\u0130\u015fte o zaman tehlikeli bir soruyu sormaya ba\u015flars\u0131n\u0131z: Tam olarak o form\u00fcl neyi varsay\u0131yordu?<\/p>\n\n\n\n
Evrensel Form\u00fcl Miti (ve Neden Kal\u0131plar\u0131 S\u00fcrekli K\u0131r\u0131yor)<\/h2>\n\n\n\n
Herhangi bir imalat at\u00f6lyesine girin, birinin onu ezbere bildi\u011fini duyars\u0131n\u0131z: 575 \u00e7arp\u0131 kal\u0131nl\u0131\u011f\u0131n karesi \u00e7arp\u0131 uzunluk, b\u00f6l\u00fc kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131. Yer\u00e7ekimi yasas\u0131 gibi geliyor. Say\u0131lar\u0131 girersiniz, kuvvet \u00e7\u0131kar.<\/p>\n\n\n\n
Ama 575 bir fizik yasas\u0131 de\u011fildir. \u00c7ok spesifik bir duruma g\u00f6re olu\u015fturulmu\u015f bir kestirmedir: yakla\u015f\u0131k 60.000 PSI \u00c7EKME MUKAVEMET\u0130<\/strong>, olan yumu\u015fak \u00e7eli\u011fin hava b\u00fck\u00fcm\u00fc, malzeme kal\u0131nl\u0131\u011f\u0131n\u0131n yakla\u015f\u0131k sekiz kat\u0131 a\u00e7\u0131kl\u0131\u011fa sahip bir kal\u0131pla. Bunlardan herhangi birini de\u011fi\u015ftirin ve \u201cyakla\u015f\u0131k\u201d olmazs\u0131n\u0131z. Farkl\u0131 bir denklemin i\u00e7indesinizdir.<\/p>\n\n\n\n Birinin \u201cyar\u0131\u00e7ap\u0131 keskinle\u015ftirmek\u201d i\u00e7in daha dar bir kal\u0131pla de\u011fi\u015ftirdi\u011fi 90 tonluk bir i\u015fin 130 tonluk bir ger\u00e7e\u011fe d\u00f6n\u00fc\u015ft\u00fc\u011f\u00fcn\u00fc g\u00f6rd\u00fcm. Makine \u015fikayet etmedi. Kal\u0131plar etti.<\/p>\n\n\n\n Hadi somut konu\u015fal\u0131m.<\/p>\n\n\n\n O 575 kestirmesinin arkas\u0131ndaki tam bi\u00e7im \u015f\u00f6yledir:<\/p>\n\n\n\n Kuvvet \u015fu oranda de\u011fi\u015fir: \u00c7EKME MUKAVEMET\u0130 \u00d7 KALINLIK\u00b2 \u00d7 UZUNLUK \u00f7 KALIP A\u00c7IKLI\u011eI<\/strong>.<\/p>\n\n\n\n O karesel KALINLIK<\/strong> terimi ilk may\u0131n tarlas\u0131d\u0131r. Kal\u0131nl\u0131\u011f\u0131 iki kat\u0131na \u00e7\u0131kar\u0131rsan\u0131z kuvveti ikiye de\u011fil, d\u00f6rde katlars\u0131n\u0131z. \u015eimdi orada ba\u015fka neyin gizlendi\u011fine dikkat edin: KALIP A\u00c7IKLI\u011eI<\/strong> paydada. A\u00e7\u0131kl\u0131\u011f\u0131 k\u00fc\u00e7\u00fclt\u00fcn\u2026 V\u2011KALIP A\u00c7IKLI\u011eI<\/strong> 10% taraf\u0131ndan, ve kuvvet kibarca artmaz. Geometri kald\u0131ra\u00e7 oldu\u011fu i\u00e7in sert bir \u015fekilde s\u0131\u00e7rar.<\/p>\n\n\n\n Peki ya 575 sabiti? Bu sadece yakla\u015f\u0131k 60.000 PSI\u2019da 8\u00d7 oran\u0131yla yumu\u015fak \u00e7elik i\u00e7in zaten \u00e7\u00f6z\u00fclm\u00fc\u015f matematik. KALIP ORANI<\/strong> hava b\u00fckmede. Bu bir ba\u015flang\u0131\u00e7 noktas\u0131d\u0131r, kutsal bir de\u011fer de\u011fil.<\/p>\n\n\n\n Y\u0131llar \u00f6nce, yeni bir programc\u0131 paslanmaz \u00e7elik \u2014 90.000 PSI \u2014 \u00c7EKME MUKAVEMET\u0130<\/strong> \u2014 ayn\u0131 575 ayar\u0131nda, malzeme fakt\u00f6r\u00fcn\u00fc ayarlamadan \u00e7al\u0131\u015ft\u0131rd\u0131. Z\u0131mba hayatta kald\u0131. Alt kal\u0131p omuzlardan mantar gibi \u015fi\u015fti. Bir g\u00fcn\u00fcm\u00fcz\u00fc kaybetmedik. \u0130tibar\u0131m\u0131z\u0131 kaybettik.<\/p>\n\n\n\n Yani hesap makinesine 575 yazarken kendine sor: h\u00e2l\u00e2 o varsay\u0131mlar\u0131n i\u00e7inde misin?<\/p>\n\n\n\n K\u0131sayolu neden herkesin sevdi\u011fini biliyorum. KALINLIK \u00d7 UZUNLUK<\/strong> somut gelir. \u00c7izimde g\u00f6rebilirsin. Metreyle \u00f6l\u00e7ebilirsin.<\/p>\n\n\n\n \u015eunu g\u00f6remezsin: \u00c7EKME MUKAVEMET\u0130<\/strong> sat\u0131n alma departman\u0131 daha ucuz tedarik\u00e7i buldu\u011fu i\u00e7in 60.000\u2019den 80.000 PSI\u2019a ge\u00e7i\u015fi. Hava b\u00fckmeden bast\u0131rma i\u015flemine ge\u00e7i\u015fteki art\u0131\u015f\u0131 hissetmezsin; temas alan\u0131 \u2014 ve gereken kuvvet \u2014 h\u0131zla artar. Ve biri 8\u00d7\u2019ten 6\u00d7\u2019e ge\u00e7ti\u011finde kesinlikle fark etmezsin, V\u2011KALIP A\u00c7IKLI\u011eI<\/strong> i\u00e7 yar\u0131\u00e7ap\u0131 kontrol etmek i\u00e7in, \u00e7izime dokunmadan gereken tonaj\u0131 fiilen art\u0131rm\u0131\u015f olur.<\/p>\n\n\n\n Kuvvet, \u00f6l\u00e7\u00fclmesi kolay olana ald\u0131rmaz. Malzeme direncine ve geometriye tepki verir.<\/p>\n\n\n\n Bir keresinde 290 tonluk bir makine, \u00e7oklu b\u00fck\u00fcml\u00fc bir kurulumda vuru\u015f ortas\u0131nda durdu. K\u00e2\u011f\u0131t \u00fczerinde, her b\u00fck\u00fcm \u201cg\u00fcvenliydi.\u201d Ancak hepsi birlikte, tek bir darbede y\u00fckler birikti. Matematik yanl\u0131\u015f de\u011fildi. Eksikti.<\/p>\n\n\n\n \u201cYeterince yak\u0131n\u201d, tak\u0131m\u0131n \u00f6l\u00fcm sebebidir.<\/p>\n\n\n\n Bir 20% d\u00fc\u015f\u00fck tahmin sadece a\u015f\u0131r\u0131 y\u00fck riski yaratmaz; gerilimi kal\u0131p omuzlar\u0131nda ve z\u0131mba ucunda yo\u011funla\u015ft\u0131r\u0131r. \u00c7elik kibarca uyarmaz. \u00d6nce akmaya ba\u015flar, sonra k\u0131r\u0131l\u0131r. Ve k\u0131r\u0131ld\u0131\u011f\u0131nda, o \u015foku ko\u00e7una, k\u0131zaklar\u0131na, g\u00f6vdene geri g\u00f6nderir.<\/p>\n\n\n\n Bir hidrolik abkant presin beklenmedik bir y\u00fck alt\u0131nda yeterince buruldu\u011funu, yatak boyunca tutars\u0131z a\u00e7\u0131lar \u00fcretmeye ba\u015flad\u0131\u011f\u0131n\u0131 izledim. Dramatik de\u011fildi. Sadece paralellikte yava\u015f\u00e7a azalan bir kay\u0131p, haftalarca hayali \u201cspringback\u201d sorunlar\u0131n\u0131 kovalamaya d\u00f6n\u00fc\u015ft\u00fc. Temel neden mi? Hava b\u00fckme i\u00e7in hesaplanan tonaj, i\u015f alt b\u00fckme kuvvetine daha yak\u0131n \u00e7al\u0131\u015ft\u0131r\u0131lm\u0131\u015ft\u0131.<\/p>\n\n\n\n Form\u00fcl ba\u015far\u0131s\u0131z olmad\u0131. Operat\u00f6r oldu \u2014 \u00e7\u00fcnk\u00fc evrensel oldu\u011funu varsayd\u0131.<\/p>\n\n\n\n Tak\u0131m\u0131n\u0131z\u0131 matematik karma\u015f\u0131k oldu\u011fu i\u00e7in k\u0131rmazs\u0131n\u0131z. Matemati\u011fin ne varsayd\u0131\u011f\u0131n\u0131 sormay\u0131 b\u0131rakt\u0131\u011f\u0131n\u0131z i\u00e7in k\u0131rars\u0131n\u0131z.<\/p>\n\n\n\n Birka\u00e7 y\u0131l \u00f6nce A36 \u00e7eyrek in\u00e7 levhadan on fit uzunlu\u011funda bir i\u015f i\u00e7in fiyat vermi\u015ftik. 3 in\u00e7lik bir V kal\u0131b\u0131 \u00fczerinde levha yakla\u015f\u0131k 139 ton olarak hesapland\u0131. Temiz. 150 tonluk bir abkant pres i\u00e7in g\u00fcvenli. Ayn\u0131 kal\u0131nl\u0131k, ayn\u0131 uzunluk \u2014 ama m\u00fc\u015fteri daha dar bir i\u00e7 yar\u0131\u00e7ap istedi, bu y\u00fczden kurulum g\u00f6revlisi 1.5 in\u00e7lik bir kal\u0131p ald\u0131.<\/p>\n\n\n\n Tonaj yakla\u015f\u0131k 300 tona f\u0131rlad\u0131.<\/p>\n\n\n\n Ba\u015fka hi\u00e7bir \u015fey de\u011fi\u015fmedi. Kal\u0131nl\u0131k de\u011fil KALINLIK<\/strong>. Uzunluk de\u011fil UZUNLUK<\/strong>. Sadece geometri.<\/p>\n\n\n\n \u0130\u015fte o zaman \u201ckal\u0131nl\u0131k problemi\u201d olmaktan \u00e7\u0131k\u0131p \u201cdiren\u00e7 problemi\u201d olmaya ba\u015flar. Abkant pres, \u00e7izimde ne yazd\u0131\u011f\u0131yla ilgilenmez. \u00dc\u00e7 \u015feye tepki verir: malzemenin uzamaya kar\u015f\u0131 direncine, kal\u0131p geometrinizin sa\u011flad\u0131\u011f\u0131 kald\u0131ra\u00e7 g\u00fcc\u00fcne ve metali ne kadar tamamen \u015fekle zorlad\u0131\u011f\u0131n\u0131za.<\/p>\n\n\n\n Birini ka\u00e7\u0131r\u0131rsan\u0131z, 575 k\u0131sa yolunuz namluda yanl\u0131\u015f fi\u015fekle dolu bir silaha d\u00f6n\u00fc\u015f\u00fcr.<\/p>\n\n\n\n Yani 575 sadece varsay\u0131mlar\u0131n\u0131n i\u00e7inde \u00e7al\u0131\u015f\u0131yorsa, d\u0131\u015f\u0131nda nas\u0131l do\u011fru hesap yapars\u0131n\u0131z? Tonaj\u0131 tablo de\u011feri gibi de\u011fil, fizik gibi ele almaya ba\u015flars\u0131n\u0131z: KUVVET \u221d \u00c7EKME MUKAVEMET\u0130 \u00d7 KALINLIK\u00b2 \u00d7 UZUNLUK \u00f7 KALIP A\u011eZI<\/strong> \u2014 ve sonra b\u00fckme y\u00f6ntemine g\u00f6re ayarlars\u0131n\u0131z.<\/p>\n\n\n\n \u00dc\u00e7 de\u011fi\u015fken. Her biri \u00e7izime dokunmadan y\u00fck\u00fcn\u00fcz\u00fc iki kat\u0131na \u00e7\u0131karabilir.<\/p>\n\n\n\n Hadi bunlar\u0131 teker teker ele alal\u0131m.<\/p>\n\n\n\n Bir programc\u0131 bir keresinde hesapta 60.000 PSI yumu\u015fak \u00e7eli\u011fi 90.000 PSI paslanmaz \u00e7elikle de\u011fi\u015ftirdi ve geri kalan her \u015feyi ayn\u0131 b\u0131rakt\u0131. Ayn\u0131 \u00e7eyrek in\u00e7 plaka. Ayn\u0131 kal\u0131p. Ayn\u0131 uzunluk.<\/p>\n\n\n\n K\u00e2\u011f\u0131t \u00fczerinde mi? Ayn\u0131 kurulum.<\/p>\n\n\n\n Ger\u00e7ekte, gerekli tonaj % artt\u0131.<\/p>\n\n\n\n \u0130\u015fte nedeni. Hava b\u00fckme yapt\u0131\u011f\u0131n\u0131zda, malzemenin d\u0131\u015f liflerini akma noktas\u0131n\u0131n \u00f6tesine kadar gerersiniz. Akma dayan\u0131m\u0131 ne kadar y\u00fcksekse \u00c7EKME MUKAVEMET\u0130<\/strong>, bu lifler plastik olarak deforme olmadan \u00f6nce o kadar fazla gerilime kar\u015f\u0131 direnir. Form\u00fcl \u201cpaslanmaz\u201d veya \u201ckarbon\u201d etiketine ald\u0131rmaz. Do\u011frudan \u00c7EKME MUKAVEMET\u0130<\/strong>.<\/p>\n\n\n\n akma dayan\u0131m\u0131yla orant\u0131l\u0131d\u0131r.<\/p>\n\n\n\n Temel sabitinizin 60.000 PSI varsayd\u0131\u011f\u0131n\u0131 ve siz 90.000 PSI ile \u00e7al\u0131\u015ft\u0131\u011f\u0131n\u0131z\u0131 d\u00fc\u015f\u00fcn\u00fcrsek, \u00e7arpan\u0131n\u0131z:<\/p>\n\n\n\n 90.000 \u00f7 60.000 = 1,5.<\/p>\n\n\n\n Bu bir yuvarlama hatas\u0131 de\u011fil. Bu, 100 tonluk bir i\u015fin 150 ton olmas\u0131 demek.<\/p>\n\n\n\n Ve paslanmaz durumunuzu daha da k\u00f6t\u00fcle\u015ftirir. Akma dayan\u0131m\u0131, genellikle yumu\u015fak \u00e7eli\u011fe k\u0131yasla \u00e7ekme dayan\u0131m\u0131na daha yak\u0131n olur ve daha h\u0131zl\u0131 pekle\u015fir. Bu da b\u00fckme ilerledik\u00e7e direncin artmas\u0131 demektir. Presiniz bunu strokun alt k\u0131sm\u0131nda y\u00fck art\u0131\u015f\u0131 olarak hisseder.<\/p>\n\n\n\n Bir keresinde, biri paslanmaz i\u00e7in acele bir i\u015fte yumu\u015fak \u00e7elik tablosuna g\u00fcvendi\u011fi i\u00e7in yepyeni bir b\u00f6lmeli kal\u0131b\u0131n omuzlar\u0131 boyunca \u00e7atlad\u0131\u011f\u0131n\u0131 g\u00f6rm\u00fc\u015ft\u00fcm. Makine kapasitesi dahilindeydi. Tak\u0131m ise de\u011fildi. Par\u00e7ay\u0131 hurdaya \u00e7\u0131karmad\u0131k. Kal\u0131b\u0131 hurdaya \u00e7\u0131kard\u0131k. \u00c7EKME MUKAVEMET\u0130<\/strong> Paslanmaz \u201cdaha a\u011f\u0131r\u201d de\u011fildir. \u00c7ekme dayan\u0131m\u0131 a\u00e7\u0131s\u0131ndan daha g\u00fc\u00e7l\u00fcd\u00fcr. Form\u00fcl zaten size ne yapman\u0131z gerekti\u011fini s\u00f6yledi \u2014 ger\u00e7ek.<\/p>\n\n\n\n akma dayan\u0131m\u0131n\u0131 temel de\u011fere oranlayarak \u00e7arpmak.<\/p>\n\n\n\n V-Kal\u0131p A\u00e7\u0131kl\u0131\u011f\u0131: 8:1 kural\u0131 ve kal\u0131b\u0131 daraltt\u0131\u011f\u0131n\u0131zda tonaj\u0131n \u00fcssel \u015fekilde artmas\u0131.<\/p>\n\n\n\n \u015eimdi kald\u0131ra\u00e7tan bahsedelim. Yayg\u0131n kural 8:1 oran\u0131d\u0131r \u2014<\/strong> V-KALIP A\u00c7IKLI\u011eI \u2248 8 \u00d7 KALINLIK.<\/p>\n\n\n\n yumu\u015fak \u00e7eli\u011fi hava b\u00fckmede. Bu oran \u00e7o\u011fu tonaj tablosuna yerle\u015fmi\u015ftir. Rahat. \u00d6ng\u00f6r\u00fclebilir.<\/p>\n\n\n\n Ama 575 bir fizik kanunu de\u011fildir. KALIP A\u00c7IKLI\u011eI<\/strong> O \u00e7eyrek in\u00e7lik plaka \u00f6rne\u011fine tekrar bak\u0131n. 3 in\u00e7lik kal\u0131p ile 1,5 in\u00e7lik kal\u0131p. Kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131n\u0131.<\/p>\n\n\n\n yar\u0131ya d\u00fc\u015f\u00fcr\u00fcrs\u00fcn\u00fcz ve denklemde payda k\u0131sm\u0131nda yer ald\u0131\u011f\u0131 i\u00e7in gerekli kuvvet iki kat\u0131na \u00e7\u0131kar.<\/p>\n\n\n\n Bu, tamamen mekanik. Daha dar bir kal\u0131p, malzemenin k\u00f6pr\u00fcledi\u011fi a\u00e7\u0131kl\u0131\u011f\u0131 azalt\u0131r, bu da plastik deformasyonu zorlamak i\u00e7in gereken e\u011filme momentini art\u0131r\u0131r. Kald\u0131ra\u00e7 kolunu k\u0131saltt\u0131n. Pres bunu kuvvetle telafi eder.<\/p>\n\n\n\n \u0130\u015fte tuzak: operat\u00f6rler, i\u00e7 yar\u0131\u00e7ap\u0131 \u201ctemizlemek\u201d veya geri yaylanmay\u0131 kontrol etmek i\u00e7in kal\u0131b\u0131 s\u0131k\u0131\u015ft\u0131r\u0131r. \u00c7izim de\u011fi\u015fmez. KALINLIK<\/strong> de\u011fi\u015fmez. Ancak geometrinin de\u011fi\u015fmesi nedeniyle tonaj h\u0131zla artar.<\/p>\n\n\n\n Birinin yar\u0131\u00e7ap\u0131 \u201ckeskinle\u015ftirmek\u201d i\u00e7in daha dar bir kal\u0131pla de\u011fi\u015ftirdi\u011fi bir 90 tonluk i\u015fin, ger\u00e7ekte 130 tonluk bir duruma d\u00f6n\u00fc\u015ft\u00fc\u011f\u00fcn\u00fc g\u00f6rd\u00fcm. Ne alarm \u00e7ald\u0131 ne de drama ya\u015fand\u0131. Sadece, hi\u00e7bir zaman o stres i\u00e7in derecelendirilmemi\u015f bir kal\u0131p setinin yava\u015f yava\u015f gerilme alt\u0131nda akmas\u0131.<\/p>\n\n\n\n Ve unutma \u2014 tak\u0131m kataloglar\u0131 maksimum y\u00fck\u00fc genellikle ayak ba\u015f\u0131na ton cinsinden listeler. Bazen k\u0131sa ton olarak, bazen metrik ton olarak. Biri 2.000 libre. Di\u011feri de\u011fil. Bunlar\u0131 kar\u0131\u015ft\u0131r\u0131rsan, g\u00fcvenlik marj\u0131n buhar olur.<\/p>\n\n\n\n K\u00fc\u00e7\u00fcltmek V-KALIP A\u00c7ILI\u015eI<\/strong> malzeme kal\u0131nl\u0131\u011f\u0131n\u0131 de\u011fi\u015ftirmeden bir presi a\u015f\u0131r\u0131 y\u00fcklemenin en h\u0131zl\u0131 yoludur.<\/p>\n\n\n\n \u015eimdi insanlar\u0131 haz\u0131rl\u0131ks\u0131z yakalayan konuya geldik.<\/p>\n\n\n\n Ayn\u0131 plakay\u0131 al. Ayn\u0131 KALINLIK<\/strong>. Ayn\u0131 \u00c7EKME MUKAVEMET\u0130<\/strong>. Ayn\u0131 KALIP A\u00c7IKLI\u011eI<\/strong>.<\/p>\n\n\n\n Hava ile b\u00fck, ve malzeme yaln\u0131zca z\u0131mba ucu ve kal\u0131p omuzlar\u0131na temas eder. \u00dc\u00e7 nokta. S\u0131n\u0131rl\u0131 temas alan\u0131. Kontroll\u00fc kuvvet.<\/p>\n\n\n\n \u015eimdi tabanla. Malzemeyi kal\u0131p duvarlar\u0131yla tam temas edecek \u015fekilde zorla. Temas alan\u0131 artar. S\u00fcrt\u00fcnme artar. Gerekli kuvvet s\u0131\u00e7rar \u2014 genellikle hava b\u00fckme tonaj\u0131n\u0131n 3\u00d7 ila 4\u00d7\u2019\u00fc kadar.<\/p>\n\n\n\n Bask\u0131lama m\u0131? Art\u0131k sadece b\u00fckm\u00fcyorsun. Geri yaylanmay\u0131 ortadan kald\u0131rmak i\u00e7in b\u00fckme hatt\u0131ndaki malzemeyi s\u0131k\u0131\u015ft\u0131r\u0131yorsun. Bu, kuvveti hava b\u00fckme gereksiniminin 5\u00d7 ila 8\u00d7\u2019ine kadar \u00e7\u0131karabilir.<\/p>\n\n\n\n Ayn\u0131 \u00e7izim. Tamamen farkl\u0131 y\u00fck durumu.<\/p>\n\n\n\n Bir ekibin, a\u00e7\u0131 tutarl\u0131l\u0131\u011f\u0131n\u0131 yakalamak i\u00e7in \u00fcretim ortas\u0131nda hava b\u00fckmeden tabanlamaya ge\u00e7ti\u011fini izlemi\u015ftim. Tonaj\u0131 yeniden hesaplamad\u0131lar. Makine patlamad\u0131. Sadece y\u00fck alt\u0131nda paralellikten yava\u015f\u00e7a sapmaya ba\u015flad\u0131, haftalarca takip etti\u011fimiz ince bir \u00e7er\u00e7eve sapmas\u0131 \u2014 sonunda hidroliklerden de\u011fil, y\u00f6ntemden kaynakland\u0131\u011f\u0131n\u0131 bulduk.<\/p>\n\n\n\n Hava b\u00fckme, minimum kal\u0131p temasl\u0131 elastik-plastik deformasyondur. Tabanlama ve bask\u0131lama, ilave s\u0131k\u0131\u015ft\u0131rmal\u0131 \u015fekillendirme ve tam kal\u0131p angajman\u0131 sa\u011flar. Daha fazla diren\u00e7. Daha fazla kuvvet.<\/p>\n\n\n\n E\u011fer tonaj\u0131 belirtmeden hesaplarsan B\u00dcKME Y\u00d6NTEM\u0130<\/strong>, denklemi bitirmedin.<\/p>\n\n\n\n Ve e\u011fer denklemi bitirmediysen, say\u0131ya g\u00fcvenme hakk\u0131n\u0131 kazanmad\u0131n.<\/p>\n\n\n\n Nas\u0131l oldu\u011funu g\u00f6rd\u00fcn \u00c7EKME MUKAVEMET\u0130<\/strong>, V\u2011KALIP A\u00c7IKLI\u011eI<\/strong>, ve B\u00dcKME Y\u00d6NTEM\u0130<\/strong> bir balyoz gibi kuvveti sallayabilirsin.<\/p>\n\n\n\n \u015eimdi ger\u00e7ek hesaplamay\u0131 istiyorsun. Bir tablo de\u011fil. \u201cYeterince yak\u0131n\u201d de\u011fil. Ko\u00e7 a\u015fa\u011f\u0131 indi\u011finde savunabilece\u011fin ad\u0131m ad\u0131m bir say\u0131.<\/p>\n\n\n\n G\u00fczel. \u0130\u015fte bu \u015fekilde demiri k\u0131rmay\u0131 b\u0131rak\u0131rs\u0131n.<\/p>\n\n\n\n Herkesin kulland\u0131\u011f\u0131 standart sabit, geleneksel kal\u0131p oran\u0131nda 60.000 PSI yumu\u015fak \u00e7eli\u011fi hava b\u00fckme i\u00e7in t\u00fcretilmi\u015ftir. Bu, dolu bir tabancadaki bir ba\u015flang\u0131\u00e7 kartu\u015fudur. Kartu\u015fu de\u011fi\u015ftir, tepki de\u011fi\u015fir. \u015eimdi yapaca\u011f\u0131m\u0131z \u015fey, bu kartu\u015flar\u0131 g\u00f6r\u00fcn\u00fcr hale getiren bir form\u00fcl olu\u015fturmak \u2014 b\u00f6ylece teti\u011fe basmadan \u00f6nce haznede tam olarak ne oldu\u011funu bilirsin.<\/p>\n\n\n\n Ve evet, bunu hesaba kataca\u011f\u0131z \u00c7EKME MUKAVEMET\u0130<\/strong>, ger\u00e7ek V\u2011KALIP A\u00c7IKLI\u011eI<\/strong>, ve B\u00dcKME Y\u00d6NTEM\u0130<\/strong> a\u00e7\u0131k\u00e7a \u2014 sihirli bir say\u0131n\u0131n i\u00e7ine gizlenen varsay\u0131mlar olarak de\u011fil.<\/p>\n\n\n\n Somut bir \u015feyle ba\u015flayal\u0131m.<\/p>\n\n\n\n \u00c7eyrek in\u00e7 plaka al. 0.250 in\u00e7 kal\u0131nl\u0131k. On fit b\u00fck\u00fcm uzunlu\u011fu. \u0130ki in\u00e7lik V kal\u0131p. Hava b\u00fckme.<\/p>\n\n\n\n \u0130mparatorluk birim sisteminde hava b\u00fckme tonaj form\u00fcl\u00fc \u015f\u00f6yledir:<\/p>\n\n\n\n AYAK BA\u015eINA TON<\/strong> = (\u00c7EKME MUKAVEMET\u0130<\/strong> \u00d7 KALINLIK\u00b2<\/strong>) \u00f7 (1.33 \u00d7 V\u2011KALIP A\u00c7IKLI\u011eI<\/strong>)<\/p>\n\n\n\n O 1.33 mistik bir \u015fey de\u011fil. Kiri\u015f e\u011filme mekani\u011finden ve 60.000 PSI tabanl\u0131 \u00e7eli\u011fe dayal\u0131 birim d\u00f6n\u00fc\u015f\u00fcm\u00fcnden gelir. Bu, geometri ve gerilme da\u011f\u0131l\u0131m\u0131n\u0131n bir sabit i\u00e7inde s\u0131k\u0131\u015ft\u0131r\u0131lm\u0131\u015f halidir.<\/p>\n\n\n\n 60.000 PSI yumu\u015fak \u00e7elik i\u00e7in say\u0131lar\u0131 yerine koyun:<\/p>\n\n\n\n Yani:<\/p>\n\n\n\n AYAK BA\u015eINA TON<\/strong> = (60.000 \u00d7 0,250\u00b2) \u00f7 (1,33 \u00d7 2,0) = (60.000 \u00d7 0,0625) \u00f7 2,66 = 3.750 \u00f7 2,66 \u2248 in\u00e7 ba\u015f\u0131na 1.409 pound \u2248 ayak ba\u015f\u0131na 16,9 ton<\/p>\n\n\n\n On ayak uzun mu? \u00c7arp\u0131n:<\/p>\n\n\n\n 16,9 \u00d7 10 = toplamda 169 ton gerekli kuvvet.<\/p>\n\n\n\n Bu hava ile b\u00fckme. Bu 60.000 PSI. Bu iki in\u00e7lik kal\u0131p.<\/p>\n\n\n\n \u015eimdi hi\u00e7bir \u015feyi de\u011fi\u015ftirmeyin, sadece V\u2011KALIP A\u00c7IKLI\u011eI<\/strong> 1,5 in\u00e7'e.<\/p>\n\n\n\n Payda k\u00fc\u00e7\u00fcl\u00fcr. Kuvvet artar:<\/p>\n\n\n\n (60.000 \u00d7 0,0625) \u00f7 (1,33 \u00d7 1,5) = 3.750 \u00f7 1,995 \u2248 in\u00e7 ba\u015f\u0131na 1.879 pound \u2248 ayak ba\u015f\u0131na 22,5 ton<\/p>\n\n\n\n On ayak 225 ton olur.<\/p>\n\n\n\n Ayn\u0131 malzeme. Ayn\u0131 kal\u0131nl\u0131k. Ayn\u0131 uzunluk. Yar\u0131m in\u00e7lik kal\u0131p de\u011fi\u015fimi. Tezg\u00e2h boyunca fazladan 56 ton y\u00fck.<\/p>\n\n\n\n Bu bir tablo hatas\u0131 de\u011fil. Bu kald\u0131ra\u00e7 mekani\u011fi \u2014 a\u00e7\u0131kl\u0131k azald\u0131k\u00e7a b\u00fckme momentinin artmas\u0131d\u0131r.<\/p>\n\n\n\n Bir keresinde bir at\u00f6lyenin tam olarak bu hamleyi 175 tonluk bir pres frende denedi\u011fini izledim. Hesap 225 ton diyordu. Etiket 175 diyordu. Yine de \u00e7al\u0131\u015ft\u0131rd\u0131lar, merkez yak\u0131n\u0131ndaki k\u0131sa bir b\u00f6l\u00fcm i\u00e7in. Ram kal\u0131c\u0131 olarak bombe yapt\u0131. Dramatik de\u011fildi. Sadece bundan sonra yap\u0131lan her uzun b\u00fckmede a\u00e7\u0131 bir u\u00e7tan di\u011ferine kayacak kadar. O makineyi bir daha asla d\u00fcz hale getiremedik.<\/p>\n\n\n\n Ve hen\u00fcz paslanmaz \u00e7elik veya alt b\u00fckmeyi bile konu\u015fmad\u0131k.<\/p>\n\n\n\n Ba\u015fka bir \u015feye dikkat edin: bu form\u00fcl gereken kuvveti verir. Ancak 175 ton \u00d7 10 ayakl\u0131k makinenizin tam on ayak boyunca g\u00fcvenli bir \u015fekilde 169 ton verebilece\u011fini mi, yoksa sadece merkeze yak\u0131n m\u0131 verebilece\u011fini s\u00f6ylemez. Makine derecelendirmesi ve kuvvet ihtiyac\u0131 farkl\u0131 problemlerdir. Say\u0131ya g\u00fcvenmeden \u00f6nce, pres frenenizin y\u00fck\u00fc nas\u0131l da\u011f\u0131tt\u0131\u011f\u0131n\u0131, CNC bombe dengeleme sisteminin gerilim alt\u0131nda nas\u0131l telafi etti\u011fini ve yap\u0131s\u0131n\u0131n tam uzunlukta tutarl\u0131 b\u00fckme i\u00e7in tasarlan\u0131p tasarlanmad\u0131\u011f\u0131n\u0131 bilmeniz gerekir. Modern 100% CNC platformlar\u0131 gibi CN-HAWE abkant pres<\/a> b\u00fckmede y\u00fcksek hassasiyet ve ger\u00e7ek d\u00fcnya y\u00fck kontrol\u00fc i\u00e7in tasarlanm\u0131\u015ft\u0131r; pres frene ve otomasyon sistemleri genelinde s\u00fcrekli Ar-Ge ve testlerle desteklenir\u2014b\u00f6ylece hesaplanan tonaj istikrarl\u0131, tekrarlanabilir makine performans\u0131yla e\u015fle\u015ftirilebilir.<\/p>\n\n\n\n \u00d6nce gerekli kuvveti hesaplay\u0131n. Sonra ger\u00e7ek makine da\u011f\u0131t\u0131m s\u0131n\u0131rlar\u0131yla kar\u015f\u0131la\u015ft\u0131r\u0131n.<\/p>\n\n\n\n \u015eimdi insanlar\u0131n kendilerine sessizce nas\u0131l yalan s\u00f6ylediklerinden bahsedelim.<\/p>\n\n\n\n Metrik sistemde ayn\u0131 hava b\u00fckme ili\u015fkisi \u015f\u00f6yle g\u00f6r\u00fcn\u00fcr:<\/p>\n\n\n\n kN metre ba\u015f\u0131na<\/strong> = (1,42 \u00d7 \u00c7EKME MUKAVEMET\u0130 (MPa)<\/strong> \u00d7 KALINLIK\u00b2 (mm)<\/strong>) \u00f7 V\u2011KALIP A\u011eZI (mm)<\/strong><\/p>\n\n\n\n Bu 1,42 de\u011feri, d\u00f6n\u00fc\u015ft\u00fcrmeler zaten g\u00f6m\u00fcl\u00fc oldu\u011fu i\u00e7in emperyal 1,33\u2019\u00fcn yerini al\u0131r. Farkl\u0131 kaplama. Ayn\u0131 fizik.<\/p>\n\n\n\n \u0130\u015fletmelerin yand\u0131\u011f\u0131 yer buras\u0131: biri MPa ile in\u00e7leri kar\u0131\u015ft\u0131r\u0131r. Ya da mm ile PSI\u2019y\u0131. Ya da tonlar\u0131 metrik tonlara d\u00f6n\u00fc\u015ft\u00fcr\u00fcr ama tak\u0131m de\u011ferinin k\u0131sa ton (2.000 lb) mu yoksa metrik ton (2.204 lb) mu oldu\u011funu kontrol etmez.<\/p>\n\n\n\n \u0130ki bin ile 2.204 \u00e7ok farkl\u0131 gelmeyebilir. farkt\u0131r. 200 tonluk bir y\u00fckte bu, 20 tonluk bir \u201ceyvah\u201d demektir.\u201d<\/p>\n\n\n\n Metre ba\u015f\u0131na 150 metrik ton i\u00e7in damgalanm\u0131\u015f bir kal\u0131b\u0131n, ayak ba\u015f\u0131na 150 k\u0131sa ton olarak i\u015flendi\u011fini g\u00f6rd\u00fcm. Bu bir yuvarlama hatas\u0131 de\u011fildir. Bu, tak\u0131m\u0131 kilometrelerce a\u015fmak demektir. Omuzlar \u00fc\u00e7\u00fcnc\u00fc vuru\u015fta \u00e7atlad\u0131.<\/p>\n\n\n\n Birimler basit muhasebe de\u011fildir. Yanl\u0131\u015f kulland\u0131\u011f\u0131n\u0131zda kuvvet \u00e7arpan\u0131na d\u00f6n\u00fc\u015f\u00fcrler.<\/p>\n\n\n\n Kural \u015fu: birim sistemini se\u00e7 ve \u00c7EKME MUKAVEMET\u0130<\/strong> nihai tonaja kadar onun i\u00e7inde kal. Gerekirse yaln\u0131zca sonunda bir kez d\u00f6n\u00fc\u015ft\u00fcr.<\/p>\n\n\n\n \u015eimdi farkl\u0131 bir kartu\u015f y\u00fckl\u00fcyoruz.<\/p>\n\n\n\n \u00c7eyrek in\u00e7lik sac\u0131n\u0131z\u0131n 60.000 PSI yumu\u015fak \u00e7elik olmad\u0131\u011f\u0131n\u0131, 90.000 PSI paslanmaz oldu\u011funu varsayal\u0131m.<\/p>\n\n\n\n D\u00fczeltmenin temiz yolu \u015fu \u015fekildedir:<\/p>\n\n\n\n MALZEME D\u00dcZELTME FAKT\u00d6R\u00dc (MCF)<\/strong> = GER\u00c7EK \u00c7EKME MUKAVEMET\u0130<\/strong> \u00f7 60.000<\/p>\n\n\n\n Yani:<\/p>\n\n\n\n MCF<\/strong> = 90.000 \u00f7 60.000 = 1,5<\/p>\n\n\n\n \u201cBiraz daha ekleme\u201d yapmazs\u0131n\u0131z. T\u00fcm hava b\u00fckme sonucunu 1,5 ile \u00e7arpars\u0131n\u0131z.<\/p>\n\n\n\n \u00d6nceki 1,5 in\u00e7 kal\u0131p \u00fczerindeki 22,5 ton\/ayak \u00f6rne\u011fimizi ele alal\u0131m:<\/p>\n\n\n\n 22,5 \u00d7 1,5 = 33,75 ton\/ayak.<\/p>\n\n\n\n On ayak?<\/p>\n\n\n\n 337,5 ton gerekir.<\/p>\n\n\n\n \u0130\u015fte, yumu\u015fak \u00e7elikte 169 ton gibi g\u00f6r\u00fcnen bir kurulumun, daha dar bir kal\u0131pla paslanmaz \u00e7elikte sessizce 300 tonun \u00fczerine \u00e7\u0131kmas\u0131n\u0131n nedeni bu.<\/p>\n\n\n\n \u015eimdi y\u00f6ntemi bunun \u00fczerine ekleyelim.<\/p>\n\n\n\n Hava b\u00fckme \u00e7arpan\u0131 = 1,0 Alt kal\u0131ba oturtma (bottoming) hava b\u00fckmeden 4\u20135\u00d7 daha fazla olabilir. Darp kal\u0131plama (coining) 8\u201310\u00d7 seviyesine ula\u015fabilir.<\/p>\n\n\n\n E\u011fer o paslanmaz i\u015fi 4\u00d7 oran\u0131nda alt kal\u0131ba oturtursan\u0131z:<\/p>\n\n\n\n 337,5 \u00d7 4 = 1.350 ton.<\/p>\n\n\n\n Ayn\u0131 \u00e7izim. Ayn\u0131 kal\u0131nl\u0131k. Ayn\u0131 uzunluk.<\/p>\n\n\n\n Farkl\u0131 fizik.<\/p>\n\n\n\n Form\u00fcllerin \u00e7o\u011funun gizledi\u011fi k\u0131s\u0131m \u015fudur: MCF<\/strong> \u00e7izgisel olarak \u00e7ekme dayan\u0131m\u0131yla \u00f6l\u00e7eklendi\u011fini varsayar. Normal pres freni aral\u0131klar\u0131ndaki \u00e7o\u011fu yap\u0131sal \u00e7elik i\u00e7in bu yeterince do\u011frudur. Ancak \u00e7al\u0131\u015fma sertle\u015fmesi y\u00fcksek ala\u015f\u0131mlar, strokun sonuna yak\u0131n noktada y\u00fckte ani art\u0131\u015fa neden olabilir. Bu art\u0131\u015f temel sabitte yer almaz. \u0130\u015fte bu noktada operat\u00f6r\u00fcn yarg\u0131s\u0131 ve ger\u00e7ek zamanl\u0131 y\u00fck izleme \u00f6nem kazan\u0131r.<\/p>\n\n\n\n Bir keresinde y\u00fcksek mukavemetli plakada yeniden hesaplama yapmadan \u201cbir deneyelim\u201d diyen bir ekibi izlemi\u015ftim MCF<\/strong>. Pres programlanan derinli\u011fe ula\u015fmadan \u00f6nce tepe bas\u0131nca ula\u015ft\u0131. Tahliye valfi \u00e7\u0131\u011fl\u0131k att\u0131. Kal\u0131p kurtuldu. Hidrolik contalar kurtulmad\u0131.<\/p>\n\n\n\n Birle\u015ftirilmi\u015f bir form\u00fcl riski ortadan kald\u0131rmaz. Onu g\u00f6r\u00fcn\u00fcr k\u0131lar. \u015eunu anlaman\u0131z\u0131 sa\u011flar:<\/p>\n\n\n\n Gerekli Kuvvet = (Geometriden gelen Temel Hava B\u00fckme Kuvveti) \u00d7 MCF<\/strong> \u00d7 Y\u00d6NTEM \u00c7ARPANI<\/strong><\/p>\n\n\n\n Ancak bundan sonra kar\u015f\u0131la\u015ft\u0131rma yapars\u0131n\u0131z:<\/p>\n\n\n\n Bu, teti\u011fe basmadan \u00f6nce yap\u0131lan tam hazne kontrol\u00fcd\u00fcr.<\/p>\n\n\n\n Sonra, bu birle\u015ftirilmi\u015f hesab\u0131 ger\u00e7ek at\u00f6lye senaryolar\u0131nda \u00e7al\u0131\u015ft\u0131raca\u011f\u0131z \u2014 ve k\u00fc\u00e7\u00fck de\u011fi\u015fkenlerin ne kadar h\u0131zl\u0131 bir \u015fekilde makineyi \u00f6ld\u00fcrecek y\u00fcklere d\u00f6n\u00fc\u015ft\u00fc\u011f\u00fcn\u00fc, sezgilerinizin bekledi\u011finden daha h\u0131zl\u0131 g\u00f6receksiniz.<\/p>\n\n\n\n K\u00fc\u00e7\u00fck de\u011fi\u015fikliklerin makineyi \u00f6ld\u00fcrecek y\u00fcke ne kadar h\u0131zl\u0131 d\u00f6n\u00fc\u015ft\u00fc\u011f\u00fcn\u00fc bilmek mi istiyorsunuz?<\/p>\n\n\n\n G\u00fczel. Bu do\u011fru soru.<\/p>\n\n\n\n Birle\u015ftirilmi\u015f denklemi zaten olu\u015fturduk \u2014 geometriden gelen temel hava b\u00fck\u00fcm kuvveti, \u00e7arp\u0131 MALZEME D\u00dcZELTME FAKT\u00d6R\u00dc<\/strong>, ile \u00e7arp\u0131l\u0131r, Y\u00d6NTEM \u00c7ARPANI<\/strong>. \u015eimdi bunu ger\u00e7ek i\u015flerde deneyece\u011fiz \u2014 m\u00fc\u015fterinin \u201cyar\u0131na laz\u0131m\u201d dedi\u011fi per\u015fembe g\u00fcn\u00fc saat 2:30\u2019da masan\u0131za d\u00fc\u015fen t\u00fcrden i\u015flerde.\u201d<\/p>\n\n\n\n Ayn\u0131 geometrisiyle. \u015eimdi her seferinde bir de\u011fi\u015fkeni de\u011fi\u015ftirdi\u011fimizde neler oldu\u011funa bak\u0131n.<\/p>\n\n\n\n 10 numara yumu\u015fak \u00e7elikten bir braket d\u00fc\u015f\u00fcn\u00fcn. Kal\u0131nl\u0131k 0.135 in\u00e7. B\u00fck\u00fcm uzunlu\u011fu 48 in\u00e7. 8\u00d7 bir kal\u0131p se\u00e7iyorsunuz, b\u00f6ylece V\u2011KALIP A\u00c7IKLI\u011eI<\/strong> yakla\u015f\u0131k 1.08 in\u00e7 oluyor. Matemati\u011fi sade ve biraz temkinli tutmak i\u00e7in 1.0 in\u00e7 olarak alaca\u011f\u0131z.<\/p>\n\n\n\n Malzeme temel yumu\u015fak \u00e7elik: \u00c7EKME MUKAVEMET\u0130 = 60.000 PSI<\/strong>.<\/p>\n\n\n\n Hava b\u00fck\u00fcm\u00fc. Hilesiz.<\/p>\n\n\n\n Form\u00fclle ba\u015fla:<\/p>\n\n\n\n AYAK BA\u015eINA TON<\/strong> = (\u00c7EKME MUKAVEMET\u0130 \u00d7 KALINLIK\u00b2<\/strong>) \u00f7 (1.33 \u00d7 V\u2011KALIP A\u00c7IKLI\u011eI<\/strong>)<\/p>\n\n\n\n Yani:<\/p>\n\n\n\n Ayak ba\u015f\u0131na tona d\u00f6n\u00fc\u015ft\u00fcr:<\/p>\n\n\n\n 821 lb\/in \u00d7 12 in \u2248 9.852 lb\/ft \u2248 ayak ba\u015f\u0131na 4.9 ton.<\/p>\n\n\n\n Par\u00e7an 4 feet uzunlu\u011funda:<\/p>\n\n\n\n 4.9 \u00d7 4 = toplam 19.6 ton.<\/p>\n\n\n\n Gerekli kuvvet 20 ton diyelim.<\/p>\n\n\n\n Bu s\u0131k\u0131c\u0131. Bu g\u00fcvenli. Tablolar\u0131n \u00fczerine in\u015fa edildi\u011fi \u015fey budur \u2014 hava b\u00fckme, yumu\u015fak \u00e7elik, \u201cnormal\u201d kal\u0131p oran\u0131.<\/p>\n\n\n\n Ve i\u015fte \u00e7\u0131raklar\u0131n kendilerine fazla g\u00fcvenmeye ba\u015flad\u0131klar\u0131 yer buras\u0131.<\/p>\n\n\n\n Bir keresinde gen\u00e7 bir \u00e7ocuk b\u00f6yle 25 tonluk bir sonucu g\u00f6r\u00fcp \u201cBunu binadaki herhangi bir makinede \u00e7al\u0131\u015ft\u0131rabiliriz,\u201d dedi. \u0130ki saat sonra eski bir mekanik presin yata\u011f\u0131n\u0131n kenar\u0131nda benzer bir 10 numara i\u015f denedi. Merkezden uzak y\u00fckleme, ko\u00e7u biraz b\u00fckt\u00fc ve z\u0131mba ucunu \u00e7atlatmaya yetti. Ucuz bir ders. Daha k\u00f6t\u00fc olabilirdi.<\/p>\n\n\n\n Temel i\u015fler seni form\u00fcl\u00fcn evrensel oldu\u011funa inand\u0131r\u0131r.<\/p>\n\n\n\n \u00d6yle de\u011fildir.<\/p>\n\n\n\n Ayn\u0131 \u00e7izim. Ayn\u0131 48 in\u00e7 b\u00fck\u00fcm. Ayn\u0131 0.135 kal\u0131nl\u0131k.<\/p>\n\n\n\n \u015eimdi m\u00fc\u015fteri 304 paslanmaz \u00e7eli\u011fe ge\u00e7iyor. Tipik \u00c7EKME MUKAVEMET\u0130<\/strong>? Yakla\u015f\u0131k 90.000 PSI.<\/p>\n\n\n\n Ve operat\u00f6r, 0.75 in\u00e7lik bir kal\u0131pla \u201cyar\u0131\u00e7ap\u0131 s\u0131k\u0131la\u015ft\u0131rmaya\u201d karar veriyor. V\u2011KALIP A\u00c7IKLI\u011eI<\/strong> 1.0 yerine.<\/p>\n\n\n\n \u0130ki de\u011fi\u015fken de\u011fi\u015fti. Y\u0131\u011f\u0131na dikkat et.<\/p>\n\n\n\n \u00d6nce, yeni kal\u0131pla geometri:<\/p>\n\n\n\n D\u00f6n\u00fc\u015ft\u00fcr:<\/p>\n\n\n\n 1.642 \u00d7 12 \u2248 19.704 lb\/ft \u2248 ayak ba\u015f\u0131na 9.85 ton.<\/p>\n\n\n\n D\u00f6rt ayak uzunlu\u011funda:<\/p>\n\n\n\n 9.85 \u00d7 4 \u2248 39.4 ton.<\/p>\n\n\n\n \u201c20 tonluk i\u015f\u201d bir anda 40 tonluk i\u015fe d\u00f6n\u00fc\u015ft\u00fc.<\/p>\n\n\n\n Hi\u00e7 ola\u011fand\u0131\u015f\u0131 bir \u015fey olmad\u0131. Kal\u0131nl\u0131\u011f\u0131 ikiye katlamad\u0131k. Uzunlu\u011fu de\u011fi\u015ftirmedik. \u015eunu art\u0131rd\u0131k: \u00c7EKME MUKAVEMET\u0130<\/strong> 1.5\u00d7 kadar ve k\u00fc\u00e7\u00fcltt\u00fck V\u2011KALIP A\u00c7IKLI\u011eI<\/strong> oran\u0131nda.<\/p>\n\n\n\n Kuvvet ikiye katland\u0131.<\/p>\n\n\n\n Bu tam olarak bir at\u00f6lyenin nas\u0131l u\u00e7uruma y\u00fcr\u00fcd\u00fc\u011f\u00fcn\u00fcn \u00f6rne\u011fi. \u201cYar\u0131\u00e7ap\u0131 keskinle\u015ftirmek\u201d i\u00e7in biri daha dar bir kal\u0131ba ge\u00e7ti\u011fi i\u00e7in 90 tonluk bir i\u015fin 130 tonluk bir ger\u00e7e\u011fe d\u00f6n\u00fc\u015ft\u00fc\u011f\u00fcn\u00fc g\u00f6rd\u00fcm. Makine \u015fik\u00e2yet etmedi. Tak\u0131m yapt\u0131. \u00dc\u00e7 hafta sonra daha a\u011f\u0131r bir \u00e7al\u0131\u015fmada kal\u0131p omuzlar\u0131nda ortaya \u00e7\u0131kan k\u0131lcal \u00e7atlaklar.<\/p>\n\n\n\n \u201cAma 575 bir fizik yasas\u0131 de\u011fil.\u201d<\/p>\n\n\n\n Hay\u0131r. Bu, yumu\u015fak \u00e7elik ve geni\u015f kal\u0131plar \u00fczerine kurulmu\u015f bir kestirme yoldur. Bunlardan birini de\u011fi\u015ftirirsen, kald\u0131ra\u00e7 kolu de\u011fi\u015fir. E\u011filme momenti artar \u00e7\u00fcnk\u00fc a\u00e7\u0131kl\u0131\u011f\u0131 k\u0131salt\u0131rken ayn\u0131 anda malzeme direncini art\u0131rm\u0131\u015f olursun.<\/p>\n\n\n\n \u015eimdi 20 ton yerine 40 tona bak\u0131yorsun.<\/p>\n\n\n\n H\u00e2l\u00e2 rahat m\u0131s\u0131n?<\/p>\n\n\n\n Yukar\u0131daki paslanmaz \u00e7elik kurulumda kalal\u0131m: 0,135 kal\u0131nl\u0131k, 48 in\u00e7 uzunluk, 0,75 in\u00e7 kal\u0131p, \u00c7EKME MUKAVEMET\u0130 = 90.000 PSI<\/strong>.<\/p>\n\n\n\n Hava b\u00fckmede toplamda yakla\u015f\u0131k 40 ton gerekiyordu.<\/p>\n\n\n\n \u015eimdi y\u00f6ntemi de\u011fi\u015ftir.<\/p>\n\n\n\n Alt b\u00fckme \u2014 yani punc\u0131n, malzemeyi kal\u0131p a\u00e7\u0131s\u0131yla tam temasa zorlad\u0131\u011f\u0131 i\u015flem \u2014 ayn\u0131 geometrik yap\u0131 i\u00e7in genellikle hava b\u00fckme kuvvetinin en az 2 kat\u0131n\u0131 gerektirir. Bu bir g\u00f6r\u00fc\u015f de\u011fil. Bu, malzemenin elastik geri kazan\u0131m\u0131 a\u015farak kal\u0131p duvarlar\u0131na plastik olarak uydurulmas\u0131d\u0131r.<\/p>\n\n\n\n Yani:<\/p>\n\n\n\n 40 ton \u00d7 2 = 80 ton.<\/p>\n\n\n\n Asgari.<\/p>\n\n\n\n Baz\u0131 malzemeler, \u00f6zellikle i\u015f sertle\u015fmesi yapan paslanmaz \u00e7elikler, strokun alt\u0131na yakla\u015f\u0131rken h\u0131zla artan temas alan\u0131 ve s\u00fcrt\u00fcnme nedeniyle bu de\u011ferin \u00f6tesine \u00e7\u0131kar. Y\u00fck e\u011frin, alt k\u0131sma yakla\u015ft\u0131k\u00e7a dikle\u015fir \u2014 tam da makinelerin en y\u00fcksek hidrolik bas\u0131nc\u0131 g\u00f6rd\u00fc\u011f\u00fc yerde.<\/p>\n\n\n\n Yumu\u015fak \u00e7elikte hava b\u00fckmede 20 ton gibi rahat g\u00f6r\u00fcnen i\u015f, \u015fimdi 80 tonluk paslanmaz alt b\u00fckme i\u015flemi oluyor.<\/p>\n\n\n\n Temelin d\u00f6rt kat\u0131.<\/p>\n\n\n\n Ayn\u0131 \u00e7izim.<\/p>\n\n\n\n Bir ekibin, 60 tonluk bir pres frende 50 tonluk paslanmaz i\u015f yapt\u0131klar\u0131n\u0131 sanarak alt b\u00fckme yapt\u0131klar\u0131n\u0131 izledim. Hava b\u00fckme hesab\u0131 do\u011fruydu. Ancak unuttular Y\u00d6NTEM \u00c7ARPANI<\/strong>. Makine strokun ortas\u0131nda emniyet bas\u0131nc\u0131na ula\u015ft\u0131 ve durdu. Tekrar denediler. Kal\u0131p hayatta kald\u0131. Ancak ko\u00e7 k\u0131lavuz bo\u015fluklar\u0131 kalmad\u0131. O fren bir daha asla do\u011fru izde \u00e7al\u0131\u015fmad\u0131.<\/p>\n\n\n\n G\u00f6rmen gereken model \u015fu:<\/p>\n\n\n\n Bunlar k\u00fc\u00e7\u00fck d\u00fczeltmeler de\u011fil. Birbirlerini katlad\u0131k\u00e7a b\u00fcy\u00fcrler.<\/p>\n\n\n\n Ve makine tablodakinin ne s\u00f6yledi\u011fiyle ilgilenmez. Yatak boyunca uygulanan kuvveti hisseder \u2014 da\u011f\u0131t\u0131lm\u0131\u015f, yo\u011funla\u015fm\u0131\u015f, merkez d\u0131\u015f\u0131, ne verirsen onu.<\/p>\n\n\n\n Yani bir bask\u0131 malzeme de\u011fi\u015ftirdi\u011finde, biri daha s\u0131k\u0131 bir kal\u0131p ald\u0131\u011f\u0131nda veya \u00fcretim \u201ca\u00e7\u0131y\u0131 sabitlemek\u201d i\u00e7in hava b\u00fckme yerine tabana inmeye karar verdi\u011finde, tahmin etmezsin.<\/p>\n\n\n\n Y\u00fck\u00fc s\u0131f\u0131rdan yeniden kurars\u0131n. Sonra bunu tam o b\u00fckme uzunlu\u011fu boyunca ger\u00e7ek makine kapasitesi ile kar\u015f\u0131la\u015ft\u0131r\u0131rs\u0131n \u2014 isim plakas\u0131ndaki hayalle de\u011fil.<\/p>\n\n\n\n \u00c7\u00fcnk\u00fc form\u00fcl dolu bir silaht\u0131r. Namludaki \u015feyin ne oldu\u011funu tam olarak biliyorsan g\u00fcvenlidir.<\/p>\n\n\n\n Her kartu\u015fun ayn\u0131 oldu\u011funu varsayd\u0131\u011f\u0131nda \u00f6l\u00fcmc\u00fcl olur.<\/p>\n\n\n\n Hesaplar\u0131 yapt\u0131n. Ayarlad\u0131n \u00c7EKME MUKAVEMET\u0130<\/strong>, s\u0131k\u0131la\u015ft\u0131rd\u0131n V\u2011KALIP A\u00c7IKLI\u011eI<\/strong>, taban b\u00fckme i\u00e7in \u00e7arpt\u0131n. Hesap makinesi 80 ton diyor.<\/p>\n\n\n\n Peki 100 tonluk presinin 6 fit boyunca kendini hurdaya \u00e7evirmeden o y\u00fck\u00fc ger\u00e7ekten kald\u0131rabilece\u011fini nas\u0131l bilirsin?<\/p>\n\n\n\n CN-HAWE\u2019nin \u00fcr\u00fcn portf\u00f6y\u00fcn\u00fcn 100% CNC tabanl\u0131 oldu\u011funu ve lazer kesim, b\u00fckme, kanal a\u00e7ma, kesme gibi \u00fcst d\u00fczey senaryolar\u0131 kapsad\u0131\u011f\u0131n\u0131 g\u00f6z \u00f6n\u00fcnde bulundurarak, bir sonraki ad\u0131m do\u011frudan ekiple ileti\u015fime ge\u00e7mekse, Bize ula\u015f\u0131n<\/a> buraya do\u011fal \u015fekilde oturur.<\/p>\n\n\n\n \u0130\u015fte kimsenin tabloya koymad\u0131\u011f\u0131 k\u0131s\u0131m: form\u00fcl m\u00fckemmel tak\u0131m, m\u00fckemmel da\u011f\u0131lm\u0131\u015f y\u00fck ve m\u00fckemmel davranan malzeme varsayar. Bu bir fantezidir. Ger\u00e7ek at\u00f6lyelerde a\u015f\u0131nm\u0131\u015f kal\u0131plar, merkez d\u0131\u015f\u0131 par\u00e7alar, kar\u0131\u015f\u0131k tane y\u00f6nl\u00fc levhalar ve yaln\u0131zca yata\u011f\u0131n bir k\u0131sm\u0131 boyunca tam nominal kapasiteyi sa\u011flayan makineler \u00e7al\u0131\u015f\u0131r. 175 ton \u00d7 10 fitlik bir pres her yerde 175 ton de\u011fildir; o tam kuvveti t\u00fcm yatak boyunca uygularsan, y\u00fck\u00fcn nas\u0131l da\u011f\u0131ld\u0131\u011f\u0131n\u0131 anlamad\u0131\u011f\u0131n s\u00fcrece g\u00f6vdeyi bombe yapars\u0131n.<\/p>\n\n\n\n Matematik sana bir say\u0131 verir. Makine bir desen hisseder.<\/p>\n\n\n\n \u0130\u015fte o bo\u015flukta tak\u0131mlar par\u00e7alan\u0131r.<\/p>\n\n\n\n Bir keresinde bir ekibin, \u201cyer vard\u0131\u201d diye uzun yata\u011f\u0131n uzak ucuna yak\u0131n \u00e7eyrek in\u00e7lik plakay\u0131 b\u00fckt\u00fc\u011f\u00fcn\u00fc izledim. Hesaplanan AYAK BA\u015eINA TON<\/strong> uygundu. Sayg\u0131 duymad\u0131klar\u0131 \u015fey, tam nominal tonaj\u0131n o yatak uzunlu\u011funun yaln\u0131zca yakla\u015f\u0131k \u2019\u0131 boyunca g\u00fcvenli oldu\u011fuydu. G\u00f6vde bi\u00e7im de\u011fi\u015ftirdi. Kal\u0131c\u0131 bombe. O pres, takozlar ve dualar olmadan bir daha asla paralel \u00e7al\u0131\u015fmad\u0131.<\/p>\n\n\n\n Keskin bir kal\u0131p omzu, kuvveti temiz bir temas \u00e7izgisi boyunca yo\u011funla\u015ft\u0131r\u0131r. Denklem tam da bunu varsayar.<\/p>\n\n\n\n \u015eimdi binlerce kez paslanmaz \u00e7elikte \u00e7al\u0131\u015ft\u0131r\u0131lm\u0131\u015f bir kal\u0131b\u0131 hayal et. Bir zamanlar keskin olan yar\u0131\u00e7ap KALIP OMUZLARI<\/strong> d\u00fczle\u015fmi\u015ftir. Dar bir temas \u00e7izgisi yerine bula\u015fm\u0131\u015f bir temas alan\u0131n\u0131z vard\u0131r. Daha fazla y\u00fczey alan\u0131. Daha fazla s\u00fcrt\u00fcnme. Malzeme ak\u0131\u015f\u0131na daha fazla diren\u00e7.<\/p>\n\n\n\n Kuvvet artar.<\/p>\n\n\n\n Sebebi \u00c7EKME MUKAVEMET\u0130<\/strong> de\u011fi\u015fmesi de\u011fil. KALINLIK<\/strong> de\u011fi\u015fmesi de\u011fil. S\u00fcrt\u00fcnme ve temas geometrisi de\u011fi\u015fti, ve senin form\u00fcl\u00fcnde \u201cy\u0131pranm\u0131\u015f tak\u0131m\u201d i\u00e7in bir alan yok.\u201d<\/p>\n\n\n\n Varsay\u0131msal olarak \u2014 ve bunu bir laboratuvar \u00e7al\u0131\u015fmas\u0131 de\u011fil, bir at\u00f6lye tahmini olarak belirtiyorum \u2014 yeni, hassas ta\u015flanm\u0131\u015f kal\u0131plardan yorgun \u00fcretim kal\u0131plar\u0131na ge\u00e7ildi\u011finde ayn\u0131 i\u015fin yakla\u015f\u0131k \u201330 oran\u0131nda daha fazla kuvvet gerektirdi\u011fini hissetti\u011fim durumlar g\u00f6rd\u00fcm. Presin sesi de\u011fi\u015fiyor. Hidrolik bas\u0131n\u00e7 vuru\u015fun alt k\u0131sm\u0131na yakla\u015f\u0131rken yava\u015f\u00e7a art\u0131yor. A\u00e7\u0131 inatla oturuyor.<\/p>\n\n\n\n Hesap makinesi h\u00e2l\u00e2 40 ton diyor.<\/p>\n\n\n\n Makine ise ba\u015fka \u015fey s\u00f6yl\u00fcyor.<\/p>\n\n\n\n Temiz matemati\u011fe kirli \u00e7eli\u011fe g\u00fcvenmek yerine g\u00fcvendi\u011fim i\u00e7in 14.000\u2019lik bir hassas kal\u0131p setini mahvettim. Say\u0131lar do\u011fruydu. Tak\u0131m do\u011fru de\u011fildi. Mikro \u00e7atlaklar a\u015f\u0131nm\u0131\u015f omuzdan ba\u015flay\u0131p daha a\u011f\u0131r bir takip i\u015finde \u00f6r\u00fcmcek a\u011f\u0131 gibi yay\u0131ld\u0131. Bunu, bir k\u00f6\u015fe b\u00fck\u00fcm ortas\u0131nda k\u0131r\u0131l\u0131p m\u00fc\u015fterinin par\u00e7as\u0131n\u0131 \u00e7izdi\u011finde fark ettik.<\/p>\n\n\n\n A\u015f\u0131nmay\u0131 d\u00fczg\u00fcn bir KALINLIK\u00b2<\/strong> terime dahil edemezsin. \u00d6n\u00fcndeki metale bakmal\u0131 ve neler ya\u015fad\u0131\u011f\u0131n\u0131 sormal\u0131s\u0131n.<\/p>\n\n\n\n Toplam tonaj hikayenin yaln\u0131zca yar\u0131s\u0131d\u0131r.<\/p>\n\n\n\n Abkant presler uzunluk boyunca ton cinsinden derecelendirilir \u2014 foot ba\u015f\u0131na ton, metre ba\u015f\u0131na ton. Bu derecelendirme y\u00fck da\u011f\u0131l\u0131m\u0131n\u0131 varsayar. Y\u00fck\u00fc e\u015fit yayarsan, g\u00f6vde onu t\u0131pk\u0131 bir k\u00f6pr\u00fcn\u00fcn trafi\u011fi ta\u015f\u0131d\u0131\u011f\u0131 gibi ta\u015f\u0131r.<\/p>\n\n\n\n \u015eimdi yata\u011f\u0131n bir ucuna yak\u0131n, keskin, k\u00fc\u00e7\u00fck yar\u0131\u00e7apl\u0131 bir z\u0131mba alt\u0131na dar bir par\u00e7a koy.<\/p>\n\n\n\n Toplam MEVCUT TONAJI<\/strong>. a\u015fmad\u0131n. Ama AYAK BA\u015eINA TON<\/strong> y\u00fck\u00fc k\u0131sa bir b\u00f6l\u00fcmde s\u0131\u00e7ratt\u0131n ve merkezi kayd\u0131rd\u0131n. Ko\u00e7 ve yatak \u201ctoplam 80 ton\u201d g\u00f6rm\u00fcyor. Onlar, kendilerini birbirinden ay\u0131rmaya \u00e7al\u0131\u015fan yo\u011funla\u015fm\u0131\u015f bir e\u011filme momenti g\u00f6r\u00fcyor.<\/p>\n\n\n\n \u0130\u015fte bu, sivri z\u0131mba problemidir.<\/p>\n\n\n\n Dar u\u00e7lu ve dar V\u2011kal\u0131pl\u0131 \u00f6zel z\u0131mbalar temas b\u00f6lgesini k\u00fc\u00e7\u00fclt\u00fcr. Ayn\u0131 hesaplanan kuvvet \u015fimdi tak\u0131m\u0131n daha az \u00e7eli\u011finden ve makine yap\u0131s\u0131n\u0131n daha az geni\u015fli\u011finden ge\u00e7iyor. Gerilim h\u0131zla artar \u00e7\u00fcnk\u00fc gerilim = kuvvet \/ alan. Alan\u0131 yar\u0131ya indir, gerilimi ikiye katla.<\/p>\n\n\n\n 90 tonluk bir i\u015fin, birinin \u201cyar\u0131\u00e7ap\u0131 keskinle\u015ftirmek\u201d i\u00e7in daha dar bir kal\u0131ba ge\u00e7mesi nedeniyle 130 tonluk bir ger\u00e7e\u011fe d\u00f6n\u00fc\u015ft\u00fc\u011f\u00fcn\u00fc g\u00f6rd\u00fcm. Toplam kuvvet art\u0131\u015f\u0131 barizdi. Bariz olmayan \u015fey ise z\u0131mba ucundaki yerel ani art\u0131\u015ft\u0131. U\u00e7 ufaland\u0131. Sonra kraterle\u015fti. Sonra bu krateri her par\u00e7aya damgalamaya ba\u015flad\u0131; biz fark edene kadar.<\/p>\n\n\n\n Ve o tabla uzunlu\u011fu s\u0131n\u0131r\u0131n\u0131 hat\u0131rlay\u0131n. Bir\u00e7ok makine, kuvvetin tamam\u0131n\u0131 yata\u011f\u0131n yakla\u015f\u0131k 60%\u2019lik k\u0131sm\u0131nda g\u00fcvenli bir \u015fekilde sa\u011flar. Y\u00fck\u00fcn\u00fcz\u00fc kenarda 2 fitlik bir alanda yo\u011funla\u015ft\u0131r\u0131rsan\u0131z, art\u0131k katalogdaki \u201cmutlu b\u00f6lge\u201dde ya\u015fam\u0131yorsunuz demektir.<\/p>\n\n\n\n Hesab\u0131n\u0131z toplam ton a\u00e7\u0131s\u0131ndan do\u011fru olabilir.<\/p>\n\n\n\n Yine de \u00e7er\u00e7eveniz i\u00e7in yanl\u0131\u015f olabilir.<\/p>\n\n\n\n \u0130ki sac. Ayn\u0131 kalite damgas\u0131. Ayn\u0131 \u00c7EKME MUKAVEMET\u0130<\/strong> k\u00e2\u011f\u0131t \u00fczerinde.<\/p>\n\n\n\n Birini haddeleme y\u00f6n\u00fcne paralel b\u00fck\u00fcn. Di\u011ferini dik olarak b\u00fck\u00fcn.<\/p>\n\n\n\n Ayn\u0131 \u015fekilde davranmazlar.<\/p>\n\n\n\n Haddeleme, tane yap\u0131s\u0131n\u0131 uzat\u0131r. Tane y\u00f6n\u00fcn\u00fcn \u00e7apraz\u0131na b\u00fckme yapt\u0131\u011f\u0131n\u0131zda, yap\u0131yla farkl\u0131 \u015fekilde m\u00fccadele edersiniz; tane y\u00f6n\u00fcyle birlikte b\u00fckme yapt\u0131\u011f\u0131n\u0131zda farkl\u0131. Geri sekme de\u011fi\u015fir. Gerekli fazla b\u00fckme oran\u0131 de\u011fi\u015fir. Bazen stro\u011fun alt k\u0131sm\u0131na yak\u0131n kuvvet e\u011frisi dikle\u015fir \u00e7\u00fcnk\u00fc malzeme, o y\u00f6nelim boyunca s\u0131k\u0131\u015ft\u0131rmaya farkl\u0131 \u015fekilde kar\u015f\u0131 koyar.<\/p>\n\n\n\n Form\u00fcl\u00fcn\u00fcz, \u00e7eli\u011fi her y\u00f6nde ayn\u0131 \u00f6zelliklere sahip izotropik kil gibi ele al\u0131r.<\/p>\n\n\n\n \u00d6yle de\u011fildir.<\/p>\n\n\n\n Ve sonra i\u015f sertle\u015fmesi vard\u0131r. \u00d6zellikle paslanmaz \u00e7elik, \u015fekil de\u011fi\u015ftik\u00e7e dayan\u0131m kazan\u0131r. Ne kadar fazla bast\u0131r\u0131rsan\u0131z, o kadar \u00e7ok kar\u015f\u0131 koyar. Bu da, stro\u011fun son birka\u00e7 derecesinde tabanlamada gereken kuvvetin, ba\u015flang\u0131\u00e7taki tahminden orant\u0131s\u0131z \u015fekilde daha y\u00fcksek olabilece\u011fi anlam\u0131na gelir. Y\u00fck h\u00fccresi \u2014 e\u011fer ak\u0131ll\u0131ca izliyorsan\u0131z \u2014 o ani art\u0131\u015f\u0131 g\u00f6sterecektir.<\/p>\n\n\n\n Uzun bir paslanmaz serisinde, hurday\u0131 optimize etmek i\u00e7in saclar\u0131 parti ortas\u0131nda d\u00f6nd\u00fcrd\u00fc\u011f\u00fcm\u00fczden bir z\u0131mbay\u0131 k\u0131rm\u0131\u015ft\u0131m. Par\u00e7alar\u0131n yar\u0131s\u0131 gayet iyi b\u00fck\u00fclm\u00fc\u015ft\u00fc. D\u00f6nd\u00fcr\u00fclm\u00fc\u015f saclar daha fazla fazla b\u00fckme gerektiriyordu ve tabanda daha sert vuruyordu. Bask\u0131 fark\u0131 g\u00f6rmese bile tak\u0131m bu fark\u0131 hissetti.<\/p>\n\n\n\n Malzemenin haf\u0131zas\u0131 vard\u0131r. Hesaplay\u0131c\u0131n\u0131zda yoktur.<\/p>\n\n\n\n Bu da bizi her ciddi \u00e7al\u0131\u015fmadan \u00f6nce sorman\u0131z gereken soruya getiriyor: \u201cTeorik tonaj nedir?\u201d de\u011fil, \u201cMaksimum AYAK BA\u015eINA TON<\/strong> makinemin bu tam uzunlukta, bu tam konumda, bu tam tak\u0131m ko\u015fulunda g\u00fcvenli bir \u015fekilde \u00fcretebilece\u011fi de\u011fer nedir?\u201d<\/p>\n\n\n\n Bu art\u0131k bir form\u00fcl problemi de\u011fil.<\/p>\n\n\n\n Bu bir operat\u00f6r do\u011frulama s\u00fcrecidir.<\/p>\n\n\n\n Hesab\u0131 yapt\u0131n\u0131z. Ayarlamalar\u0131n\u0131z\u0131 yapt\u0131n\u0131z \u00c7EKME MUKAVEMET\u0130<\/strong>, d\u00fczeltilmi\u015f KALIP A\u00c7IKLI\u011eI<\/strong>, hava b\u00fckme yerine tam b\u00fckme i\u00e7in \u00e7arp\u0131lm\u0131\u015f. G\u00fczel.<\/p>\n\n\n\n \u015eimdi o elektronik tabloyla ilgili hissetti\u011fin gururu unut.<\/p>\n\n\n\n \u00c7\u00fcnk\u00fc makine, say\u0131n\u0131n ne kadar zarif g\u00f6r\u00fcnd\u00fc\u011f\u00fcyle ilgilenmez. AYAK BA\u015eINA TON<\/strong> Kuvvetin nereye uyguland\u0131\u011f\u0131na, ne kadar s\u00fcre uyguland\u0131\u011f\u0131na ve o ko\u00e7 alt\u0131ndaki \u00e7elik \u00e7er\u00e7evenin bunu akmadan ta\u015f\u0131y\u0131p ta\u015f\u0131yamayaca\u011f\u0131na bakar. \u0130\u015fte burada matematik\u00e7i olmay\u0131 b\u0131rak\u0131r, operat\u00f6r olmay\u0131 ba\u015flat\u0131r\u0131z.<\/p>\n\n\n\n \u0130\u015fte protokol. Kuram de\u011fil. Katalog s\u00fcs\u00fc de\u011fil. Bir dizilim.<\/p>\n\n\n\n Birinci: kar\u015f\u0131la\u015ft\u0131r AYAK BA\u015eINA TON<\/strong> b\u00fckmekte oldu\u011fun tam uzunluk boyunca makinenin g\u00fcvenli \u015fekilde verebilece\u011fiyle. \u0130kinci: y\u00f6ntem de\u011fi\u015fiklikleri ve bilinmeyenleri hesaba katacak ger\u00e7ek bir g\u00fcvenlik pay\u0131 olu\u015ftur. \u00dc\u00e7\u00fcnc\u00fc: ilk darbeyi inan\u00e7 s\u0131\u00e7ramas\u0131 de\u011fil, bir tan\u0131 arac\u0131 haline getir.<\/p>\n\n\n\n Bir keresinde toplam tonaja de\u011fil, da\u011f\u0131l\u0131ma g\u00fcvenen biri y\u00fcz\u00fcnden 175 tonluk bir presin kal\u0131c\u0131 bir bombe ald\u0131\u011f\u0131n\u0131 izlemi\u015ftim. Matematik 160 ton toplam diyordu. Makine ise 40 AYAK BA\u015eINA TON<\/strong> tonu yata\u011f\u0131n ucuna y\u0131\u011f\u0131lm\u0131\u015f halde g\u00f6rd\u00fc. \u00c7elik akt\u0131. Bir daha d\u00fczelmedi.<\/p>\n\n\n\n 10 feet boyunca 100 ton olarak derecelendirilmi\u015f bir pres, her yerde 100 tonluk bir makine de\u011fildir.<\/p>\n\n\n\n O, \u00e7al\u0131\u015fma uzunlu\u011fu boyunca e\u015fit da\u011f\u0131l\u0131m varsay\u0131m\u0131yla bir 10 AYAK BA\u015eINA TON<\/strong> makinedir.<\/p>\n\n\n\n \u015eimdi 2 footluk bir par\u00e7ay\u0131 al ve sol kenardan 12 in\u00e7 uza\u011fa park et. Hesab\u0131n 25 AYAK BA\u015eINA TON<\/strong>, diyorsa, o ko\u00e7 ve yatak b\u00f6l\u00fcm\u00fcne tek bir k\u00fc\u00e7\u00fck b\u00f6lgeye yo\u011funla\u015ft\u0131r\u0131lm\u0131\u015f 50 ton ta\u015f\u0131mas\u0131n\u0131 s\u00f6yl\u00fcyorsun. Di\u011fer sekiz foot hi\u00e7bir \u015fey yapm\u0131yor.<\/p>\n\n\n\n Katalog derecelendirmeleri da\u011f\u0131l\u0131m varsayar. \u00c7er\u00e7eveler k\u00f6pr\u00fc gibi tasarlan\u0131r \u2014 y\u00fck a\u00e7\u0131kl\u0131k boyunca yay\u0131l\u0131r. Yo\u011funla\u015ft\u0131r\u0131rsan, o yerel b\u00f6l\u00fcmdeki e\u011filme momenti ani \u015fekilde y\u00fckselir. Sapma art\u0131k do\u011frusal de\u011fildir. Geometriktir.<\/p>\n\n\n\n Ve i\u015fte operat\u00f6rlerin aldat\u0131ld\u0131\u011f\u0131 nokta: toplam MEVCUT TONAJI<\/strong> makinenin maksimumunun alt\u0131nda olabilir, ancak yerel GER\u0130LME<\/strong> \u2014 alan taraf\u0131ndan b\u00f6l\u00fcnen kuvvet \u2014 o piston segmentinin ta\u015f\u0131yabilece\u011finden fazlas\u0131na ula\u015f\u0131r.<\/p>\n\n\n\n \u0130ki fit uzunlu\u011funda zar zor olan k\u0131sa bir paslanmaz braketi, operat\u00f6r par\u00e7ay\u0131 de\u011fil de arka dayama parmaklar\u0131n\u0131 ortalad\u0131\u011f\u0131 i\u00e7in yata\u011f\u0131n sol taraf\u0131n\u0131 kal\u0131c\u0131 olarak b\u00fck\u00fclm\u00fc\u015f durumda g\u00f6rd\u00fcm. Makine toplam\u0131 a\u015fmad\u0131 TONAJ<\/strong>. Yap\u0131sal sa\u011fduyuyu a\u015ft\u0131.<\/p>\n\n\n\n Bu \u015fekilde do\u011frulama yapars\u0131n\u0131z:<\/p>\n\n\n\n Ayak ba\u015f\u0131na gereksiniminiz, o konumdaki makinenin ayak ba\u015f\u0131na kapasitesini a\u015f\u0131yorsa, \u201cbiraz agresif\u201d de\u011filsiniz. Yap\u0131sal olarak a\u015f\u0131r\u0131 y\u00fck bindiriyorsunuz.<\/p>\n\n\n\n Say\u0131sal olarak k\u00e2\u011f\u0131t \u00fczerinde uygun g\u00f6r\u00fcnse bile, bir presi 100% oran\u0131nda \u00e7al\u0131\u015ft\u0131rmazs\u0131n\u0131z KAPAS\u0130TE<\/strong>.<\/p>\n\n\n\n Bir dizeli de her vardiyada k\u0131rm\u0131z\u0131 \u00e7izgiye kadar kullanmazs\u0131n\u0131z.<\/p>\n\n\n\n Neden 80%? \u00c7\u00fcnk\u00fc form\u00fcl\u00fcn\u00fcz her \u015feyi bilmez. Lif y\u00f6n\u00fcn\u00fc, kal\u0131p a\u015f\u0131nmas\u0131n\u0131, s\u00fcrt\u00fcnmedeki de\u011fi\u015fimleri, hidrolik ya\u011fdaki s\u0131cakl\u0131k dalgalanmalar\u0131n\u0131 veya farkl\u0131 a\u00e7\u0131larda, ayak ba\u015f\u0131na k\u0131sa ton cinsinden mi yoksa metre ba\u015f\u0131na metrik ton cinsinden mi derecelendirildi\u011fini g\u00f6rmez. Bir katalogda 60 damgal\u0131 bir kal\u0131p, ba\u015fka bir katalogda 46 damgal\u0131 olandan her zaman daha g\u00fc\u00e7l\u00fc de\u011fildir; birimleri ve derecelendirme ko\u015fullar\u0131n\u0131 d\u00f6n\u00fc\u015ft\u00fcrmedik\u00e7e.<\/p>\n\n\n\n Mekanizma \u015fu \u015fekildedir: Maksimum g\u00f6vde y\u00fck\u00fcne yakla\u015ft\u0131k\u00e7a sapma do\u011frusal olmayan bi\u00e7imde artar. K\u00fc\u00e7\u00fck bir ek kuvvet orant\u0131s\u0131z derecede daha b\u00fcy\u00fck yap\u0131sal gerilme yarat\u0131r. \u0130\u015fte ta\u00e7lama sistemlerinin s\u0131n\u0131r\u0131na ula\u015ft\u0131\u011f\u0131 an. \u0130\u015fte pimlerin a\u015f\u0131nmaya ba\u015flad\u0131\u011f\u0131 an. Mikro \u00e7atlaklar\u0131n ba\u015flad\u0131\u011f\u0131 and\u0131r.<\/p>\n\n\n\n \u015eimdi b\u00fckme y\u00f6ntemini ekleyin.<\/p>\n\n\n\n Hava b\u00fckme temel d\u00fczeyde mi? G\u00fczel \u2014 80% kural\u0131 mant\u0131kl\u0131d\u0131r. Alt\u0131na bat\u0131rma 1,5\u00d7 kuvvette mi? Marj\u0131n\u0131z hemen daral\u0131r. Z\u0131mba ile 5\u00d7 kuvvet mi? 80% kural\u0131 anlams\u0131z hale gelir \u00e7\u00fcnk\u00fc strokun sonunda y\u00fck art\u0131\u015f\u0131 an\u0131nda kapasiteyi a\u015fabilir.<\/p>\n\n\n\n Bir operat\u00f6r\u00fcn \u201ca\u00e7\u0131 kay\u0131yordu\u201d dedi\u011fi i\u00e7in t\u00fcm hafta hava b\u00fckme ile i\u015flendi\u011fi bir par\u00e7ay\u0131 alt\u0131na bast\u0131\u011f\u0131n\u0131 izlemi\u015ftim. Bu y\u00f6ntem de\u011fi\u015fimi etkili GEREKL\u0130 KUVVET<\/strong> de\u011ferlendirme d\u0131\u015f\u0131nda KAPAS\u0130TE<\/strong> orijinal hava b\u00fckme hesaplamas\u0131 g\u00fcvenli olmas\u0131na ra\u011fmen. O g\u00fcn piston ke\u00e7eleri ar\u0131zalanmad\u0131. \u00c7er\u00e7eve zamanla deforme oldu. Alt\u0131 ay sonra kal\u0131c\u0131 bir sapmay\u0131 telafi etmek i\u00e7in takoz koyuyorduk.<\/p>\n\n\n\n G\u00fcvenlik pay\u0131 korkakl\u0131k de\u011fildir. Form\u00fcl\u00fcn\u00fcz\u00fcn g\u00f6remedi\u011fi \u015feyleri hesaba katmakt\u0131r.<\/p>\n\n\n\n \u0130\u015fte dolu tabanca benzetmesinin ger\u00e7e\u011fe d\u00f6n\u00fc\u015ft\u00fc\u011f\u00fc yer buras\u0131.<\/p>\n\n\n\n Form\u00fcl ne olmas\u0131 gerekti\u011fini s\u00f6yler. \u0130lk darbe ise ne oldu\u011funu s\u00f6yler.<\/p>\n\n\n\n A\u015famal\u0131 olarak do\u011frulay\u0131n:<\/p>\n\n\n\n E\u011fer y\u00fck, hesaplad\u0131\u011f\u0131n\u0131z KUVVET E\u011eR\u0130S\u0130<\/strong>, taraf\u0131ndan \u00f6ng\u00f6r\u00fclenden daha h\u0131zl\u0131 artarsa, durun. Bir \u015fey de\u011fi\u015fti \u2014 belki ger\u00e7ek \u00c7EKME MUKAVEMET\u0130<\/strong> spesifikasyondan daha y\u00fcksek, belki de KALIP A\u00c7IKLI\u011eI<\/strong> a\u015f\u0131nmadan dolay\u0131 etkin olarak daha k\u00fc\u00e7\u00fck, ya da belki istemeden tabana \u00e7arp\u0131yorsunuz.<\/p>\n\n\n\n Bug\u00fcn\u00fcn dijital y\u00fck sens\u00f6rleri, eski tablolar\u0131n asla g\u00f6steremedi\u011fi sapmalar\u0131 size g\u00f6sterebilir. Hesaplad\u0131\u011f\u0131n\u0131z talep 20 AYAK BA\u015eINA TON<\/strong> ve makine son birka\u00e7 derecede h\u0131zla 26\u201cya t\u0131rman\u0131yorsa, bu \u201dyeterince yak\u0131n\u201d de\u011fildir. Bu 30%\u2019l\u00fck bir farkt\u0131r.<\/p>\n\n\n\n Kariyerimin ba\u015flar\u0131nda, sese oldu\u011fundan fazla say\u0131ya g\u00fcvenerek bir dizi b\u00f6l\u00fcml\u00fc z\u0131mbay\u0131 mahvettim. Bas\u0131n\u00e7 g\u00f6stergesi bana y\u00fck e\u011frisinin olmas\u0131 gerekenden daha dik oldu\u011funu s\u00f6yl\u00fcyordu. Devam ettim. Segment kama yolundan ayr\u0131ld\u0131. Hava b\u00fckme i\u00e7in matematik do\u011fruydu. Makine, derinlik durdurucusu k\u0131l pay\u0131 hatal\u0131 oldu\u011fu i\u00e7in taban yap\u0131yordu.<\/p>\n\n\n\n \u0130leriye ta\u015f\u0131yaca\u011f\u0131n\u0131z tek \u015fey \u015fu:<\/p>\n\n\n\n Form\u00fcl otorite de\u011fildir. Bu bir varsay\u0131md\u0131r.<\/p>\n\n\n\n Makine \u2014 \u00e7er\u00e7eve oran\u0131, ayak ba\u015f\u0131na s\u0131n\u0131rlar\u0131, canl\u0131 y\u00fck geri bildirimi \u2014 deneyin kendisidir. Bu ikisi \u00e7eli\u015firse, teoriden ziyade \u00e7eli\u011fe inan\u0131rs\u0131n\u0131z.<\/p>\n\n\n\n Alt alt\u0131, bir t\u00fcfek sesi gibi \u00e7at\u0131rdayarak b\u00f6l\u00fcnd\u00fc. \u00c7eyrek in\u00e7lik levha. Hi\u00e7bir egzotik \u015fey yok. Operat\u00f6r, bir kurulum sayfas\u0131n\u0131n arkas\u0131nda hesaplamalar\u0131 yapm\u0131\u015ft\u0131: 575 \u00d7 T\u00b2 \u00d7 L. Makine g\u00fcvenli olarak derecelendirilmi\u015fti. \u0130\u015f rutin olmal\u0131yd\u0131. Bunun yerine, karbidi s\u00fcp\u00fcr\u00fcyorduk ve muhasebeye neden \u201cbasit bir b\u00fckme\u201d oldu\u011funu a\u00e7\u0131kl\u0131yorduk [\u2026]<\/p>","protected":false},"author":3,"featured_media":1313,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_breakdance_hide_in_design_set":false,"_breakdance_tags":"","footnotes":""},"categories":[1],"tags":[],"class_list":["post-1309","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-uncategorized"],"_links":{"self":[{"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/posts\/1309","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/comments?post=1309"}],"version-history":[{"count":1,"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/posts\/1309\/revisions"}],"predecessor-version":[{"id":1314,"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/posts\/1309\/revisions\/1314"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/media\/1313"}],"wp:attachment":[{"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/media?parent=1309"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/categories?post=1309"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/tags?post=1309"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}575 Kural\u0131: Standart form\u00fcl\u00fcn asl\u0131nda varsayd\u0131klar\u0131 (yumu\u015fak \u00e7elik, hava b\u00fck\u00fcm\u00fc, 8x kal\u0131p)<\/h3>\n\n\n\n
![\"Standart](\"https:\/\/cn-hawe.com\/wp-content\/uploads\/2026\/03\/What-the-standard-formula-actually-assumes-mild-steel-air-bending-8x-die_w1200.jpg\")
<\/figure>\n\n\n\nNeden kal\u0131nl\u0131k \u00d7 uzunlu\u011fun yeterli g\u00f6r\u00fcnd\u00fc\u011f\u00fc ama en b\u00fcy\u00fck kuvvet etkenlerini sessizce g\u00f6z ard\u0131 etti\u011fi<\/h3>\n\n\n\n
![\"Neden](\"https:\/\/cn-hawe.com\/wp-content\/uploads\/2026\/03\/Why-thickness-\u00d7-length-feels-sufficient_w1200.jpg\")
<\/figure>\n\n\n\n\u201cYeterince yak\u0131n\u201d tahminlerin gizli maliyeti: K\u0131r\u0131lm\u0131\u015f kal\u0131plar, durmu\u015f makineler ve hurdaya \u00e7\u0131kan par\u00e7alar<\/h3>\n\n\n\n
![\""Yeterince](\"https:\/\/cn-hawe.com\/wp-content\/uploads\/2026\/03\/Cracked-dies-stalled-machines-and-scrapped-parts_w1200.jpg\")
<\/figure>\n\n\n\nDiren\u00e7 Fizi\u011fi: Tonaj\u0131n\u0131z\u0131 Ele Ge\u00e7iren \u00dc\u00e7 De\u011fi\u015fken<\/h2>\n\n\n\n
Malzeme \u00c7ekme Mukavemeti: Paslanmaz \u00e7eli\u011fin sadece \u201cdaha a\u011f\u0131r\u201d karbon \u00e7elik olmad\u0131\u011f\u0131n\u0131 (ve temel de\u011ferin sizi nas\u0131l yan\u0131ltt\u0131\u011f\u0131n\u0131)<\/h3>\n\n\n\n
O say\u0131y\u0131 ayarlamazsan\u0131z, hesaplama yapm\u0131yorsunuz. Kumar oynuyorsunuz.<\/h3>\n\n\n\n
B\u00fckme Y\u00f6ntemi: Hava b\u00fckme vs. tabanlama vs. bask\u0131lama (neden kuvvet 4x ila 8x artar)<\/h3>\n\n\n\n
Birle\u015fik Form\u00fcl\u00fc \u00c7\u00f6z\u00fcmleme: Mekanizmadan Hesaplamay\u0131 Olu\u015fturmak<\/h2>\n\n\n\n
Temel Denklem: Malzeme \u00f6zelliklerini ve tak\u0131m geometrisini tonlara \u00e7evirmek<\/h3>\n\n\n\n
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Metrik vs. \u0130mparatorluk sabitleri: Do\u011fruluk kaybetmeden d\u00f6n\u00fc\u015ft\u00fcrme<\/h3>\n\n\n\n
Malzeme D\u00fczeltme Fakt\u00f6r\u00fcn\u00fc (MCF) tahmin y\u00fcr\u00fctmeden uygulamak<\/h3>\n\n\n\n
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Ad\u0131m Ad\u0131m: Ger\u00e7ek D\u00fcnya B\u00fck\u00fcmleri i\u00e7in Tonaj Hesaplama<\/h2>\n\n\n\n
\u00d6rnek 1: Temel durum (10 numara yumu\u015fak \u00e7elik, 48\u2033 b\u00fck\u00fcm, 8x kal\u0131p)<\/h3>\n\n\n\n
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\u00d6rnek 2: \u00c7arpan (Ayn\u0131 par\u00e7a paslanmaz \u00e7elikte, daha k\u00fc\u00e7\u00fck bir V kal\u0131pta)<\/h3>\n\n\n\n
\n
\u00d6rnek 3: Tehlike B\u00f6lgesi (Ayn\u0131 geometrik yap\u0131, ancak hava b\u00fckme yerine alt b\u00fckme)<\/h3>\n\n\n\n
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Teorik Matemati\u011fin Bozuldu\u011fu Yer: G\u00f6r\u00fcnmez De\u011fi\u015fkenler<\/h2>\n\n\n\n
Tak\u0131m A\u015f\u0131nmas\u0131: K\u00f6r bir kal\u0131p tonaj ihtiyac\u0131n\u0131z\u0131 gizlice \u201130 art\u0131r\u0131r<\/h3>\n\n\n\n
Yo\u011funla\u015fm\u0131\u015f Y\u00fckler: \u201cSivri z\u0131mba\u201d sorununun neden toplam makine kapasitesini g\u00f6lgede b\u0131rakt\u0131\u011f\u0131<\/h3>\n\n\n\n
Tane Y\u00f6n\u00fc ve Malzeme Haf\u0131zas\u0131: Standart hesaplay\u0131c\u0131lara kar\u015f\u0131 koyan de\u011fi\u015fkenler<\/h3>\n\n\n\n
Operat\u00f6r\u00fcn Ger\u00e7eklik Kontrol\u00fc: Pedala Basmadan \u00d6nce Matemati\u011fi Do\u011frulama<\/h2>\n\n\n\n
Ayak ba\u015f\u0131na d\u00fc\u015fen ton vs. tam yatak kapasitesi: Ko\u00e7un belirli bir b\u00f6l\u00fcm\u00fcn\u00fc a\u015f\u0131r\u0131 m\u0131 y\u00fckl\u00fcyorsun?<\/h3>\n\n\n\n
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G\u00fcvenlik marj\u0131n\u0131 hesaplamak: Neden 80% kapasitenin \u00f6tesine asla ge\u00e7memeniz gerekir<\/h3>\n\n\n\n
\u201c\u0130lk Darbe\u201d Protokol\u00fc: Ne zaman makine geri bildirimine form\u00fclden daha \u00e7ok g\u00fcvenmelisiniz<\/h3>\n\n\n\n
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\u0130lgili Kaynaklar ve Sonraki Ad\u0131mlar<\/h2>\n\n\n\n
\n