\u0131 y\u00fcklenmeden korur. 1.200 paslanmaz \u00e7elik levha y\u00fckl\u00fc kamyonu iskeleye hasars\u0131z bir \u015fekilde y\u00f6nlendirmez.<\/p>\n\n\n\n

              Hurda Kutusu Uyar\u0131s\u0131: Bu hata, \u201cg\u00fcvenlik i\u00e7in\u201d yap\u0131lan bir kal\u0131p de\u011fi\u015fiminden sonra a\u00e7\u0131 kontrol\u00fcn\u00fc ge\u00e7en ancak flan\u015f uzunlu\u011fu .030 ile .060 aras\u0131nda sapan par\u00e7alar olarak ortaya \u00e7\u0131kar. Makine g\u00fcnl\u00fc\u011f\u00fc m\u00fckemmel g\u00f6r\u00fcn\u00fcr. Par\u00e7alar kaynak fikst\u00fcr\u00fcne uymaz. Lazer hassasiyetini su\u00e7lamaya ba\u015flars\u0131n\u0131z. As\u0131l su\u00e7lu, asla yeniden hesaplamad\u0131\u011f\u0131n\u0131z geometri sapmas\u0131d\u0131r.<\/p>\n\n\n\n

              Peki, hesap makinesi sadece u\u00e7urumun kenar\u0131n\u0131 koruyorsa, ger\u00e7ekte nas\u0131l y\u00f6nlendirme yapars\u0131n\u0131z?<\/p>\n\n\n\n

              Ger\u00e7ek b\u00fck\u00fcmler ile gelecekteki tahminler aras\u0131nda at\u00f6lye kat\u0131nda bir geri bildirim d\u00f6ng\u00fcs\u00fc olu\u015fturmak<\/h3>\n\n\n\n

              De\u011fi\u015fkenli\u011fi, ger\u00e7ekle\u015fece\u011fini varsayarak kontrol edersiniz.<\/p>\n\n\n\n

              Yeni \u00e7elik partisi mi? Bir \u00f6nceki \u00e7al\u0131\u015fman\u0131n b\u00fck\u00fcm indirimine g\u00fcvenmezsiniz. Bu partiden, bu damar y\u00f6n\u00fcnde, bu kal\u0131pta, bu uzunlukta bir test numunesi kesersiniz. \u00dc\u00e7 \u015feyi \u00f6l\u00e7ersiniz: geri esneme (springback) sonras\u0131 a\u00e7\u0131, \u00f6l\u00e7ebiliyorsan\u0131z i\u00e7 yar\u0131\u00e7ap ve flan\u015f uzunlu\u011fu.<\/p>\n\n\n\n

              \u015eimdi bunu tekrar matemati\u011fe d\u00f6n\u00fc\u015ft\u00fcr\u00fcn. E\u011fer flan\u015f .018 uzunsa, bu b\u00fck\u00fcm indiriminizin .018 eksik oldu\u011fu anlam\u0131na gelir. Bu teori de\u011fil; metalin size y\u00fck alt\u0131nda n\u00f6tr ekseninizin ger\u00e7ekte nerede durdu\u011funu s\u00f6ylemesidir.<\/p>\n\n\n\n

              Bu i\u015f, bu malzeme ve bu tak\u0131m i\u00e7in a\u00e7\u0131n\u0131m tablonuzdaki say\u0131y\u0131 de\u011fi\u015ftirin. M\u00fcmk\u00fcnse bunu d\u00f6k\u00fcm veya tedarik\u00e7i ile etiketleyin. Art\u0131k bir sonraki par\u00e7a umudu de\u011fil, ger\u00e7ekli\u011fi yans\u0131t\u0131yor.<\/p>\n\n\n\n

              Geri bildirim d\u00f6ng\u00fcs\u00fc budur: Tahmin et \u2192 Test b\u00fck\u00fcm\u00fc yap \u2192 \u00d6l\u00e7 \u2192 B\u00fck\u00fcm indirimini ayarla \u2192 Program\u0131 kilitle.<\/p>\n\n\n\n

              Ve bunu bir de\u011fi\u015fken her de\u011fi\u015fti\u011finde tekrarlars\u0131n\u0131z: kal\u0131p geni\u015fli\u011fi, malzeme partisi, sizi \u00e7er\u00e7eve s\u0131n\u0131rlar\u0131na yakla\u015ft\u0131ran b\u00fck\u00fcm uzunlu\u011fu.<\/p>\n\n\n\n

              Ge\u00e7en bahar bir gen\u00e7, 10 fitlik 11 kalibre paslanmaz \u00e7eli\u011fi \u2014312 dolar de\u011ferinde malzeme\u2014 tamamen \u201cg\u00fcvenli\u201d bir kurulumdan ge\u00e7irdi. Tonaj uygundu. Makine memnundu. Yapmad\u0131\u011f\u0131 \u015fey, yeni palet geldi\u011finde yeniden test etmemekti. Akma dayan\u0131m\u0131 daha y\u00fcksekti. Geri yaylanma artt\u0131. Flan\u015flar uzad\u0131. Birisi montaj geni\u015fli\u011fini kontrol etti\u011finde, \u00fc\u00e7 par\u00e7a \u00e7oktan b\u00fck\u00fclm\u00fc\u015ft\u00fc.<\/p>\n\n\n\n

              Bu bir hesap makinesi hatas\u0131 de\u011fildi.<\/p>\n\n\n\n

              Bu, eksik bir geri bildirim d\u00f6ng\u00fcs\u00fcyd\u00fc.<\/p>\n\n\n\n

              Hurda Kutusu Uyar\u0131s\u0131: Parti varyasyonu hatalar\u0131, yava\u015f bir a\u00e7\u0131 kaymas\u0131 olarak ortaya \u00e7\u0131kar \u2014 90.0, sonra 89.6, sonra 89.2 \u2014 ve operat\u00f6rler b\u00fck\u00fcm pay\u0131n\u0131 g\u00fcncellemeden ko\u00e7 derinli\u011fini .005 veya .010 art\u0131\u015flarla y\u00fckseltir. A\u00e7\u0131 d\u00fczeltilir. Ancak d\u00fcz par\u00e7a tasar\u0131m\u0131 d\u00fczeltilmez. \u00c7ok b\u00fck\u00fcml\u00fc par\u00e7alar, son flan\u015f kutuyu a\u00e7maya zorlayana kadar hata biriktirmeye ba\u015flar.<\/p>\n\n\n\n

              \u015eimdi a\u00e7\u0131y\u0131 yakalamak i\u00e7in derinli\u011fi ayarl\u0131yorsunuz. Peki siz bunu yaparken makineyi ne koruyor?<\/p>\n\n\n\n

              Makine a\u015f\u0131r\u0131 y\u00fck riskini ve malzeme hurdas\u0131n\u0131 ayn\u0131 anda azaltmak<\/h3>\n\n\n\n

              \u0130\u015fte zihinsel de\u011fi\u015fim.<\/p>\n\n\n\n

              Makine g\u00fcvenli\u011fini ve par\u00e7a do\u011frulu\u011funu iki ayr\u0131 hedef olarak g\u00f6rmeyi b\u0131rak\u0131n. Bunlar, farkl\u0131 taraflardan bak\u0131lan ayn\u0131 kontrol problemidir.<\/p>\n\n\n\n

              Fit ba\u015f\u0131na kuvvet sadece bir kapasite say\u0131s\u0131 de\u011fildir. Bu bir da\u011f\u0131l\u0131m problemidir. E\u011fer yan \u00e7er\u00e7eve mesafesinin '\u0131ndan daha az\u0131nda tam tonajla \u00e7al\u0131\u015f\u0131rsan\u0131z, hesap makinesi ne derse desin \u00e7er\u00e7eve hasar\u0131 riskiyle kar\u015f\u0131 kar\u015f\u0131ya kal\u0131rs\u0131n\u0131z. Bu, makinenin kendi geometrisidir. Bu nedenle par\u00e7a uzunlu\u011fu ve b\u00fck\u00fcm konumu, sadece yerle\u015fim detaylar\u0131 de\u011fil, yap\u0131sal de\u011fi\u015fkenler haline gelir.<\/p>\n\n\n\n

              Yeni bir parti, a\u00e7\u0131y\u0131 yakalamak i\u00e7in daha fazla penetrasyona ihtiya\u00e7 duydu\u011funda, bu, strokun alt k\u0131sm\u0131nda daha y\u00fcksek \u015fekillendirme kuvveti anlam\u0131na gelir. Daha fazla penetrasyon, daha s\u0131k\u0131 bir sar\u0131m demektir. Daha s\u0131k\u0131 sar\u0131m radyusu kayd\u0131r\u0131r. Radyus kaymas\u0131 b\u00fck\u00fcm pay\u0131n\u0131 de\u011fi\u015ftirir. Ve fit ba\u015f\u0131na artan kuvvet, sizi tak\u0131m veya \u00e7er\u00e7eve s\u0131n\u0131rlar\u0131na daha fazla yakla\u015ft\u0131rabilir.<\/p>\n\n\n\n

              Tek bir ayar di\u011ferlerinin hepsini hareket ettirir.<\/p>\n\n\n\n

              Bir s\u00fcre\u00e7 sahibi sadece derinli\u011fi art\u0131rmaz. \u015eunu sorar:<\/p>\n\n\n\n

                \n
              • Bu ger\u00e7ek b\u00fck\u00fcm uzunlu\u011fu boyunca fit ba\u015f\u0131na mevcut tonaj\u0131m nedir?<\/li>\n\n\n\n
              • E\u011fer penetrasyonu .015 art\u0131r\u0131rsam, kuvvet ne kadar y\u00fckselir?<\/li>\n\n\n\n
              • Hala tak\u0131m derecelendirmesinin i\u00e7inde miyim \u2014 ayn\u0131 derecelendirme y\u00f6ntemini kullanarak?<\/li>\n\n\n\n
              • Yeni radyus, b\u00fck\u00fcm pay\u0131n\u0131n g\u00fcncellenmesini gerektiriyor mu?<\/li>\n<\/ul>\n\n\n\n

                Bu, hem y\u00fck kay\u0131\u015flar\u0131n\u0131 hem de a\u011f\u0131rl\u0131k derecesini izlerken kamyonu s\u00fcrmeye benzer.<\/p>\n\n\n\n

                Bariz olmayan \u00e7\u0131kar\u0131m \u2014 yan\u0131n\u0131zda ta\u015f\u0131yaca\u011f\u0131n\u0131z \u015fey \u2014 \u015fudur:<\/p>\n\n\n\n

                De\u011fi\u015fkenli\u011fi onu ortadan kald\u0131rarak kontrol etmezsiniz. Onu, sapma ile d\u00fczeltme aras\u0131ndaki s\u00fcreyi k\u0131saltarak kontrol edersiniz.<\/p>\n\n\n\n

                \u201cMalzeme de\u011fi\u015fti\u201d ile \u201cd\u00fcz desen g\u00fcncellendi\u201d aras\u0131ndaki d\u00f6ng\u00fcn\u00fcz bir test b\u00fck\u00fcm\u00fc uzunlu\u011fundaysa, de\u011fi\u015fkenlik size bir numuneye mal olur. E\u011fer bu d\u00f6ng\u00fc on par\u00e7a uzunlu\u011fundaysa, de\u011fi\u015fkenlik size 2 oran\u0131nda \u015ferit ve \u00e7arp\u0131lm\u0131\u015f montaj par\u00e7alar\u0131na mal olur.<\/p>\n\n\n\n

                Hesap makinesi sizi yoldan \u00e7\u0131kmaktan korur.<\/p>\n\n\n\n

                S\u00fcre\u00e7 sahipli\u011fi, y\u00fck\u00fcn m\u00fc\u015fteriye ula\u015fmas\u0131n\u0131 sa\u011flar.<\/p>\n\n\n\n

                Ve her b\u00fck\u00fcm\u00fc kuvvet, geometri, kal\u0131p derecesi ve parti davran\u0131\u015f\u0131 aras\u0131ndaki canl\u0131 bir etkile\u015fim olarak g\u00f6rmeye ba\u015flad\u0131\u011f\u0131n\u0131zda, \u201cHangi say\u0131y\u0131 girmeliyim?\u201d diye sormay\u0131 b\u0131rak\u0131rs\u0131n\u0131z.\u201d<\/p>\n\n\n\n

                \u201cMetal bana \u015fu an ne anlat\u0131yor?\u201d diye sormaya ba\u015flars\u0131n\u0131z.\u201d<\/p>\n\n\n\n

                <\/p>","protected":false},"excerpt":{"rendered":"

                Ge\u00e7en bahar bir \u00e7ocuk, 11 ayar paslanmaz \u00e7elikten 10 fitlik bir \u015feridi \u2014312 dolar de\u011ferinde malzeme\u2014 tamamen \u201cg\u00fcvenli\u201d bir kurulumdan ge\u00e7irdi. Hesap makinesi 74 ton diyordu. 135 tonluk presimiz t\u0131k bile demedi. Her iki bacak da 1\/8 in\u00e7 k\u0131sa \u00e7\u0131kt\u0131. Makine gayet iyiydi. Par\u00e7a ise \u00e7\u00f6p oldu. \u201cG\u00fcvenli vuru\u015f\u201d ile \u201cdo\u011fru par\u00e7a\u201d aras\u0131ndaki o bo\u015fluk, \u00e7o\u011fu gencin [\u2026]<\/p>","protected":false},"author":3,"featured_media":1165,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_breakdance_hide_in_design_set":false,"_breakdance_tags":"","footnotes":""},"categories":[1],"tags":[],"class_list":["post-1164","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-uncategorized"],"_links":{"self":[{"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/posts\/1164","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/comments?post=1164"}],"version-history":[{"count":1,"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/posts\/1164\/revisions"}],"predecessor-version":[{"id":1170,"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/posts\/1164\/revisions\/1170"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/media\/1165"}],"wp:attachment":[{"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/media?parent=1164"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/categories?post=1164"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/tags?post=1164"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}