{"id":1367,"date":"2026-03-18T06:12:22","date_gmt":"2026-03-18T06:12:22","guid":{"rendered":"https:\/\/cn-hawe.com\/?p=1367"},"modified":"2026-03-19T06:17:49","modified_gmt":"2026-03-19T06:17:49","slug":"precision-press-brake-forming","status":"publish","type":"post","link":"https:\/\/cn-hawe.com\/tr\/precision-press-brake-forming\/","title":{"rendered":"Hassas Abkant Pres B\u00fck\u00fcm\u00fc: Geri Yaylanma ve B\u00fck\u00fcm Do\u011frulu\u011fu Sorunlar\u0131n\u0131n \u00c7\u00f6z\u00fcm\u00fc"},"content":{"rendered":"

200 tonluk bir pres frenin, 3\/16 in\u00e7 HSLA \u00fczerinde 90\u00b0\u2019lik bir b\u00fckmeyi iki dereceyle ka\u00e7\u0131rd\u0131\u011f\u0131n\u0131 izledim. Yepyeni bir makine. CNC ta\u00e7lama. Lazer a\u00e7\u0131 kontrol\u00fc. Ekran 90,0\u00b0 diyordu. Par\u00e7a ise 92\u00b0 dedi.<\/p>\n\n\n\n

Operat\u00f6r tonaj\u0131 su\u00e7lad\u0131. S\u00fcperviz\u00f6r program\u0131 su\u00e7lad\u0131. \u00c7elik ise orada \u00f6ylece durdu, \u015fekline tutunan, seni duydu\u011fu h\u00e2lde kendi cevab\u0131n\u0131 vermeye karar veren inat\u00e7\u0131 bir \u00e7\u0131rak gibi.<\/p>\n\n\n\n

Ekran ile \u00e7elik aras\u0131ndaki o bo\u015fluk, hassasiyetin ger\u00e7ekten ya\u015fad\u0131\u011f\u0131 yerdir\u2014ve o bo\u015flu\u011fu kapatmak yaln\u0131zca ham tonajla de\u011fil; tekrarlanabilirlik, telafi ve ger\u00e7ek \u00fcretim i\u015f ak\u0131\u015flar\u0131na entegrasyon i\u00e7in tasarlanm\u0131\u015f CNC kontroll\u00fc b\u00fckme sistemleriyle m\u00fcmk\u00fcnd\u00fcr. CN-HAWE\u2019nin 100% CNC tabanl\u0131 b\u00fckme sistemleri gibi \u00e7\u00f6z\u00fcmler, \u015fu adreste ayr\u0131nt\u0131l\u0131 olarak yer al\u0131r: pres fren \u00e7\u00f6z\u00fcmleri sayfas\u0131<\/a>, ve her vuru\u015fta elastik davran\u0131\u015f\u0131n, otomasyonun ve a\u00e7\u0131 tutarl\u0131l\u0131\u011f\u0131n\u0131n hizalanmas\u0131 gereken \u00fcst d\u00fczey sac metal uygulamalar\u0131 i\u00e7in \u00fcretilmi\u015ftir.<\/p>\n\n\n\n

Hassasiyet \u0130ll\u00fczyonu: Neden Y\u00fcksek Tonaj ve CNC Garantileri Ger\u00e7ek Do\u011fru A\u00e7\u0131lar\u0131 Vermez<\/h2>\n\n\n\n

200 tonluk bir frenin, 50 ksi A36 m\u0131 yoksa 70 ksi HSLA m\u0131 takt\u0131\u011f\u0131n\u0131 bilme \u015fans\u0131 yoktur. Sadece kuvveti ve konumu bilir. Akma dayan\u0131m\u0131\u2014\u00e7eli\u011fin elastik davran\u0131\u015f\u0131n\u0131 b\u0131rak\u0131p kal\u0131c\u0131 \u015fekil almaya ba\u015flad\u0131\u011f\u0131 gerilim\u2014ram taraf\u0131ndan \u201chissedilemez\u201d. Bu, hesaplad\u0131\u011f\u0131n\u0131z bir de\u011ferdir.<\/p>\n\n\n\n

D\u00fckkanlar\u0131n a\u00e7\u0131 tutars\u0131zl\u0131\u011f\u0131n\u0131 \u201c\u00e7\u00f6zmek\u201d i\u00e7in b\u00fcy\u00fck makineler sat\u0131n ald\u0131klar\u0131n\u0131 g\u00f6rd\u00fcm. Daha fazla kuvvet. Daha h\u0131zl\u0131 servo motorlar. Daha s\u0131k\u0131 arka dayama tekrarlanabilirli\u011fi. Ve vardiya boyunca h\u00e2l\u00e2 yar\u0131m derecelik d\u00fczeltmelerin pe\u015finde ko\u015fuyorlar. \u00c7\u00fcnk\u00fc makine konumu binde bir hassasiyetle tekrarlayabilir, ama geri s\u0131\u00e7ramay\u0131 silemez. Tavlamad\u0131\u011f\u0131n\u0131z bir kaynak diki\u015fi yan\u0131ndaki kal\u0131nt\u0131 gerilimleri normalize edemez. Ram hareket etmeden \u00f6nce yapt\u0131\u011f\u0131n\u0131z yanl\u0131\u015f kal\u0131p se\u00e7imini de d\u00fczeltemez.<\/p>\n\n\n\n

Y\u00fcksek tonaj par\u00e7ay\u0131 b\u00fcker. Ama yaylanmadan sonra nereye oturaca\u011f\u0131n\u0131 garanti etmez.<\/p>\n\n\n\n

Yani denetleyici 90\u00b0 diyorsa, ama par\u00e7a 92\u00b0 g\u00f6steriyorsa, tam olarak ne oldu?<\/p>\n\n\n\n

Denetleyici 90 Derece Diyorsa, Par\u00e7a Neden 92?<\/h3>\n\n\n\n
\"Denetleyici<\/figure>\n\n\n\n

1 in\u00e7 V kal\u0131b\u0131nda 10 numara A36 sac\u0131 hava b\u00fckme ile b\u00fckmeyi g\u00f6z\u00fcn\u00fczde canland\u0131r\u0131n. 8x kural\u0131n\u0131 izliyorsunuz\u2014k\u0131zak a\u00e7\u0131kl\u0131\u011f\u0131 malzeme kal\u0131nl\u0131\u011f\u0131n\u0131n yakla\u015f\u0131k sekiz kat\u0131\u2014yani 0.135 in\u00e7 sac i\u00e7in 1 in\u00e7 civar\u0131 do\u011fru. Program, 90\u00b0\u2019yi tutturacak \u015fekilde z\u0131mba derinli\u011fini hesaplar.<\/p>\n\n\n\n

Y\u00fck alt\u0131ndayken 88\u00b0\u2019ye ula\u015f\u0131rs\u0131n\u0131z. Bas\u0131nc\u0131 b\u0131rakt\u0131\u011f\u0131n\u0131zda, par\u00e7a gev\u015fer ve 92\u00b0\u2019ye geri d\u00f6ner.<\/p>\n\n\n\n

Hi\u00e7bir \u015fey \u201cyanl\u0131\u015f gitmedi\u201d. \u00c7elik akmaya ba\u015flad\u0131, sonra deformasyonun elastik k\u0131sm\u0131 geri kazand\u0131. Bu geri kazan\u0131m, yaylanmad\u0131r\u2014malzemenin molek\u00fcler haf\u0131zas\u0131n\u0131n par\u00e7ay\u0131 k\u0131smen yerine \u00e7ekmesidir. Daha y\u00fcksek akma dayan\u0131m\u0131? Daha fazla s\u0131\u00e7rama. Daha geni\u015f kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131? Daha fazla s\u0131\u00e7rama. Daha ince malzeme? Daha fazla s\u0131\u00e7rama.<\/p>\n\n\n\n

\u015eimdi ayn\u0131 kal\u0131nl\u0131kta, ayn\u0131 kal\u0131pta A36\u2019y\u0131 \u00e7\u0131kar ve yerine 70 ksi HSLA koy. Denetleyici akma dayan\u0131m\u0131n\u0131n 40% kadar artt\u0131\u011f\u0131n\u0131 otomatik olarak bilmez. Malzeme k\u00fct\u00fcphanen ayarl\u0131 de\u011filse\u2014ya da daha k\u00f6t\u00fcs\u00fc, varsay\u0131lan de\u011ferlere g\u00fcveniyorsan\u2014b\u00fckme programlam\u0131yorsun. Tahmin edip d\u00fczeltme yap\u0131yorsun.<\/p>\n\n\n\n

Ve i\u015fte i\u015fletmelerin kendini kand\u0131rd\u0131\u011f\u0131 nokta: makine ayn\u0131 yanl\u0131\u015f a\u00e7\u0131y\u0131 kusursuz bi\u00e7imde tekrarlarsa, buna \u201cdo\u011fru\u201d diyorlar. Tekrarlanabilirlik do\u011fruluk de\u011fildir. Sadece tutarl\u0131 hatad\u0131r.<\/p>\n\n\n\n

O h\u00e2lde, ram \u00e7eli\u011fe de\u011fmeden \u00f6nce hangi de\u011fi\u015fkenler zaten sonucu belirliyor?<\/p>\n\n\n\n

Gizli De\u011fi\u015fken Y\u0131\u011f\u0131n\u0131: Malzeme, Kal\u0131plar ve Y\u00f6ntem Ram Hareket Etmeden \u00d6nce Etkile\u015fir<\/h3>\n\n\n\n
\"Kal\u0131p<\/figure>\n\n\n\n

Bir kez uzun bir yatakta \u00fc\u00e7 nokta kontrol\u00fc yapt\u0131m: ayn\u0131 program, ayn\u0131 sac; sol, orta, sa\u011f. Orta a\u00e7\u0131 kenarlardan 0.3\u00b0\u2019den fazla farkl\u0131yd\u0131. G\u00f6vde sapmas\u0131 ve ta\u00e7lama telafisi tam olarak e\u015fle\u015fmemi\u015fti. CNC bizi uyarmad\u0131. Bunu \u00e7elik s\u00f6yledi.<\/p>\n\n\n\n

\u015eimdi ger\u00e7ek \u00fcretim ko\u015fullar\u0131n\u0131 \u00fcst \u00fcste koy. Kaynak diki\u015fi yak\u0131n\u0131ndaki plaka kal\u0131nt\u0131 gerilim ta\u015f\u0131r. Gerilim gidermeyi atla, o b\u00f6lge farkl\u0131 bir ala\u015f\u0131m gibi b\u00fck\u00fcl\u00fcr. B\u00fckme ofsetlerini malzeme kal\u0131nl\u0131\u011f\u0131n\u0131n alt\u0131 kat\u0131ndan daha yak\u0131na al\u0131rsan, ram hizas\u0131zl\u0131\u011f\u0131na ve dengesiz bas\u0131n\u00e7 geri d\u00f6n\u00fc\u015f\u00fcne davetiye \u00e7\u0131kar\u0131rs\u0131n. Bu teori de\u011fil\u2014bu, valflerin a\u015f\u0131nmas\u0131 ve \u00e7evrim s\u00fcrelerinin uzarken a\u00e7\u0131lar\u0131n kaymas\u0131d\u0131r.<\/p>\n\n\n\n

Tak\u0131m geometrisi de en az onun kadar \u00f6nemlidir. Raflarda olan \u201c10x vard\u0131\u201d diye 8x kal\u0131nl\u0131kta bir V-kal\u0131ptan 10x\u2019e ge\u00e7erseniz, i\u00e7 yar\u0131\u00e7ap\u0131 ve geri esneme davran\u0131\u015f\u0131n\u0131 de\u011fi\u015ftirmi\u015f olursunuz. Ayn\u0131 z\u0131mbalama derinli\u011fi. Farkl\u0131 sonu\u00e7. Denetleyici yaln\u0131zca derinli\u011fi g\u00f6r\u00fcr. Malzeme yar\u0131\u00e7ap\u0131 hisseder.<\/p>\n\n\n\n

Y\u00f6ntem her \u015feyi birbirine ba\u011flar. Hava b\u00fckme, zeminleme, bask\u0131lama (coining)\u2014her biri deformasyonun ne kadar\u0131n\u0131n elastik, ne kadar\u0131n\u0131n tamamen plastik oldu\u011funu de\u011fi\u015ftirir. Daha fazla plastik deformasyon geri esnemeyi azalt\u0131r, fakat tonaj\u0131 u\u00e7urur ve kal\u0131plar\u0131 y\u0131prat\u0131r. E\u011fer z\u0131mbalar\u0131 s\u00fcrekli de\u011fi\u015ftirmeyi sevmedi\u011finiz s\u00fcrece, havac\u0131l\u0131k ba\u011flant\u0131 par\u00e7alar\u0131n\u0131 b\u00fct\u00fcn g\u00fcn boyunca coin etmezsiniz.<\/p>\n\n\n\n

Malzeme. Tak\u0131m. Y\u00f6ntem. Hi\u00e7biri yaln\u0131zca beygir g\u00fcc\u00fcyle kontrol edilmez.<\/p>\n\n\n\n

Dolay\u0131s\u0131yla e\u011fer kuvvet hassasiyetin dayanak noktas\u0131 de\u011filse, ne \u00f6yledir?<\/p>\n\n\n\n

Sorunun Yeniden \u00c7er\u00e7evelenmesi: Hassasiyet Plastik Kuvvette De\u011fil, Elastik Telafide Ya\u015far<\/h3>\n\n\n\n
\"Elastik<\/figure>\n\n\n\n

A\u00e7\u0131 \u00f6l\u00e7erli modern bir servo preste deneyimli bir operat\u00f6r\u00fc izleyin. \u0130lk vurma: y\u00fck alt\u0131nda 88\u00b0, bo\u015fald\u0131\u011f\u0131nda 92\u00b0. Daha fazla tonaj aramaz. Programa iki derece fazla b\u00fckme ekler\u2014daha derine iner ki elastik geri kazan\u0131mdan sonra par\u00e7a 90\u00b0\u2019ye rahatlas\u0131n.<\/p>\n\n\n\n

\u00c7elikle sava\u015fm\u0131yor. Onunla m\u00fczakere ediyor.<\/p>\n\n\n\n

Sizden istedi\u011fim de\u011fi\u015fim i\u015fte bu: hassasiyeti \u201cdo\u011fru \u015fekilde uygulanm\u0131\u015f kuvvet\u201d olarak g\u00f6rmekten vazge\u00e7in, \u201c\u00f6ng\u00f6r\u00fclm\u00fc\u015f ve telafi edilmi\u015f elastik davran\u0131\u015f\u201d olarak g\u00f6rmeye ba\u015flay\u0131n. Plastik kuvvet sizi akma noktas\u0131n\u0131n \u00f6tesine ge\u00e7irir. Elastik telafi sizi do\u011fru a\u00e7\u0131ya getirir.<\/p>\n\n\n\n

Y\u00fcksek h\u0131zl\u0131 servolar ve s\u00f6n\u00fcmleme sistemleri kesinlikle yard\u0131mc\u0131 olur. Mekanik bo\u015flu\u011fu ortadan kald\u0131r\u0131r ve \u00fcretim h\u0131z\u0131nda programl\u0131 derinli\u011fe tutarl\u0131 bir \u015fekilde ula\u015fman\u0131z\u0131 sa\u011flar. Malzeme partilerinin istikrarl\u0131 oldu\u011fu y\u00fcksek hacimli \u00e7al\u0131\u015fmalarda bu tutarl\u0131l\u0131k, gev\u015fek hesaplanm\u0131\u015f geri esneme matemati\u011fini geride b\u0131rakabilir. Ama o durumda bile, belirli bir malzeme partisine, kal\u0131nl\u0131\u011fa ve kal\u0131p d\u00fczenine ba\u011fl\u0131 \u00f6\u011frenilmi\u015f telafi de\u011ferlerine g\u00fcveniyorsunuz. Bunlardan birini de\u011fi\u015ftirin, eski rakamlar yalan s\u00f6yler.<\/p>\n\n\n\n

Denetleyici yakla\u015f\u0131k hesap yapar. Karar\u0131 veren malzemedir.<\/p>\n\n\n\n

Ve bunu kabul etti\u011finiz anda art\u0131k \u201cmakine ne kadar b\u00fcy\u00fck?\u201d diye sormazs\u0131n\u0131z\u2014\u201c\u00e7eli\u011fin neyi hat\u0131rlad\u0131\u011f\u0131n\u0131 ne kadar iyi anl\u0131yorum?\u201d diye sormaya ba\u015flars\u0131n\u0131z.<\/p>\n\n\n\n

Geri Esneme Denkleminin \u015eifresini \u00c7\u00f6zmek: Neden Malzeme Akmas\u0131 Hareketli Bir Hedeftir<\/h2>\n\n\n\n

Ge\u00e7en k\u0131\u015f yepyeni bir makinede 0,125 in\u00e7 17-4PH i\u015fledik. Program 90\u00b0 diyordu. \u0130lk darbe bo\u015fald\u0131ktan sonra 94\u00b0\u2019ye a\u00e7\u0131ld\u0131. T\u00fcm hafta boyunca 304 paslanmaz \u00e7elikte kulland\u0131\u011f\u0131m\u0131z ayn\u0131 kal\u0131p. Ayn\u0131 derinlik. Farkl\u0131 sonu\u00e7. De\u011fi\u015fen tek \u015fey, o levhan\u0131n i\u00e7indeki akma dayan\u0131m\u0131yd\u0131.<\/p>\n\n\n\n

\u0130lk seferde do\u011fru a\u00e7\u0131ya denk gelmek mi istiyorsunuz? O zaman akmay\u0131 malzeme k\u00fct\u00fcphanesindeki sabit bir say\u0131 gibi de\u011fil, elastik haf\u0131zan\u0131n bek\u00e7isi gibi g\u00f6rmeye ba\u015flay\u0131n. Geri esneme bir gizem de\u011fil\u2014akmay\u0131 a\u015ft\u0131ktan sonra elastik gerinimin geri kazan\u0131lmas\u0131d\u0131r. Uygulad\u0131\u011f\u0131n\u0131z plastik gerinim miktar\u0131na g\u00f6re akma dayan\u0131m\u0131 ne kadar y\u00fcksekse, o kadar sert geri d\u00f6ner. Bu felsefe de\u011fil. Bu, gerilme-gerinim e\u011frisi matemati\u011fidir.<\/p>\n\n\n\n

\u00c7o\u011fu denetleyici, sertifikan\u0131n \u00fczerinde b\u00fcy\u00fck yaz\u0131ld\u0131\u011f\u0131 i\u00e7in \u00e7ekme dayan\u0131m\u0131n\u0131 kaydeder. Ama \u00e7ekme dayan\u0131m\u0131 k\u0131r\u0131lmadan \u00f6nceki tepedir. Geri esneme \u00e7ok daha \u00f6nce kararla\u015ft\u0131r\u0131l\u0131r\u2014tam olarak akmay\u0131 ge\u00e7ti\u011finiz anda ve onun \u00f6tesine ne kadar gitti\u011finizle. E\u011fer telafi programlamas\u0131n\u0131 e\u011frinin yanl\u0131\u015f k\u0131sm\u0131na g\u00f6re yap\u0131yorsan\u0131z, bir hayaletle pazarl\u0131k ediyorsunuz demektir.<\/p>\n\n\n\n

O zaman de\u011firmen sertifikas\u0131ndaki hangi say\u0131 ger\u00e7ekten z\u0131mban\u0131za kar\u015f\u0131 m\u00fccadele ediyor?<\/p>\n\n\n\n

Akma Dayan\u0131m\u0131 vs. \u00c7ekme Dayan\u0131m\u0131: Hangisi Ger\u00e7ekten Z\u0131mban\u0131za Kar\u015f\u0131 Sava\u015f\u0131yor?<\/h3>\n\n\n\n

Yumu\u015fak A36\u2019y\u0131 ele al\u0131n. Akma yakla\u015f\u0131k 36 ksi civar\u0131nda, \u00e7ekme 58\u201370 ksi civar\u0131nda olabilir. Geni\u015f bir aral\u0131k. Boyun verme \u00f6ncesinde plastik deformasyon i\u00e7in bo\u015f alan\u0131n\u0131z vard\u0131r. 8x bir kal\u0131pta hava b\u00fckme yapt\u0131\u011f\u0131n\u0131zda, d\u0131\u015f liflerde akmay\u0131 fazlas\u0131yla ge\u00e7ersiniz. Bol miktarda plastik gerinim olu\u015fur. Geri esneme kontrol edilebilir durumdad\u0131r \u00e7\u00fcnk\u00fc plastik b\u00f6lge elastik \u00e7ekirde\u011fe bask\u0131nd\u0131r.<\/p>\n\n\n\n

\u015eimdi akma\/\u00e7ekme oran\u0131n\u0131n 0,9\u201ca yakla\u015ft\u0131\u011f\u0131 y\u00fcksek dayan\u0131ml\u0131 ala\u015f\u0131mlarla kar\u015f\u0131la\u015ft\u0131r\u0131n. 80 ksi akman\u0131n 88 ksi \u00e7elme de\u011ferine yakla\u015ft\u0131\u011f\u0131 sertifikalar g\u00f6rd\u00fcm. Bu, malzemenin akmaya ba\u015flamas\u0131yla neredeyse hemen s\u0131n\u0131r\u0131na ula\u015ft\u0131\u011f\u0131 anlam\u0131na gelir. \u201dKal\u0131c\u0131 \u015fekil de\u011fi\u015fikli\u011fi\u201c ile \u201dkopma\u201d aras\u0131nda plastik tampon daha azd\u0131r. S\u0131n\u0131rda b\u00fck\u00fcyorsunuz. Elastik k\u0131s\u0131m, toplam gerinimin daha b\u00fcy\u00fck bir pay\u0131n\u0131 al\u0131r. Bo\u015fald\u0131\u011f\u0131nda daha fazla s\u0131\u00e7rama olur.<\/p>\n\n\n\n

Bu nedenle 17-4PH\u2014yakla\u015f\u0131k 950\u20131050 MPa akma, 1100 MPa civar\u0131 \u00e7ekme\u2014disiplinli ama affetmez bir \u00e7\u0131rak gibi davran\u0131r. Y\u00fcksek ve sert akar, fazla akma sonras\u0131 uzama vermez. Hizmette hassas par\u00e7alar i\u00e7in harikad\u0131r. Pres i\u00e7inde zordur. K\u00e2\u011f\u0131t \u00fczerindeki \u00e7ekme de\u011ferleri benzer g\u00f6r\u00fcnd\u00fc\u011f\u00fc i\u00e7in 304 gibi programlarsan\u0131z, yetersiz telafi yapar ve t\u00fcm vardiya boyunca a\u00e7\u0131y\u0131 yakalamaya \u00e7al\u0131\u015f\u0131rs\u0131n\u0131z.<\/p>\n\n\n\n

Ve i\u015fte d\u00fckk\u00e2nlar\u0131n kendilerini kand\u0131rd\u0131\u011f\u0131 nokta: makine ayn\u0131 yanl\u0131\u015f a\u00e7\u0131y\u0131 m\u00fckemmel \u015fekilde tekrar etti\u011finde buna \u201cdo\u011fru\u201d derler. Kontrol\u00f6r i\u015fini yapt\u0131. Siz ona yanl\u0131\u015f muharebe haritas\u0131n\u0131 verdiniz.<\/p>\n\n\n\n

Yani \u00e7ekme mukavemeti size nas\u0131l \u00f6ld\u00fc\u011f\u00fcn\u00fc s\u00f6yler. Akma mukavemeti size nas\u0131l geri s\u0131\u00e7rad\u0131\u011f\u0131n\u0131 s\u00f6yler. Hangisi, y\u00fck alt\u0131ndaki 88\u00b0 i\u00e7in \u00f6nemlidir?<\/p>\n\n\n\n

Tane Y\u00f6n\u00fc Tuza\u011f\u0131: Ayn\u0131 Sac \u00dczerinde Neden Ayn\u0131 Par\u00e7alar Farkl\u0131 Davran\u0131r<\/h3>\n\n\n\n

Bir keresinde ayn\u0131 0,187 in\u00e7lik 5052 ala\u015f\u0131ml\u0131 4\u00d78 sacdan iki braketi kestim. Ayn\u0131 yerle\u015fim, ayn\u0131 kal\u0131nl\u0131k, ayn\u0131 program. Biri tane y\u00f6n\u00fcne dik, di\u011feri y\u00f6n\u00fcyle ayn\u0131 do\u011frultuda b\u00fck\u00fcld\u00fc. \u0130lk olan 90,2\u00b0\u2019ye gev\u015fedi. \u0130kincisi 91,1\u00b0\u2019ye a\u00e7\u0131ld\u0131. M\u00fc\u015fteri tolerans\u0131 \u00b10,5\u00b0 idi. Biri ge\u00e7ti. Di\u011feri ge\u00e7medi.<\/p>\n\n\n\n

Hadvelenen sac izotropik de\u011fildir\u2014bu sadece \u201cher y\u00f6nde ayn\u0131 davranmaz\u201d demenin temiz bir yoludur. Hadvelenme s\u0131ras\u0131nda taneler hadde y\u00f6n\u00fc boyunca uzar. Tane y\u00f6n\u00fcne dik b\u00fckerseniz, bu uzam\u0131\u015f yap\u0131lar\u0131 paralel b\u00fck\u00fclmeye g\u00f6re farkl\u0131 \u015fekillerde germeye zorlars\u0131n\u0131z. Etkili akma mukavemeti y\u00f6nle birlikte hafif\u00e7e de\u011fi\u015fir. \u00c7ok de\u011fil. Sadece, havac\u0131l\u0131k braketlerinde ondal\u0131k derece kovalarken fark yaratacak kadar.<\/p>\n\n\n\n

Geni\u015f V-kal\u0131plarda ince stoklarda\u2014\u00f6rne\u011fin 1 in\u00e7lik bir kal\u0131pta 16 numara sacda\u2014plastik b\u00f6lge zaten s\u0131\u011fd\u0131r. Akma davran\u0131\u015f\u0131ndaki k\u00fc\u00e7\u00fck y\u00f6nsel de\u011fi\u015fiklikler, \u00f6l\u00e7\u00fclebilir esneme farklar\u0131 olarak ortaya \u00e7\u0131kar. E\u011fer d\u00fcz par\u00e7a tasar\u0131mc\u0131n\u0131z, levha verimini art\u0131rmak i\u00e7in par\u00e7alar\u0131 d\u00f6nd\u00fcr\u00fcp b\u00fck\u00fcm y\u00f6n\u00fcn\u00fc belirtmiyorsa, telafi tablonuz haz\u0131rl\u0131ks\u0131z yakalanm\u0131\u015f olur.<\/p>\n\n\n\n

\u00c7elik, nas\u0131l b\u00fck\u00fcld\u00fc\u011f\u00fcn\u00fcz\u00fc hat\u0131rlamadan \u00e7ok \u00f6nce nas\u0131l hadde\u00adlendi\u011fini hat\u0131rlar.<\/p>\n\n\n\n

Yani akma mukavemeti ala\u015f\u0131ma ve y\u00f6ne g\u00f6re de\u011fi\u015fiyorsa, ayn\u0131 ergitme partisinde de\u011fi\u015fti\u011finde ne olur?<\/p>\n\n\n\n

\u00d6ng\u00f6r\u00fclemez Olan\u0131 \u00d6ng\u00f6rmek: S\u00fcneklik Dalgalanmalar\u0131 Tekrarlanabilirli\u011fi Nas\u0131l Sabote Eder<\/h3>\n\n\n\n

Bir grup 10 numara HSLA i\u015flettik; ilk palet +1,5\u00b0 fazla b\u00fckmede temiz \u00e7\u0131kt\u0131. \u0130kinci palet\u2014ayn\u0131 spesifikasyon, ayn\u0131 tedarik\u00e7i\u201490\u00b0\u2019de oturmak i\u00e7in +2,2\u00b0 gerektirdi. Sertifikalar tolerans i\u00e7indeydi. Kal\u0131nl\u0131k \u00f6l\u00e7\u00fcmleri ayn\u0131yd\u0131. Ne de\u011fi\u015fti? Muhtemelen kimya ve so\u011fuma h\u0131z\u0131ndaki mikro farkl\u0131l\u0131klar akmay\u0131 birka\u00e7 ksi art\u0131r\u0131p s\u00fcnekli\u011fi azaltt\u0131.<\/p>\n\n\n\n

Bunu y\u00fczeyde g\u00f6remezsiniz. Ama par\u00e7a yar\u0131m derece daha fazla a\u00e7\u0131ld\u0131\u011f\u0131nda hissedersiniz.<\/p>\n\n\n\n

S\u00fcneklik\u2014malzemenin k\u0131r\u0131lmadan \u00f6nce plastik olarak \u015fekil de\u011fi\u015ftirme kabiliyeti\u2014b\u00fck\u00fcmdeki gerilimin ne kadar\u0131n\u0131n kal\u0131c\u0131, ne kadar\u0131n\u0131n elastik olaca\u011f\u0131n\u0131 belirler. D\u00fc\u015f\u00fck s\u00fcneklik, akmadan hemen sonra \u00e7ekme mukavemetine yakla\u015ft\u0131\u011f\u0131n\u0131z anlam\u0131na gelir. Plastik b\u00f6lge daral\u0131r. Elastik geri kazan\u0131m, toplam gerilimin daha b\u00fcy\u00fck bir b\u00f6l\u00fcm\u00fcn\u00fc olu\u015fturur. Bu nedenle, \u00e7ekme mukavemeti akmaya \u00e7ok yak\u0131n olan y\u00fcksek karbonlu \u00e7elikler zarif\u00e7e geri sekmek yerine \u00e7atlayabilir. Bu t\u00fcr durumlarda sorun \u00e7ok fazla haf\u0131za de\u011fildir. Sorun affedicili\u011fin olmay\u0131\u015f\u0131d\u0131r.<\/p>\n\n\n\n

\u015eimdi tam tersini d\u00fc\u015f\u00fcn\u00fcn. A\u015f\u0131r\u0131 s\u00fcnek metaller gerilimi yerel olarak yo\u011funla\u015ft\u0131rabilir\u2014\u00e7ekme testlerindeki boyun verme bunu a\u00e7\u0131k\u00e7a g\u00f6sterir. B\u00fckmede, kal\u0131p yar\u0131\u00e7ap\u0131 veya y\u00fczey durumu nedeniyle gerilim kal\u0131nl\u0131k boyunca e\u015fit da\u011f\u0131lmazsa, varsayd\u0131\u011f\u0131n\u0131z uniform akma davran\u0131\u015f\u0131 ge\u00e7ersiz olur. Modeliniz ba\u015fka bir \u015fey demi\u015fti. D\u0131\u015f lifler ba\u015fka bir \u015fey yapt\u0131.<\/p>\n\n\n\n

Peki bunu nas\u0131l programlars\u0131n\u0131z?<\/p>\n\n\n\n

Katalog numaras\u0131na g\u00fcvenmezsiniz. Ger\u00e7ek partiden, ger\u00e7ek kal\u0131pta, ger\u00e7ek kal\u0131nl\u0131kta bir test numunesi b\u00fckersiniz. Yapabilirseniz y\u00fck alt\u0131nda \u00f6l\u00e7\u00fcm yap\u0131n. Gerekli ger\u00e7ek fazla b\u00fckmeyi kaydedin. Telafinizi bro\u015f\u00fcrdeki \u00e7ekme mukavemetine de\u011fil, g\u00f6zlemlenen akma davran\u0131\u015f\u0131na g\u00f6re olu\u015fturun. Daha sonra de\u011fi\u015fkenleri \u00fcst \u00fcste y\u0131\u011fmamak i\u00e7in tane y\u00f6n\u00fcn\u00fc ve kal\u0131p se\u00e7imini 8x kal\u0131nl\u0131k kural\u0131yla sabitleyin.<\/p>\n\n\n\n

Kontrol\u00f6r sadece yakla\u015f\u0131k de\u011fer verir. Karar \u00e7eli\u011fin elindedir.<\/p>\n\n\n\n

Ve akman\u0131n ala\u015f\u0131m, y\u00f6n ve s\u00fcneklikle birlikte de\u011fi\u015fen bir hedef oldu\u011funu kabul etti\u011finizde, \u015fu daha keskin soruyu sormaya haz\u0131rs\u0131n\u0131z: b\u00fckme y\u00f6ntemi, o elastik haf\u0131zan\u0131n ne kadar\u0131n\u0131n darbeden sonra kald\u0131\u011f\u0131n\u0131 nas\u0131l de\u011fi\u015ftirir?<\/p>\n\n\n\n

Havada B\u00fckme vs. Tabanlama: Y\u00f6nteminiz Yaylanma Katsay\u0131s\u0131n\u0131 Nas\u0131l De\u011fi\u015ftirir<\/h2>\n\n\n\n

\u00dc\u00e7 Nokta Temas Gizemi: Neden Havada B\u00fckme Sadece Kuvvet De\u011fil, Zeka Gerektirir<\/h3>\n\n\n\n

Tezg\u00e2hta 1 in\u00e7 V-kal\u0131pta b\u00fck\u00fclm\u00fc\u015f 0,125 in\u00e7lik bir 5052 numunem var\u2014tam olarak 8x kal\u0131nl\u0131k kural\u0131na uygun. Y\u00fck alt\u0131nda 88\u00b0 okuyor. Ko\u00e7 yukar\u0131 \u00e7\u0131k\u0131yor. 92,4\u00b0\u2019ye gev\u015fiyor. Bu 4\u00b0\u2019ten fazla bir esneme, ve yaz\u0131m hatas\u0131 de\u011fil. \u0130\u00e7 yar\u0131\u00e7ap b\u00fcy\u00fck oldu\u011funda baz\u0131 al\u00fcminyum partilerinin 5\u00b0\u2019yi ge\u00e7ti\u011fini g\u00f6rd\u00fcm.<\/p>\n\n\n\n

Hava b\u00fck\u00fcm\u00fcnde asl\u0131nda olan \u015fey bu.<\/p>\n\n\n\n

Sac sadece \u00fc\u00e7 noktada tak\u0131mlara temas eder: z\u0131mba ucu ve iki kal\u0131p omzu. A\u00e7\u0131, malzemenin sabit bir bo\u015flu\u011fa uydurulmaya zorlanmas\u0131yla de\u011fil, n\u00fcfuz derinli\u011fiyle olu\u015fur. Bu, kal\u0131nl\u0131\u011f\u0131n \u00e7o\u011funun kar\u0131\u015f\u0131k durumda oldu\u011fu anlam\u0131na gelir\u2014d\u0131\u015f lifler akma s\u0131n\u0131r\u0131n\u0131 ge\u00e7mi\u015f, i\u00e7 \u00e7ekirdek h\u00e2l\u00e2 elastiktir. Bas\u0131nc\u0131 b\u0131rakt\u0131\u011f\u0131n\u0131zda, o elastik \u00e7ekirdek bo\u015fal\u0131r ve b\u00fck\u00fcm\u00fc a\u00e7ar. Ne kadar? Tam olarak o partiye \u00f6zg\u00fc akma davran\u0131\u015f\u0131n\u0131n izin verdi\u011fi kadar.<\/p>\n\n\n\n

Hava b\u00fck\u00fcm, elastiklikle bir pazarl\u0131kt\u0131r.<\/p>\n\n\n\n

Sadece malzemeyi de\u011fi\u015ftirin\u2014A36\u2019dan ayn\u0131 8x kal\u0131pta 70 ksi HSLA\u2019ya ge\u00e7in\u2014ve gerekli a\u015f\u0131r\u0131 b\u00fck\u00fcm birden artar. Geometri de\u011fi\u015fmedi. Tonaj neredeyse hi\u00e7 de\u011fi\u015fmedi. Akma direnci de\u011fi\u015fti. \u0130\u015fte \u00e7arpan\u0131n\u0131z bu. Yumu\u015fak \u00e7elikte 1\u20132\u00b0 a\u015f\u0131r\u0131 b\u00fckme yapabilirsiniz. Y\u00fcksek mukavemetli malzemede 3\u00b0 ola\u011fan d\u0131\u015f\u0131 de\u011fildir. Baz\u0131 al\u00fcminyumlarda daha da fazla.<\/p>\n\n\n\n

Ve i\u015fte at\u00f6lyelerin kendini kand\u0131rd\u0131\u011f\u0131 nokta: e\u011fer makine ayn\u0131 hatal\u0131 a\u00e7\u0131y\u0131 m\u00fckemmel \u015fekilde tekrar ediyorsa, buna \u201cdo\u011fru\u201d derler. CNC sadece varsay\u0131lan akma de\u011ferine dayal\u0131 derinlik ve a\u00e7\u0131 matemati\u011fini bilir. Bu paletin bir \u00f6ncekinden 6 ksi daha y\u00fcksek akmaya sahip oldu\u011funu hissedemez. Hava b\u00fckmeyi bir d\u00fc\u011fmeye basma i\u015flemi gibi g\u00f6r\u00fcrseniz, vardiya boyunca a\u00e7\u0131 kovalars\u0131n\u0131z \u00e7\u00fcnk\u00fc \u00fc\u00e7 nokta temas\u0131 b\u00fck\u00fcm\u00fcn i\u00e7inde b\u00fcy\u00fck bir elastik \u00e7ekirde\u011fin canl\u0131 kalmas\u0131na izin verir.<\/p>\n\n\n\n

Peki elastik \u00e7ekirde\u011fi bilerek azalt\u0131rsak ne olur?<\/p>\n\n\n\n

Hava B\u00fckmeden Kal\u0131ba Oturtmaya Ge\u00e7ti\u011finizde Yaylanma (Springback) Ne Olur?<\/h3>\n\n\n\n

Ayn\u0131 malzeme. Ayn\u0131 kal\u0131nl\u0131k. \u015eimdi par\u00e7a V i\u00e7inde yar\u0131da durmak yerine, z\u0131mbay\u0131 daha derine s\u00fcrerek par\u00e7ay\u0131 kal\u0131p y\u00fczeyleriyle neredeyse tam temas ettiriyorsunuz. Darbeleme de\u011fil\u2014sadece kal\u0131ba oturtma. Z\u0131mba a\u00e7\u0131s\u0131, kal\u0131p a\u00e7\u0131s\u0131ndan biraz daha keskindir, bu y\u00fczden malzeme hedef geometrisine daha yak\u0131n bir \u015fekilde zorlan\u0131r.<\/p>\n\n\n\n

Y\u00fck alt\u0131ndayken metal art\u0131k \u00fc\u00e7 nokta aras\u0131nda y\u00fczm\u00fcyor. Kal\u0131p duvarlar\u0131 boyunca bast\u0131r\u0131lm\u0131\u015f durumda. Kesitin daha fazlas\u0131 akma s\u0131n\u0131r\u0131n\u0131 ge\u00e7iyor \u00e7\u00fcnk\u00fc onu sadece bo\u015flukta e\u011fmek yerine, kal\u0131p a\u00e7\u0131s\u0131na uydurmak i\u00e7in plastik olarak \u015fekillendiriyorsunuz.<\/p>\n\n\n\n

Yaylanma azal\u0131r. S\u0131f\u0131ra de\u011fil. Ama azal\u0131r.<\/p>\n\n\n\n

E\u011fer 0.125 in\u00e7 \u00e7eli\u011fi hava b\u00fckmede 2\u00b0 a\u015f\u0131r\u0131 b\u00fckmeye ihtiyac\u0131n\u0131z varsa, kal\u0131ba oturtma bunu 1\u00b0\u2019nin alt\u0131na indirebilir. \u00c7arpan k\u00fc\u00e7\u00fcl\u00fcr \u00e7\u00fcnk\u00fc kal\u0131nl\u0131\u011f\u0131n elastik k\u0131sm\u0131 azal\u0131r. Daha fazla molek\u00fcler haf\u0131zay\u0131 bask\u0131 alt\u0131na alm\u0131\u015f olursunuz.<\/p>\n\n\n\n

Ama kendinizi kand\u0131rmay\u0131n\u2014kal\u0131ba oturtma yaylanmadan tamamen ar\u0131nm\u0131\u015f de\u011fildir. Z\u0131mba ve kal\u0131p h\u00e2l\u00e2 malzemeyi d\u00f6vme i\u015flemi gibi t\u00fcm kal\u0131nl\u0131\u011f\u0131 boyunca s\u0131k\u0131\u015ft\u0131rmaz. \u00c7ekirdekte h\u00e2l\u00e2 elastik gerilme depolan\u0131r. Bu nedenle kal\u0131ba oturtma kurulumlar\u0131 genellikle bir veya iki derece daha keskin ta\u015flanm\u0131\u015f tak\u0131mlar kullan\u0131r. Baz\u0131 geri d\u00f6n\u00fc\u015f olaca\u011f\u0131n\u0131 bildikleri i\u00e7in mekanik olarak \u00f6nceden telafi ederler.<\/p>\n\n\n\n

Ve i\u015fte \u201cher \u015fey makine kalitesiyle ilgili\u201d diyenleri rahats\u0131z eden k\u0131s\u0131m: kal\u0131ba oturtma, daha eski, gev\u015fek bir presi oldu\u011fundan daha iyi g\u00f6sterebilir. Malzemeyi kal\u0131p a\u00e7\u0131s\u0131na zorlayarak, hassas derinlik kontrol\u00fcne ba\u011f\u0131ml\u0131l\u0131\u011f\u0131 azalt\u0131rs\u0131n\u0131z. Zeka yerine tonaj ve temas koyars\u0131n\u0131z.<\/p>\n\n\n\n

Bu i\u015fe yarar\u2014bir yere kadar.<\/p>\n\n\n\n

Daha y\u00fcksek \u015fekillendirme bas\u0131nc\u0131, daha fazla tak\u0131m a\u015f\u0131nmas\u0131, kozmetik par\u00e7alarda g\u00f6r\u00fcn\u00fcr kal\u0131p izleri ve makine g\u00f6vdesine daha fazla y\u00fck olarak bedelini \u00f6dersiniz. At\u00f6lyelerde g\u00fcn boyu 10 \u00f6l\u00e7\u00fc paslanmaz\u0131 kal\u0131ba oturtup sonra y\u0131llar boyunca ko\u00e7 paralelli\u011finin neden kayd\u0131\u011f\u0131n\u0131 merak ettiklerini g\u00f6rd\u00fcm. \u00c7elik unutmaz. Presiniz de \u00f6yle.<\/p>\n\n\n\n

Yani kal\u0131ba oturtma, daha fazla akma s\u0131n\u0131r\u0131n\u0131 a\u015farak yaylanmay\u0131 azalt\u0131yorsa, peki t\u00fcm yolu giderseniz ne olur?<\/p>\n\n\n\n

A\u015f\u0131r\u0131 Hassasiyet i\u00e7in Darbeleme (Coining): Tonaj Maliyeti Ger\u00e7ekten Kar\u015f\u0131l\u0131\u011f\u0131n\u0131 Verdi\u011finde<\/h3>\n\n\n\n

Art\u0131k pazarl\u0131k yok. Eziyoruz.<\/p>\n\n\n\n

Darbeleme, z\u0131mba ucunu malzemeye, kal\u0131nl\u0131k boyunca t\u00fcm b\u00fck\u00fcm b\u00f6lgesini plastik olarak \u015fekillendirecek kadar bas\u0131n\u00e7la bat\u0131r\u0131r. Tonaj, hava b\u00fckmeye g\u00f6re be\u015f ila on kat artabilir. Sadece bir a\u00e7\u0131 olu\u015fturmuyorsunuz\u2014onu damgal\u0131yorsunuz. \u0130\u00e7 yar\u0131\u00e7ap, z\u0131mba yar\u0131\u00e7ap\u0131 h\u00e2line gelir \u00e7\u00fcnk\u00fc malzeme temas b\u00f6lgesinde tamamen akma s\u0131n\u0131r\u0131n\u0131 a\u015far.<\/p>\n\n\n\n

Elastik haf\u0131zan\u0131n saklanacak yeri kalmaz.<\/p>\n\n\n\n

Geri esneme neredeyse ihmal edilebilir hale gelir, \u00e7\u00fcnk\u00fc esnek \u00e7ekirdek b\u00fckme b\u00f6lgesinde b\u00fcy\u00fck \u00f6l\u00e7\u00fcde ortadan kald\u0131r\u0131lm\u0131\u015ft\u0131r. Malzeme daha geni\u015f bir a\u00e7\u0131ya \u201cgeri gev\u015feyemez\u201d; \u00e7\u00fcnk\u00fc kal\u0131nl\u0131\u011f\u0131n\u0131n b\u00fcy\u00fck k\u0131sm\u0131nda akma s\u0131n\u0131r\u0131n\u0131 a\u015facak kadar ileriye itilmi\u015ftir.<\/p>\n\n\n\n

Bu y\u00fczden \u00b10,25\u00b0 hassasiyetin ger\u00e7ekten \u00f6nemli oldu\u011fu ve \u00fcretim hacimlerinin y\u00fck\u00fc hakl\u0131 \u00e7\u0131kard\u0131\u011f\u0131 dar toleransl\u0131 havac\u0131l\u0131k ba\u011flant\u0131 par\u00e7alar\u0131nda d\u00f6vme i\u015flemi kullan\u0131lmaktad\u0131r. Operat\u00f6r programda iki derecelik fazla b\u00fckme ekler \u2014 elastik toparlanmadan sonra par\u00e7an\u0131n 90\u00b0\u2019ye oturmas\u0131 i\u00e7in daha derine iter \u2014 bu hava b\u00fckme i\u015flemidir. D\u00f6vmede ise bu dengeleme neredeyse yok olur, \u00e7\u00fcnk\u00fc geometrisi mekanik olarak kilitlenmi\u015ftir.<\/p>\n\n\n\n

Ancak bu hassasiyeti bedavaya elde edemezsiniz.<\/p>\n\n\n\n

Gerekli tonaj, makinenin s\u0131n\u0131rlar\u0131na yakla\u015fabilir. Kal\u0131plar a\u015f\u0131r\u0131 temas gerilimine maruz kal\u0131r. Y\u00fczey kalitesi zarar g\u00f6rebilir. Bak\u0131m aral\u0131klar\u0131 k\u0131sal\u0131r. Ak\u0131ll\u0131 dengeleme ve uygun 8x kal\u0131p se\u00e7imiyle hava b\u00fckme yap\u0131labilecek par\u00e7alar\u0131 d\u00f6v\u00fcyorsan\u0131z, beyin g\u00fcc\u00fc yerine kaba kuvvet kullan\u0131yor ve yar\u0131m milyon dolarl\u0131k bir yat\u0131r\u0131m\u0131 y\u0131prat\u0131yorsunuz demektir.<\/p>\n\n\n\n

A\u00e7\u0131 de\u011fi\u015fiminin maliyeti tonaj ve a\u015f\u0131nma maliyetini a\u015ft\u0131\u011f\u0131nda d\u00f6vme anlam kazan\u0131r. Bu, g\u00f6steri\u015f de\u011fil, stratejik bir karard\u0131r.<\/p>\n\n\n\n

Art\u0131k yelpazeyi g\u00f6rd\u00fcn\u00fcz: hava b\u00fckme b\u00fcy\u00fck bir esnek \u00e7ekirdek b\u0131rak\u0131r, tabanlama bunu azalt\u0131r, d\u00f6vme ise neredeyse tamamen ortadan kald\u0131r\u0131r. Ayn\u0131 malzeme. Ayn\u0131 akma davran\u0131\u015f\u0131. Farkl\u0131 miktarda molek\u00fcler haf\u0131zan\u0131n korunmas\u0131na izin verilir.<\/p>\n\n\n\n

E\u011fer y\u00f6ntem, ne kadar haf\u0131zan\u0131n kald\u0131\u011f\u0131n\u0131 de\u011fi\u015ftiriyorsa, bir sonraki kald\u0131ra\u00e7 kuvvet de\u011fildir.<\/p>\n\n\n\n

Geometridir.<\/p>\n\n\n\n

V-Kal\u0131p ve Z\u0131mba \u0130kilemi: Kuvvet ile \u015eekil Aras\u0131ndaki Aray\u00fcz\u00fcn M\u00fchendisli\u011fi<\/h2>\n\n\n\n

0,125 in\u00e7 kal\u0131nl\u0131\u011f\u0131nda 5052 malzemesini 1 in\u00e7lik bir V kal\u0131ba koyun ve 90\u00b0 hava b\u00fckme yap\u0131n. Muhtemelen 3\u20134\u00b0 geri esneme g\u00f6receksiniz. Sadece kal\u0131b\u0131 0,75 in\u00e7 a\u00e7\u0131kl\u0131\u011fa de\u011fi\u015ftirin ve ayn\u0131 derinlik program\u0131n\u0131 \u00e7al\u0131\u015ft\u0131r\u0131n. A\u00e7\u0131 de\u011fi\u015fir. Tonaj de\u011fi\u015fir. Geri esneme de\u011fi\u015fir. Ayn\u0131 makine. Ayn\u0131 operat\u00f6r. Ayn\u0131 malzeme.<\/p>\n\n\n\n

Peki ne de\u011fi\u015fti?<\/p>\n\n\n\n

Aray\u00fcz. V kal\u0131p ve z\u0131mba, kuvvetin kal\u0131nl\u0131k boyunca gerinim da\u011f\u0131l\u0131m\u0131na d\u00f6n\u00fc\u015ft\u00fc\u011f\u00fc yerdir. Hava b\u00fckmede bu da\u011f\u0131l\u0131m \u00fc\u00e7 nokta taraf\u0131ndan belirlenir: z\u0131mba ucu ve kal\u0131p omuzlar\u0131. V a\u00e7\u0131kl\u0131\u011f\u0131n\u0131 de\u011fi\u015ftirirseniz, do\u011fal olarak olu\u015fan b\u00fckme yar\u0131\u00e7ap\u0131n\u0131 de\u011fi\u015ftirirsiniz. Yar\u0131\u00e7ap de\u011fi\u015fti\u011finde, kesitin ne kadar\u0131n\u0131n akma s\u0131n\u0131r\u0131n\u0131 a\u015ft\u0131\u011f\u0131n\u0131 ve ne kadar\u0131n\u0131n \u00e7ekirdekte esnek kald\u0131\u011f\u0131n\u0131 da de\u011fi\u015ftirirsiniz. Bu esnek \u00e7ekirdek, bahsetti\u011fimiz \u201cbellek\u201dtir.<\/p>\n\n\n\n

Kal\u0131p geometrisi sadece par\u00e7an\u0131n \u015feklini belirlemez. \u00c7\u0131rakl\u0131\u011f\u0131n ne kadar\u0131n\u0131n dersi hat\u0131rlayaca\u011f\u0131n\u0131 da belirler.<\/p>\n\n\n\n

Ve e\u011fer CNC\u2019nin k\u00f6t\u00fc bir kal\u0131p se\u00e7imini telafi edebilece\u011fini d\u00fc\u015f\u00fcn\u00fcyorsan\u0131z, pahal\u0131 oyuncaklar\u0131 olan bir d\u00fc\u011fme bas\u0131c\u0131s\u0131na d\u00f6nm\u00fc\u015fs\u00fcn\u00fcz demektir.<\/p>\n\n\n\n

8 Kat Kural\u0131n\u0131n Yeniden De\u011ferlendirilmesi: V A\u00e7\u0131kl\u0131klar\u0131n\u0131 Sadece Kal\u0131nl\u0131\u011fa De\u011fil, Malzeme Davran\u0131\u015f\u0131na G\u00f6re Se\u00e7mek<\/h3>\n\n\n\n

Yeni ba\u015flayan birinin 0,125 in\u00e7 \u00e7elik i\u00e7in \u201chep bunu kullan\u0131yoruz\u201d diyerek 1 in\u00e7lik kal\u0131p ald\u0131\u011f\u0131n\u0131 g\u00f6rd\u00fcm. Yan\u0131lm\u0131yordu. Sadece nedenini bilmiyordu.<\/p>\n\n\n\n

8\u00d7 kural\u0131, yumu\u015fak \u00e7elikte hava b\u00fckme s\u0131ras\u0131nda V kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131n\u0131n malzeme kal\u0131nl\u0131\u011f\u0131n\u0131n yakla\u015f\u0131k sekiz kat\u0131 olmas\u0131 gerekti\u011fini s\u00f6yler. 0,125 in\u00e7 i\u00e7in bu 1,000 in\u00e7tir. Bu bir efsane de\u011fildir. Bu, geometridir ve gerinim kontrol\u00fcd\u00fcr. Yakla\u015f\u0131k 8\u00d7 oran\u0131nda, do\u011fal olarak olu\u015fan i\u00e7 b\u00fckme yar\u0131\u00e7ap\u0131 V a\u00e7\u0131kl\u0131\u011f\u0131n\u0131n yakla\u015f\u0131k 0,16\u2019s\u0131d\u0131r. Yani 1 in\u00e7lik bir kal\u0131p size yakla\u015f\u0131k 0,160 in\u00e7lik bir i\u00e7 yar\u0131\u00e7ap verir. Bu yar\u0131\u00e7ap \u00f6ng\u00f6r\u00fclebilir bir gerinim gradyan\u0131 \u00fcretir: i\u00e7 y\u00fczeye yak\u0131n plastik, n\u00f6tr eksene do\u011fru esnek, yayg\u0131n akma de\u011ferleri i\u00e7in y\u00f6netilebilir geri esneme.<\/p>\n\n\n\n

\u015eimdi ayn\u0131 kal\u0131nl\u0131kta 70 ksi HSLA malzeme kullan\u0131n. Akma dayan\u0131m\u0131 daha y\u00fcksektir. Bu da ayn\u0131 yar\u0131\u00e7ap i\u00e7in, kal\u0131nl\u0131\u011f\u0131n daha k\u00fc\u00e7\u00fck bir k\u0131sm\u0131n\u0131n akma s\u0131n\u0131r\u0131n\u0131 a\u015faca\u011f\u0131 anlam\u0131na gelir. Esnek \u00e7ekirde\u011finiz b\u00fcy\u00fcr. Geri esneme artar.<\/p>\n\n\n\n

At\u00f6lyeler tam da burada kendilerini kand\u0131r\u0131rlar. \u201cKal\u0131nl\u0131k de\u011fi\u015fmedi\u201d diyerek 8\u00d7 kal\u0131b\u0131 kullanmaya devam ederler, sonra t\u00fcm vardiya boyunca a\u00e7\u0131y\u0131 derinlik ayarlar\u0131yla kovalarlar.<\/p>\n\n\n\n

8\u00d7 kural\u0131, yumu\u015fak \u00e7eli\u011fin davran\u0131\u015f\u0131na g\u00f6re olu\u015fturulmu\u015ftur. Bu bir ba\u015flang\u0131\u00e7 noktas\u0131d\u0131r, emir de\u011fildir.<\/p>\n\n\n\n

Daha y\u00fcksek akma dayan\u0131ml\u0131 malzemelerde, kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131n\u0131n s\u0131k\u0131la\u015ft\u0131r\u0131lmas\u0131\u2014\u00f6rne\u011fin 8\u00d7\u2019ten 6\u00d7\u2019e ge\u00e7mek\u2014do\u011fal i\u00e7 yar\u0131\u00e7ap\u0131 azalt\u0131r. Daha k\u00fc\u00e7\u00fck yar\u0131\u00e7ap y\u00fczey gerilimini art\u0131r\u0131r. Kal\u0131nl\u0131\u011f\u0131n daha b\u00fcy\u00fck bir k\u0131sm\u0131 akma s\u0131n\u0131r\u0131n\u0131 a\u015far. Elastik \u00e7ekirdek k\u00fc\u00e7\u00fcl\u00fcr. Geri yaylanma azal\u0131r. Ancak tonaj h\u0131zla artar ve y\u00fczey gerilimi k\u0131r\u0131lma s\u0131n\u0131rlar\u0131na yakla\u015f\u0131r. Al\u00fcminyumda, \u00f6zellikle tane y\u00f6n\u00fcne dik b\u00fckmelerde, a\u00e7\u0131 kararl\u0131l\u0131\u011f\u0131 elde etmeye \u00e7al\u0131\u015f\u0131rken \u00e7atlak riski sat\u0131n al\u0131rs\u0131n\u0131z.<\/p>\n\n\n\n

Ger\u00e7ek soru \u201cKal\u0131nl\u0131k nedir?\u201d de\u011fil. Ger\u00e7ek soru \u201cHangi akma dayan\u0131m\u0131n\u0131 y\u00f6netiyorum ve kal\u0131nl\u0131k boyunca ne kadar plastik n\u00fcfuziyet elde etmem gerekiyor?\u201d sorusudur.\u201d<\/p>\n\n\n\n

8\u00d7 kural\u0131n\u0131 tamamen g\u00f6rmezden gelin ve emin olun \u00e7elik sizi sert bir \u015fekilde e\u011fitir. K\u00f6r\u00fc k\u00f6r\u00fcne uygulay\u0131n, ayn\u0131 sonucu al\u0131rs\u0131n\u0131z.<\/p>\n\n\n\n

Bu bizi \u00e7o\u011fu ki\u015finin asla hesaplamad\u0131\u011f\u0131 \u015feye getiriyor.<\/p>\n\n\n\n

V-Kal\u0131p Geni\u015fli\u011fi \u00c7arpan Etkisi: 10% Kal\u0131p De\u011fi\u015fiminin 40% Kuvvet Dalgalanmas\u0131 Yaratmas\u0131<\/h3>\n\n\n\n

Ayn\u0131 0.125 in\u00e7lik sac\u0131 1.000 in\u00e7lik bir kal\u0131pta kullan\u0131n. \u015eimdi kal\u0131b\u0131 0.900 in\u00e7e daralt\u0131n. Bu, 10% oran\u0131nda bir a\u00e7\u0131kl\u0131k azalmas\u0131d\u0131r.<\/p>\n\n\n\n

Hava b\u00fckme tonaj\u0131 kal\u0131p geni\u015fli\u011fiyle ters orant\u0131l\u0131d\u0131r. Kabaca T \u221d 1\/V denebilir. V de\u011ferini 10% kadar k\u00fc\u00e7\u00fclt\u00fcn, tonaj azalmaz\u2014yakla\u015f\u0131k 11% artar. Bu, temiz matematiksel sonu\u00e7tur.<\/p>\n\n\n\n

Ama hik\u00e2yenin tamam\u0131 bu de\u011fil.<\/p>\n\n\n\n

\u00c7\u00fcnk\u00fc daha k\u00fc\u00e7\u00fck kal\u0131p ayn\u0131 zamanda olu\u015fan i\u00e7 yar\u0131\u00e7ap\u0131 da k\u00fc\u00e7\u00fclt\u00fcr. K\u00fc\u00e7\u00fck yar\u0131\u00e7ap, i\u00e7 y\u00fczeyde daha y\u00fcksek gerilim demektir. Daha y\u00fcksek gerilim ise daha fazla plastik deformasyon anlam\u0131na gelir. Ayn\u0131 a\u00e7\u0131y\u0131 elde etmek i\u00e7in, \u00f6zellikle y\u00fcksek akma dayan\u0131ml\u0131 malzemelerde, genellikle basit 1\/V denkleminin \u00f6ng\u00f6rd\u00fc\u011f\u00fcnden daha derin b\u00fckmeniz gerekir. Ger\u00e7ek d\u00fcnyada kuvvet art\u0131\u015f\u0131, malzeme ve hedef a\u00e7\u0131ya ba\u011fl\u0131 olarak \u201340 aras\u0131nda hissedilebilir.<\/p>\n\n\n\n

Bir at\u00f6lyede, 10-gauge A36 \u00e7eli\u011finde \u201ca\u00e7\u0131y\u0131 s\u0131k\u0131la\u015ft\u0131rmak\u201d i\u00e7in 1 in\u00e7lik kal\u0131ptan 0.875 in\u00e7lik kal\u0131ba ge\u00e7ildi\u011fini g\u00f6rd\u00fcm. Pres fren y\u00fck g\u00f6stergesi, rahatten makinenin nominal tonaj s\u0131n\u0131r\u0131n\u0131n e\u015fi\u011fine geldi. Ayn\u0131 par\u00e7a \u00e7izimi. Ayn\u0131 kal\u0131nl\u0131k. Farkl\u0131 geometridir. Makine zay\u0131flamad\u0131. Kal\u0131p darald\u0131.<\/p>\n\n\n\n

\u015eimdi y\u00f6ntemi de i\u015fin i\u00e7ine kat\u0131n. Taban b\u00fckme (bottoming) zaten yakla\u015f\u0131k 1,5\u00d7 daha fazla hava b\u00fckme tonaj\u0131 ister. Konumlama (coining) 5\u00d7 gerektirebilir. Kal\u0131b\u0131 daralt\u0131p ayn\u0131 anda y\u00f6ntemi de a\u011f\u0131rla\u015ft\u0131r\u0131rsan\u0131z, \u00e7arpanlar katlan\u0131r ve tak\u0131m, pimler, \u00e7er\u00e7eveler strese girer. E\u011fer malzeme partisi y\u00fcksek akma de\u011ferine sahipse, d\u00fczg\u00fcn tablolar\u0131n\u0131zdaki rakamlar u\u00e7ar gider.<\/p>\n\n\n\n

\u0130\u015fte bu y\u00fczden yepyeni bir makine \u201ca\u00e7\u0131 tutars\u0131zl\u0131\u011f\u0131\u201d i\u00e7in su\u00e7lan\u0131r, oysa as\u0131l sorun kuvvet ve gerilme da\u011f\u0131l\u0131m\u0131n\u0131 i\u015flem s\u0131n\u0131r\u0131n\u0131n \u00f6tesine ta\u015f\u0131yan kal\u0131p se\u00e7imidir.<\/p>\n\n\n\n

Ve kuvvet, aray\u00fcz\u00fcn yaln\u0131zca yar\u0131s\u0131d\u0131r.<\/p>\n\n\n\n

Punch (Z\u0131mba) Yar\u0131\u00e7ap\u0131 Se\u00e7imi: \u201cKeskin B\u00fck\u00fcm\u201d Gerilme \u00c7atla\u011f\u0131ndan Ka\u00e7\u0131nmak<\/h3>\n\n\n\n

Bir keresinde 0.090 in\u00e7lik 304 paslanmaz \u00e7elikten bir brakette neredeyse s\u0131f\u0131r i\u00e7 yar\u0131\u00e7ap belirtilmi\u015fti. Programc\u0131, a\u00e7\u0131y\u0131 \u201ckilitlemek\u201d ve geri yaylanmayla m\u00fccadele etmek i\u00e7in keskin bir z\u0131mba ucu se\u00e7ti. \u0130lk on par\u00e7a iyi g\u00f6r\u00fcn\u00fcyordu. On birincide i\u00e7 b\u00fck\u00fcmde sa\u00e7 teli inceli\u011finde bir \u00e7atlak belirdi.<\/p>\n\n\n\n

Neden?<\/p>\n\n\n\n

Keskin z\u0131mba ucu, gerilimi i\u00e7 y\u00fczeyde yo\u011funla\u015ft\u0131r\u0131r. B\u00fck\u00fclmede gerilme yakla\u015f\u0131k olarak kal\u0131nl\u0131\u011f\u0131n i\u00e7 yar\u0131\u00e7ap\u0131n iki kat\u0131na b\u00f6l\u00fcnmesine e\u015fittir. Yar\u0131\u00e7ap\u0131 k\u00fc\u00e7\u00fcltt\u00fck\u00e7e y\u00fczey gerilimi h\u0131zla artar. Y\u00fcksek dayan\u0131ml\u0131 veya d\u00fc\u015f\u00fck s\u00fcneklikli malzemelerde, kal\u0131nl\u0131\u011f\u0131n geri kalan\u0131 anlaml\u0131 \u015fekilde akmadan \u00f6nce uzama s\u0131n\u0131rlar\u0131n\u0131 a\u015fabilirsiniz. Bu durumda, kararl\u0131l\u0131ktan \u00f6nce \u00e7atlak elde edersiniz.<\/p>\n\n\n\n

Di\u011fer yandan, z\u0131mba yar\u0131\u00e7ap\u0131n\u0131 fazla b\u00fcy\u00fck se\u00e7erseniz\u2014klasik yar\u0131\u00e7ap b\u00fck\u00fcmde oldu\u011fu gibi\u2014en y\u00fcksek y\u00fczey gerilimini o kadar azalt\u0131rs\u0131n\u0131z ki, kal\u0131n bir elastik \u00e7ekirdek kal\u0131r. Geri yaylanma \u00f6ng\u00f6r\u00fclemez hale gelir. Geri d\u00f6n\u00fc\u015f flan\u015f\u0131 olmayan \u00e7oklu b\u00fck\u00fcml\u00fc par\u00e7alarda, her b\u00fck\u00fcmde 2\u00b0 fark d\u00f6rt b\u00fck\u00fcmde 8\u00b0\u201cye ula\u015fabilir. Tek darbe ile \u201dg\u00fcvenli\u201d g\u00f6r\u00fcnen geometriler, ard\u0131\u015f\u0131k i\u015flemde tolerans felaketine d\u00f6n\u00fc\u015f\u00fcr.<\/p>\n\n\n\n

Peki \u00e7\u00f6z\u00fcm nedir?<\/p>\n\n\n\n

Z\u0131mba yar\u0131\u00e7ap\u0131n\u0131 malzeme s\u00fcnekli\u011fine ve hedef i\u00e7 yar\u0131\u00e7apa g\u00f6re ayarlay\u0131n; \u201ckeskin e\u015fittir hassas\u201d anlay\u0131\u015f\u0131na g\u00f6re de\u011fil. Hava b\u00fckmede, z\u0131mba yar\u0131\u00e7ap\u0131 se\u00e7ilen V kal\u0131b\u0131n\u0131n olu\u015fturdu\u011fu do\u011fal yar\u0131\u00e7apla ayn\u0131 veya ondan k\u00fc\u00e7\u00fck olmal\u0131d\u0131r. Bu, temas ko\u015fullar\u0131n\u0131 dengede tutar ve a\u015f\u0131r\u0131 gerilimi \u00f6nler. Do\u011fal olarak olu\u015fan yar\u0131\u00e7aptan daha s\u0131k\u0131 bir i\u00e7 yar\u0131\u00e7ap istiyorsan\u0131z, sadece jilet gibi keskin bir z\u0131mba kullanmay\u0131n\u2014kal\u0131p geni\u015fli\u011fini, y\u00f6ntemi tekrar g\u00f6zden ge\u00e7irin ya da telafili z\u0131mba a\u00e7\u0131s\u0131yla kontroll\u00fc taban b\u00fckmeye ge\u00e7in.<\/p>\n\n\n\n

7\u00b0 geri yaylanma vakas\u0131n\u0131n, tonaj\u0131 art\u0131rarak veya kal\u0131b\u0131 daraltarak de\u011fil, 83\u00b0 z\u0131mba ile hassas taban b\u00fckme uygulanarak \u00e7\u00f6z\u00fcld\u00fc\u011f\u00fcn\u00fc g\u00f6rd\u00fcm. B\u00f6ylece plastik ak\u0131\u015f hedef geometrisiyle e\u015fle\u015fti. Telafiyi kuvvet de\u011fil, geometrinin kendisi sa\u011flad\u0131.<\/p>\n\n\n\n

Kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131 belirler. Z\u0131mba, gerilme yo\u011funla\u015fmas\u0131n\u0131 belirler. Birlikte, kal\u0131nl\u0131\u011f\u0131n ne kadar\u0131n\u0131n akaca\u011f\u0131n\u0131 ve ne kadar\u0131n\u0131n hat\u0131rlayaca\u011f\u0131n\u0131 belirlerler.<\/p>\n\n\n\n

Ve bir kez tonaj\u0131 art\u0131r\u0131p o \u201chaf\u0131zay\u0131\u201d kontrol etmek i\u00e7in aral\u0131klar\u0131 daraltmaya ba\u015flad\u0131\u011f\u0131n\u0131zda, art\u0131k sadece malzeme ile pazarl\u0131k yapm\u0131yorsunuz\u2014makine yap\u0131s\u0131n\u0131 da y\u00fckl\u00fcyorsunuz. Bu da bizi, kal\u0131p de\u011fil, \u00e7er\u00e7eve zay\u0131f halka oldu\u011funda neler oldu\u011funa getiriyor.<\/p>\n\n\n\n

Ta\u00e7 D\u00fczeltmesi: Makine Sapmas\u0131n\u0131 Ba\u015flamadan \u00d6nce N\u00f6tralize Etmek<\/h2>\n\n\n\n

175 tonluk bir prese tak\u0131lm\u0131\u015f 1 in\u00e7lik V kal\u0131pta, 0.125 in\u00e7 kal\u0131nl\u0131\u011f\u0131ndaki 5052 malzemenin 12 fitlik hava b\u00fck\u00fcm\u00fc. Merkez 90\u00b0 okuyor. Her iki u\u00e7taki son 6 in\u00e7 92\u00b0 okuyor. Ayn\u0131 program. Ayn\u0131 z\u0131mba. Ayn\u0131 operat\u00f6r.<\/p>\n\n\n\n

Bu, etrafta dola\u015fan geri esneme (springback) de\u011fil. Bu, y\u00fck alt\u0131nda makinenin sarkmas\u0131d\u0131r.<\/p>\n\n\n\n

Tonaj\u0131 art\u0131rd\u0131\u011f\u0131n\u0131zda\u2014dar kal\u0131p, y\u00fcksek akma de\u011ferli parti, o elastik \u00e7ekirde\u011fi dizginlemek i\u00e7in daha derin penetrasyon\u2014art\u0131k sadece sacla pazarl\u0131k etmiyorsunuz. Kiri\u015f gibi, ko\u00e7 ve tabla \u00fczerine y\u00fck bindiriyorsunuz. U\u00e7lardan sabitlenmi\u015f \u00e7elik \u00e7er\u00e7eve, ortada kuvvet. Temel mekanik: kiri\u015fler en \u00e7ok ortada sapar. Makine ortada a\u015fa\u011f\u0131 do\u011fru saparsa, z\u0131mban\u0131n kal\u0131ba g\u00f6re penetrasyonu ortada u\u00e7lardan daha az olur. Daha az penetrasyon, daha a\u00e7\u0131k a\u00e7\u0131 demektir.<\/p>\n\n\n\n

Peki o \u00f6rnekte neden merkez s\u0131k\u0131 \u00e7\u0131kt\u0131?<\/p>\n\n\n\n

\u00c7\u00fcnk\u00fc at\u00f6lye, \u00f6nceki i\u015ften mekanik ta\u00e7 ayar\u0131n\u0131 korumu\u015ftu\u2014daha hafif malzeme i\u00e7in fazla telafi edilmi\u015fti. Tabla yukar\u0131 do\u011fru \u00f6n kamberliydi. Daha a\u011f\u0131r y\u00fck alt\u0131nda, \u00e7er\u00e7eve sarkmas\u0131 ve \u00f6n y\u00fck birbirini tutmad\u0131. Sapma e\u011frisi de\u011fi\u015fti ama d\u00fczeltme de\u011fi\u015fmedi. Sonu\u00e7 rastgele de\u011fildi. \u00d6ng\u00f6r\u00fclebilirdi.<\/p>\n\n\n\n

Ve i\u015fte at\u00f6lyelerin kendilerini kand\u0131rd\u0131\u011f\u0131 yer: makine ayn\u0131 yanl\u0131\u015f a\u00e7\u0131y\u0131 m\u00fckemmel \u015fekilde tekrarlarsa, buna \u201cdo\u011fru\u201d derler.\u201d<\/p>\n\n\n\n

Tekrarlanabilirlik geometri de\u011fildir. Sadece tutarl\u0131 hatad\u0131r.<\/p>\n\n\n\n

Bir sonraki ad\u0131m do\u011frudan ekiple konu\u015fmaksa, Bize ula\u015f\u0131n<\/a> buraya do\u011fal \u015fekilde oturur.<\/p>\n\n\n\n

E\u011fer tak\u0131m geometrisi gerilme da\u011f\u0131l\u0131m\u0131n\u0131 kal\u0131nl\u0131k boyunca belirliyorsa, \u00e7er\u00e7eve sapmas\u0131 bu gerilmenin uzunluk boyunca ne kadar e\u015fit uyguland\u0131\u011f\u0131n\u0131 belirler. Bu ikisinden birini ka\u00e7\u0131r\u0131rsan\u0131z, malzemenin haf\u0131zas\u0131yla yapt\u0131\u011f\u0131n\u0131z pazarl\u0131k geri esneme daha konu\u015fmaya girmeden da\u011f\u0131l\u0131r.<\/p>\n\n\n\n

Merkez vs. U\u00e7lar: Neden B\u00fck\u00fcm A\u00e7\u0131n\u0131z Tabla Boyunca De\u011fi\u015fir<\/h3>\n\n\n\n

Basit bir modeli hayal edin. Yan \u00e7er\u00e7eveler aras\u0131nda on iki fit. Ram, b\u00fck\u00fcm hatt\u0131 boyunca toplam 120 ton a\u015fa\u011f\u0131 do\u011fru bas\u0131yor. Kiri\u015f gibi davran\u0131n: merkezdeki sapma uzunlu\u011fun k\u00fcp\u00fcyle ve y\u00fckle do\u011fru orant\u0131l\u0131 artar. Tonaj\u0131 ikiye katlay\u0131n, sapma da ikiye katlan\u0131r. B\u00fck\u00fcm uzunlu\u011funu art\u0131r\u0131n, sapma h\u0131zla y\u00fckselir.<\/p>\n\n\n\n

\u015eimdi malzeme ger\u00e7ekli\u011fini katmanlay\u0131n.<\/p>\n\n\n\n

\u00c7ekme mukavemetindeki 10%\u2019lik bir art\u0131\u015f, ayn\u0131 a\u00e7\u0131y\u0131 elde etmek i\u00e7in yakla\u015f\u0131k 10% daha fazla kuvvet gerektirir. Kal\u0131nl\u0131k 10% artarsa, tonaj yakla\u015f\u0131k 20%\u2019ya kadar s\u0131\u00e7rayabilir \u00e7\u00fcnk\u00fc b\u00fckme kuvveti kal\u0131nl\u0131\u011f\u0131n karesiyle orant\u0131l\u0131d\u0131r. Bu ekstra kuvvet sadece penetrasyonu de\u011fi\u015ftirmez\u2014y\u00fck alt\u0131nda \u00e7er\u00e7eve \u015feklini de\u011fi\u015ftirir.<\/p>\n\n\n\n

E\u011fer ta\u00e7 sistemi daha hafif parti i\u00e7in ayarlanm\u0131\u015fsa, yeni y\u00fck profili farkl\u0131 bir sapma e\u011frisi olu\u015fturur. Merkez a\u00e7\u0131l\u0131r, u\u00e7lar s\u0131k\u0131 kal\u0131r ya da yatak nas\u0131l \u00f6n y\u00fcklenmi\u015fse tersine olur.<\/p>\n\n\n\n

Ayn\u0131 \u00e7izimde A36 yerine 70 ksi HSLA kullan\u0131ld\u0131\u011f\u0131n\u0131 g\u00f6rd\u00fcm. Ayn\u0131 8\u00d7 kal\u0131p. Ayn\u0131 programlanm\u0131\u015f derinlik. Operat\u00f6r, programa iki derece fazla b\u00fck\u00fcm ekledi\u2014elastik geri kazan\u0131mdan sonra par\u00e7a 90\u00b0\u2019ye gev\u015fesin diye daha derin s\u00fcr\u00fcyor. U\u00e7lar iyi \u00e7\u0131kt\u0131. Merkez, on fit boyunca 1.5\u00b0 a\u00e7\u0131k kald\u0131. Operat\u00f6r derinli\u011fi kovalamaya devam etti. Tek yapt\u0131\u011f\u0131, genel tonaj\u0131 art\u0131rmak ve sapma uyumsuzlu\u011funu b\u00fcy\u00fctmekti.<\/p>\n\n\n\n

Malzeme yanl\u0131\u015f davranm\u0131yordu. \u00c7er\u00e7eve \u00f6yleydi.<\/p>\n\n\n\n

Ta\u00e7lama, k\u00f6t\u00fc programlamay\u0131 d\u00fczeltmekle ilgili de\u011fildir. Yay geri kazan\u0131m\u0131yla tart\u0131\u015fmaya girmeden \u00f6nce, makinenin elastik e\u011frisini y\u00fck e\u011frisiyle e\u015fle\u015ftirmekle ilgilidir.<\/p>\n\n\n\n

Peki, bu hareketli hedefi ger\u00e7ekten takip eden sistem hangisidir?<\/p>\n\n\n\n

Hidrolik ve Takoz (Wedge) Ta\u00e7lama: Ger\u00e7ek Zamanl\u0131 Strese Ger\u00e7ekten Hangi Sistem Tepki Veriyor?<\/h3>\n\n\n\n

\u0130kisini de kulland\u0131m.<\/p>\n\n\n\n

Mekanik takoz ta\u00e7lama d\u00fcr\u00fcst ama statiktir. \u00d6n y\u00fcklemeyi ayarlars\u0131n\u0131z\u2014temelde vuru\u015ftan \u00f6nce yata\u011f\u0131 hafif yukar\u0131ya do\u011fru b\u00fcker hale getirirsiniz. \u201cBeklenen\u201d tonaj alt\u0131nda yatak d\u00fczle\u015fir. Varsay\u0131mlar\u0131n\u0131z do\u011fruysa, bu harika \u015fekilde \u00e7al\u0131\u015f\u0131r.<\/p>\n\n\n\n

Ama parti de\u011fi\u015fti\u011finde varsay\u0131mlar \u00e7\u00f6ker.<\/p>\n\n\n\n

Mukavemetteki 10%\u2019lik bir art\u0131\u015f, 10% daha fazla kuvvet demektir. Bu da 10% daha fazla esneme demektir. Mekanik takozlar bunu bilmez. Y\u00fck alt\u0131ndayken ayarlanamazlar. Merkez a\u00e7\u0131k \u00e7\u0131karsa, durursunuz, takoz koyars\u0131n\u0131z, yeniden ayarlars\u0131n\u0131z ve yeniden denersiniz. \u00dcretim bunu sevmez.<\/p>\n\n\n\n

Hidrolik ta\u00e7lama sistemleri, yata\u011f\u0131n boyunca b\u00f6lgelere ya\u011f basarak dengeleme olu\u015fturur. Daha iyileri d\u00f6ng\u00fc s\u0131ras\u0131nda ayar yapmaya izin verir. Tonaj artt\u0131k\u00e7a, ta\u00e7lama silindirlerindeki bas\u0131n\u00e7 varsay\u0131lan y\u00fcke de\u011fil, ger\u00e7ek y\u00fcke uyacak \u015fekilde ayarlanabilir. Kuvvet artarken tabla sacla daha d\u00fczlemsel temas halinde kal\u0131r.<\/p>\n\n\n\n

Bu \u00f6nemlidir \u00e7\u00fcnk\u00fc hava b\u00fckmede kuvvet strok boyunca sabit de\u011fildir. A\u00e7\u0131 kapan\u0131rken zirve yapar. Statik bir takoz, bu e\u011frinin yaln\u0131zca bir noktas\u0131na uyar. Tepkisel bir hidrolik sistem onu izleyebilir.<\/p>\n\n\n\n

Ama kafam\u0131z\u0131 net tutal\u0131m.<\/p>\n\n\n\n

Hidrolik ta\u00e7lama bile h\u00e2l\u00e2 bir yakla\u015f\u0131md\u0131r. \u00c7o\u011fu sistem noktalar halinde de\u011fil, b\u00f6lgeler halinde telafi eder. Contalar\u0131n a\u015f\u0131nmas\u0131, ya\u011f s\u0131cakl\u0131\u011f\u0131, valf tepkisi\u2014bunlar\u0131n hepsi zamanla davran\u0131\u015f\u0131 de\u011fi\u015ftirir. E\u011fer g\u00f6vdenin esneme e\u011frisi ile sistemin telafi e\u011frisi nokta nokta uyu\u015fmuyorsa, h\u00e2l\u00e2 yakla\u015f\u0131k de\u011ferle \u00e7al\u0131\u015f\u0131yorsunuz demektir.<\/p>\n\n\n\n

H\u00e2l\u00e2 kendi haf\u0131zas\u0131 olan bir makineyle, \u00e7eli\u011fin haf\u0131zas\u0131yla pazarl\u0131k yap\u0131yorsunuz.<\/p>\n\n\n\n

Bu da ge\u00e7ici esnemeyi kal\u0131c\u0131 hasara d\u00f6n\u00fc\u015ft\u00fcren hatay\u0131 g\u00fcndeme getiriyor.<\/p>\n\n\n\n

\u201cKano\u201d Etkisi: A\u015f\u0131r\u0131 Tonaj\u0131n Hassasiyetinizi Kal\u0131c\u0131 Olarak Nas\u0131l E\u011fdi\u011fi<\/h3>\n\n\n\n

Bir d\u00fckk\u00e2na girdim; yepyeni bir makine \u201con feet boyunca a\u00e7\u0131 tutam\u0131yordu.\u201d Merkez her zaman a\u00e7\u0131k. U\u00e7lar her zaman s\u0131k\u0131. Yay geri tepmesini ortadan kald\u0131rmak i\u00e7in dar bir kal\u0131pta 10 numara paslanmaz \u00e7eli\u011fi dipten b\u00fckmeye ba\u015flam\u0131\u015flard\u0131\u2014\u00fcst \u00fcste \u00e7arpanlar: dar V, y\u00fcksek akma mukavemeti, dipten b\u00fckme y\u00f6ntemi.<\/p>\n\n\n\n

Her \u00e7evrimde neredeyse nominal tonajda \u00e7al\u0131\u015f\u0131yorlard\u0131.<\/p>\n\n\n\n

Zamanla, yatak u\u00e7larda kal\u0131c\u0131 bir yukar\u0131 e\u011fim ve ortada hafif bir sarkma geli\u015ftirdi. D\u00fczlem cetvel ve yaprak mastarlarla kontrol ettik. Dramatik de\u011fildi. Birka\u00e7 binde. Ama gereken sadece bu kadar.<\/p>\n\n\n\n

Gerilme matemati\u011fini d\u00fc\u015f\u00fcn\u00fcn. Hava b\u00fckmede, birka\u00e7 binde penetrasyon fark\u0131, kal\u0131p geni\u015fli\u011fine ba\u011fl\u0131 olarak a\u00e7\u0131y\u0131 bir derece veya daha fazla de\u011fi\u015ftirebilir. Yatak kal\u0131c\u0131 bir \u015fekil ald\u0131ysa\u2014ustalar\u0131n \u201ckanoya d\u00f6nm\u00fc\u015f\u201d dedikleri durum\u2014ta\u00e7lamay\u0131 g\u00fcn boyu ayarlasan\u0131z bile sistemi ger\u00e7ekten d\u00fczle\u015ftiremezsiniz. Elastik davran\u0131\u015f\u0131 de\u011fil, hasar\u0131 telafi ediyorsunuz.<\/p>\n\n\n\n

G\u00f6vde, nominal tonaj i\u00e7inde elastik olarak esnemek \u00fczere tasarlan\u0131r. Bunu s\u00fcrekli a\u015ft\u0131\u011f\u0131n\u0131zda, makinenin kendisinde elastikten plastike deformasyona ge\u00e7ersiniz. Art\u0131k makinenin de haf\u0131zas\u0131 vard\u0131r.<\/p>\n\n\n\n

Ve sac\u0131n aksine, onu hurdaya \u00e7\u0131kar\u0131p yenisini alamazs\u0131n\u0131z.<\/p>\n\n\n\n

E\u011fer tak\u0131m geometrisi yay geri tepmeyi kontrol etmek i\u00e7in tonaj\u0131 zorluyor ve ta\u00e7lama elastik esnemeyi n\u00f6tralize etmeye \u00e7al\u0131\u015f\u0131yorsa, ger\u00e7ek disiplin elastikiyetin bitti\u011fi ve kal\u0131c\u0131 deformasyonun ba\u015flad\u0131\u011f\u0131 noktay\u0131 bilmektir.<\/p>\n\n\n\n

\u00c7\u00fcnk\u00fc presi k\u00f6t\u00fc kulland\u0131\u011f\u0131n\u0131zda bunu hat\u0131rlamaya ba\u015flad\u0131\u011f\u0131nda, malzemeyle her pazarl\u0131\u011f\u0131n\u0131z e\u011frilmi\u015f bir ba\u015flang\u0131\u00e7 noktas\u0131ndan ba\u015flar.<\/p>\n\n\n\n

Malzeme Varyasyonuna Dayanan Bir Geri Yaylanma Telafi Stratejisi Olu\u015fturmak<\/h2>\n\n\n\n

G\u00fcvenli tonaj aral\u0131\u011f\u0131n\u0131 ve do\u011fru ta\u00e7 ayar\u0131n\u0131 m\u0131 istiyorsunuz?<\/p>\n\n\n\n

Bunu tahminle de\u011fil, test b\u00fck\u00fcmlerle kazan\u0131rs\u0131n\u0131z.<\/p>\n\n\n\n

G\u00f6vdedeki nominal tonaj etiketi, makinenin kal\u0131c\u0131 olarak akmaya ba\u015flad\u0131\u011f\u0131 noktay\u0131 g\u00f6sterir. Ger\u00e7ek \u00e7al\u0131\u015fma aral\u0131\u011f\u0131n\u0131z daha dard\u0131r: g\u00f6vde elastik kald\u0131\u011f\u0131, yatak y\u00fck alt\u0131nda d\u00fcz kald\u0131\u011f\u0131 ve malzeme sadece spesifikasyonlar\u0131na oturacak kadar ak\u0131\u015fa ge\u00e7ti\u011fi aral\u0131kt\u0131r. Bu aral\u0131k, akma mukavemeti de\u011fi\u015fti\u011finde, tah\u0131l y\u00f6n\u00fc (grain direction) de\u011fi\u015fti\u011finde veya biri A36 yerine 70 ksi \u00e7eli\u011fi koyup size s\u00f6ylemeyi unuttu\u011funda kayar.<\/p>\n\n\n\n

\u00c7elik hat\u0131rlar.<\/p>\n\n\n\n

Bu parti bu kal\u0131pta, bu makinede nas\u0131l davrand\u0131\u011f\u0131n\u0131 \u00f6l\u00e7mezseniz, iki haf\u0131zayla k\u00f6r pazarl\u0131k yap\u0131yorsunuz\u2014sac\u0131n ve presin haf\u0131zas\u0131yla. Yani strateji \u201ciki derece ekle ve um\u201d de\u011fildir. Kontroll\u00fc sondalard\u0131r: k\u0131sa par\u00e7alar, \u00f6l\u00e7\u00fclm\u00fc\u015f dald\u0131rma, do\u011frulanm\u0131\u015f a\u00e7\u0131lar, tonaj\u0131 kartal gibi izleme. \u00dcretimi oradan ge\u00e7irmeden \u00f6nce elastik s\u0131n\u0131r\u0131 haritaland\u0131r\u0131yorsunuz.<\/p>\n\n\n\n

Bu, abkant presi i\u015fletmekle \u015fekillendirme s\u00fcrecini kontrol etmek aras\u0131ndaki farkt\u0131r.<\/p>\n\n\n\n

Ampirik B\u00fckme Testleri: 4 Saatlik Yeniden \u0130\u015flemeyi \u00d6nleyen 15 Dakikal\u0131k Yat\u0131r\u0131m<\/h3>\n\n\n\n

Ben i\u015fe tam boy 10 foot\u2019luk bir par\u00e7ayla ba\u015flamam.<\/p>\n\n\n\n

Ayn\u0131 sacdan, ayn\u0131 tah\u0131l y\u00f6n\u00fcnde 3 in\u00e7 geni\u015fli\u011finde bir \u015ferit keserim ve \u00e7al\u0131\u015fma yapaca\u011f\u0131m\u0131z tam kal\u0131pta b\u00fckme i\u015flemini ger\u00e7ekle\u015ftiririm\u2014belgelenmi\u015f bir neden yoksa V a\u00e7\u0131kl\u0131\u011f\u0131 malzeme kal\u0131nl\u0131\u011f\u0131n\u0131n 8 kat\u0131 olmal\u0131d\u0131r. Malzeme 0.125 in\u00e7se, 1 in\u00e7 V kullan\u0131r\u0131m. Kitap \u00f6yle diyor diye de\u011fil, \u201cyaylanmayla sava\u015fmak\u201d i\u00e7in kal\u0131b\u0131 s\u0131k\u0131\u015ft\u0131ranlar\u0131n tonajlar\u0131n\u0131 sessizce iki kat\u0131na \u00e7\u0131kard\u0131klar\u0131n\u0131 g\u00f6rd\u00fc\u011f\u00fcm i\u00e7in.<\/p>\n\n\n\n

\u0130\u015fte d\u00fc\u011fmeye basanlar\u0131n es ge\u00e7ti\u011fi matematik: hava b\u00fckme tonaj\u0131 kal\u0131nl\u0131\u011f\u0131n karesiyle orant\u0131l\u0131d\u0131r ve kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131 artt\u0131k\u00e7a azal\u0131r. V\u2019yi 10\u201315% daralt\u0131rsan\u0131z, kuvvet h\u0131zla y\u00fckselir. Bu ekstra kuvvet sadece a\u00e7\u0131y\u0131 kapatmaz. G\u00f6vdeyi daha fazla b\u00fcker. \u015eimdi ta\u00e7 ayar\u0131n\u0131z daha yaylanmay\u0131 g\u00f6rmeden bozulmu\u015ftur.<\/p>\n\n\n\n

Bu y\u00fczden test \u015feridini 90\u00b0 programl\u0131 olarak \u00e7al\u0131\u015ft\u0131r\u0131r\u0131m.<\/p>\n\n\n\n

Sonra ne kadar gev\u015fedi\u011fini \u00f6l\u00e7erim.<\/p>\n\n\n\n

E\u011fer 92\u00b0\u2019ye a\u00e7\u0131l\u0131yorsa, bu kurulumda yakla\u015f\u0131k 2\u00b0 fazla b\u00fckmeye ihtiyac\u0131m oldu\u011funu bilirim. Programda iki derece fazla b\u00fckme ekler\u2014daha derine bast\u0131r\u0131r ki elastik geri d\u00f6n\u00fc\u015ften sonra par\u00e7a 90\u00b0\u2019ye otursun. Ama bitmi\u015f say\u0131lmam. Vuru\u015f s\u0131ras\u0131nda tonaj grafi\u011fini izlerim. K\u0131sa \u015feritte zaten nominal kapasitenin \u201390%\u2019inde isem, tam boy bir b\u00fckmenin sapmay\u0131 art\u0131raca\u011f\u0131n\u0131 ve ta\u00e7 ayar\u0131 do\u011fru de\u011filse kal\u0131c\u0131 deformasyona yakla\u015fabilece\u011fini bilirim.<\/p>\n\n\n\n

On be\u015f dakika. \u00dc\u00e7 \u015ferit. Bask\u0131n ve ters tah\u0131l y\u00f6n\u00fcnde, \u00e7izim ikisini de izinliyse.<\/p>\n\n\n\n

\u00dcretim ekibi \u00e7eli\u011fi su\u00e7larken bitmi\u015f par\u00e7alarda a\u00e7\u0131 kovalamayla ge\u00e7en d\u00f6rt saatten \u00e7ok daha iyidir.<\/p>\n\n\n\n

Malzeme Ailesine G\u00f6re Fazla B\u00fckme A\u00e7\u0131lar\u0131: Ger\u00e7ekten \u0130\u015fe Yarayan Ba\u015flang\u0131\u00e7 Noktalar\u0131<\/h3>\n\n\n\n

K\u00f6kl\u00fc s\u00f6ylentilere de\u011fil, ba\u015flang\u0131\u00e7 noktalar\u0131na ihtiyac\u0131n\u0131z var.<\/p>\n\n\n\n

Uygun bir 8\u00d7 kal\u0131pta yumu\u015fak \u00e7elik mi? Tipik kal\u0131nl\u0131klarda bir ila iki derece yaylanma. 5052-H32 al\u00fcminyum? \u0130ki ila d\u00f6rt, tah\u0131l y\u00f6n\u00fcne dikse bazen daha fazla. Hava b\u00fckmede 304 paslanmaz? \u00dc\u00e7 ila be\u015f derece yayg\u0131nd\u0131r. 70 ksi dayan\u0131ml\u0131 y\u00fcksek mukavemetli d\u00fc\u015f\u00fck ala\u015f\u0131ml\u0131 \u00e7elik? Temiz kurulumda yedi derece g\u00f6rd\u00fcm.<\/p>\n\n\n\n

Bunlar vaat de\u011fil. Ba\u015flang\u0131\u00e7 teklifidir.<\/p>\n\n\n\n

Mekanizma basittir: daha y\u00fcksek akma dayan\u0131m\u0131, hava b\u00fckme s\u0131ras\u0131nda kal\u0131nl\u0131k boyunca daha b\u00fcy\u00fck bir elastik \u00e7ekirdek anlam\u0131na gelir. Daha fazla elastik \u00e7ekirdek, y\u00fck kalkt\u0131\u011f\u0131nda daha fazla geri kazan\u0131m demektir. Bu elastik b\u00f6lgeyi ezmek i\u00e7in dip b\u00fckme ya da bask\u0131 uygulayabilirsiniz, evet\u2014ama bask\u0131 b\u00fckme, hava b\u00fckmeye k\u0131yasla be\u015f ila on kat daha fazla tonaj gerektirebilir. Standart bir pres frende, elastik \u00e7er\u00e7eve sapmas\u0131n\u0131 kal\u0131c\u0131 \u201ckano\u201d \u015feklini alacak hale getirmenin yolu budur.<\/p>\n\n\n\n

Ve yatak bir \u015fekil ald\u0131\u011f\u0131nda, \u201c\u00e7\u00f6z\u00fcm\u00fcn\u00fcz\u201d yeni problem haline gelir.<\/p>\n\n\n\n

Bu derece aral\u0131klar\u0131n\u0131 koruma bariyerleri olarak g\u00f6r\u00fcr\u00fcm. 0.125 in\u00e7 304 paslanmaz \u00e7elik test par\u00e7am 1 in\u00e7 V kal\u0131pta d\u00f6rt derece a\u00e7\u0131l\u0131yorsa bu normaldir. Sekiz derece a\u00e7\u0131l\u0131yorsa bir \u015fey de\u011fi\u015fmi\u015ftir\u2014malzeme sertli\u011fi, yanl\u0131\u015f kal\u0131p geni\u015fli\u011fi, hatal\u0131 z\u0131mba yar\u0131\u00e7ap\u0131. Test, \u00fcretim par\u00e7as\u0131na dokunmadan \u00f6nce beklenen davran\u0131\u015f s\u0131n\u0131rlar\u0131 i\u00e7inde olup olmad\u0131\u011f\u0131m\u0131 s\u00f6yler.<\/p>\n\n\n\n

Varyasyonu ortadan kald\u0131ramazs\u0131n\u0131z.<\/p>\n\n\n\n

Onu s\u0131n\u0131rlar i\u00e7ine al\u0131rs\u0131n\u0131z.<\/p>\n\n\n\n

CNC Telafi Tablolar\u0131na Ne Zaman G\u00fcvenmeli, Ne Zaman \u00dczerine Yazmal\u0131<\/h3>\n\n\n\n

Modern kumandalar malzeme k\u00fct\u00fcphaneleri ta\u015f\u0131r. Baz\u0131lar\u0131 a\u00e7\u0131y\u0131 ger\u00e7ek zamanl\u0131 okuyarak derinli\u011fi an\u0131nda ayarlar.<\/p>\n\n\n\n

Kullan\u0131\u015fl\u0131 ara\u00e7lar.<\/p>\n\n\n\n

Ama h\u00e2l\u00e2 ortalama akma de\u011ferlerine ve varsay\u0131lan s\u00fcrt\u00fcnmeye dayal\u0131 yakla\u015f\u0131mlard\u0131r. Tah\u0131l y\u00f6n\u00fc, y\u00fczey kalitesi veya parti kimyas\u0131n\u0131 de\u011fi\u015ftirin; ger\u00e7ek geri yaylanma e\u011frisi kayar. F\u0131r\u00e7alanm\u0131\u015f paslanmazda lazer a\u00e7\u0131 sistemlerinin \u015fa\u015f\u0131r\u0131p ger\u00e7ekte olmayan iki derecelik bir fark\u0131n pe\u015fine d\u00fc\u015ft\u00fcklerini g\u00f6rd\u00fcm.<\/p>\n\n\n\n

Ve i\u015fte at\u00f6lyelerin kendilerini kand\u0131rd\u0131\u011f\u0131 yer: makine ayn\u0131 yanl\u0131\u015f a\u00e7\u0131y\u0131 m\u00fckemmel \u015fekilde tekrarlarsa, buna \u201cdo\u011fru\u201d derler.\u201d<\/p>\n\n\n\n

Tabloya test par\u00e7alar\u0131m bunu do\u011frulad\u0131\u011f\u0131nda g\u00fcvenirim. Kumanda, bu kal\u0131nl\u0131ktaki paslanmaz\u0131n bu kal\u0131pta 3\u00b0 fazla b\u00fckme gerekti\u011fini s\u00f6yl\u00fcyor ve test \u015feridim 87\u00b0\u2019den 90\u00b0\u2019ye gev\u015fiyorsa, g\u00fczel. Uyum i\u00e7indeyiz. 3\u00b0 diyor ama ben 5\u00b0 \u00f6l\u00e7\u00fcyorsam, \u00e7ekinmeden d\u00fczeltirim. Kumanda akma dayan\u0131m\u0131ndaki kaymay\u0131 hissedemez. Siz \u00f6l\u00e7ebilirsiniz.<\/p>\n\n\n\n

CNC bir hesap makinesidir.<\/p>\n\n\n\n

Siz proses sahibisiniz.<\/p>\n\n\n\n

Davran\u0131\u015f\u0131 \u00f6l\u00e7\u00fclm\u00fc\u015f de\u011ferlere dayanarak telafi olu\u015fturdu\u011funuzda\u2014k\u0131sa \u015feritler, bilinen kal\u0131p geometrisi, do\u011frulanm\u0131\u015f tonaj\u2014geri yaylanmaya tepki vermeyi b\u0131rak\u0131r, onu \u00f6ng\u00f6rmeye ba\u015flars\u0131n\u0131z. Ve makinenin elastik s\u0131n\u0131rlar\u0131 i\u00e7inde \u00f6ng\u00f6rebildi\u011finizde, sohbet \u201cNe kadar sert vurabilirim?\u201d sorusundan daha ciddi bir konuya evrilir.<\/p>\n\n\n\n

Ne t\u00fcr bir operat\u00f6r olmak istiyorsunuz: par\u00e7a \u00fcreten biri mi, sonu\u00e7lar\u0131 kontrol eden biri mi?<\/p>\n\n\n\n

Makine Operat\u00f6r\u00fcnden Proses Kontrol\u00f6r\u00fcne<\/h2>\n\n\n\n

Tahmin ikinci vardiyada da devam etmeli.<\/p>\n\n\n\n

Kafan\u0131zda de\u011fil. Not defterinizde de\u011fil. S\u00fcrecin i\u00e7inde \u2014 b\u00f6ylece par\u00e7a siz orada olsan\u0131z da olmasan\u0131z da 90\u00b0 a\u00e7\u0131yla \u00e7\u0131ks\u0131n.<\/p>\n\n\n\n

Bu, bir makine i\u015fletmekle bir \u015fekillendirme sistemini kontrol etmek aras\u0131ndaki \u00e7izgidir.<\/p>\n\n\n\n

Yepyeni bir makine sizi kayan bir s\u00fcre\u00e7ten kurtarmaz. Alt\u0131 haneli bir fren presini zemine sabitleyen, OEM malzeme tablosunu y\u00fckleyip hassasiyetin haz\u0131r geldi\u011fini varsayan at\u00f6lyeler g\u00f6rd\u00fcm. \u0130ki ay sonra g\u00fcnd\u00fcz vardiyas\u0131 90\u00b0, gece vardiyas\u0131 92\u00b0 b\u00fck\u00fcyor ve herkes \u00e7eli\u011fi su\u00e7luyor. Ger\u00e7ekte de\u011fi\u015fen \u015fey kuvvet de\u011fil, disiplindir. Kilitli kal\u0131p kural\u0131 yok. Belirlenmi\u015f test \u015feridi sonu\u00e7lar\u0131 yok. O parti ve tah\u0131l y\u00f6n\u00fcne ba\u011fl\u0131 ortakla\u015fa kararla\u015ft\u0131r\u0131lm\u0131\u015f fazla b\u00fckme yok. Sadece s\u00f6zl\u00fc bilgi.<\/p>\n\n\n\n

\u00c7elik, uzun haf\u0131zal\u0131 inat\u00e7\u0131 bir \u00e7\u0131ra\u011fd\u0131r. 0.125 in\u00e7 304\u2019\u00fc tah\u0131l y\u00f6n\u00fcne kar\u015f\u0131 1 in\u00e7 V kal\u0131pta nas\u0131l davrand\u0131\u011f\u0131n\u0131 yazmazsan\u0131z, sonraki operat\u00f6r i\u015fe s\u0131f\u0131rdan ba\u015flar.<\/p>\n\n\n\n

Peki tahmini ki\u015fisel olmaktan \u00e7\u0131kar\u0131p tekrar edilebilir hale nas\u0131l getirirsiniz?<\/p>\n\n\n\n

Neden Hassas Abkant Pres \u015eekillendirme \u00d6ncelikle Bir Malzeme Problemidir<\/h3>\n\n\n\n

\u00c7\u00fcnk\u00fc \u00e7o\u011fu at\u00f6lyede en b\u00fcy\u00fck hata kayna\u011f\u0131 geri dayama kaymas\u0131 veya ta\u00e7lanma uyumsuzlu\u011fu de\u011fildir. \u00d6l\u00e7\u00fclmemi\u015f geri esnemedir.<\/p>\n\n\n\n

Elastik geri kazan\u0131m\u0131 yok sayarsan\u0131z iki derece veya daha fazla kumar oynuyorsunuz demektir. Bu bir kurulum s\u0131k\u0131nt\u0131s\u0131 de\u011fil. Bu, yar\u0131m derece toleransl\u0131 havac\u0131l\u0131k par\u00e7alar\u0131nda hurda anlam\u0131na gelir.<\/p>\n\n\n\n

Akma dayan\u0131m\u0131 burada kap\u0131 bek\u00e7isidir. Daha y\u00fcksek akma dayan\u0131m\u0131, havada b\u00fckme s\u0131ras\u0131nda daha kal\u0131n bir elastik \u00e7ekirdek demektir. Daha kal\u0131n elastik \u00e7ekirdek, y\u00fck kalkt\u0131\u011f\u0131nda daha fazla geri kazan\u0131m anlam\u0131na gelir. Makine bu kaymay\u0131 siz s\u00f6ylemedi\u011finiz s\u00fcrece \u201cg\u00f6rmez.\u201d Ve akma dayan\u0131m\u0131 partiden partiye de\u011fi\u015fir \u2014 ayn\u0131 spesifikasyon aral\u0131\u011f\u0131nda bile.<\/p>\n\n\n\n

Kuvveti standartla\u015ft\u0131r\u0131p hassasiyet umamazs\u0131n\u0131z.<\/p>\n\n\n\n

Elastik davran\u0131\u015fa nas\u0131l tepki verdi\u011finizi standartla\u015ft\u0131r\u0131rs\u0131n\u0131z.<\/p>\n\n\n\n

Bu, her yeni malzeme partisi, kal\u0131nl\u0131k veya tane y\u00f6nelimi i\u00e7in ayn\u0131 kontroll\u00fc denemenin tetiklendi\u011fi anlam\u0131na gelir: k\u0131sa \u015ferit, m\u00fchendislik aksini s\u00f6ylemedik\u00e7e 8\u00d7 kural\u0131na g\u00f6re do\u011fru V, gev\u015feme sonras\u0131 \u00f6l\u00e7\u00fclen a\u00e7\u0131, g\u00f6zlemlenen tonaj. Sonu\u00e7 sadece \u201c3\u00b0 fazla b\u00fckme gerekiyor\u201d de\u011fildir. Belgelenmi\u015ftir: malzeme \u0131s\u0131s\u0131, kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131, z\u0131mba yar\u0131\u00e7ap\u0131, programlanm\u0131\u015f derinlik, ger\u00e7ek geri esneme.<\/p>\n\n\n\n

Art\u0131k ma\u011fazan\u0131za ait, genel bir CNC tablosuna de\u011fil, bir malzeme tepkisi k\u00fct\u00fcphanesi olu\u015fturuyorsunuz.<\/p>\n\n\n\n

Ama yaln\u0131zca belgeler operat\u00f6rler aras\u0131ndaki kaymay\u0131 durdurmaz, de\u011fil mi?<\/p>\n\n\n\n

Manuel Abkantlar\u0131 K\u00f6t\u00fc Kalibre Edilmi\u015f CNC\u2019lerden Daha \u0130yi Hale Getiren Kurulum Disiplini<\/h3>\n\n\n\n

Keskin bir operat\u00f6rle \u00e7al\u0131\u015fan bir manuel abkant\u0131n, k\u00f6t\u00fc kalibre edilmi\u015f bir CNC\u2019yi t\u00fcm g\u00fcn boyunca tam bir derece farkla geride b\u0131rakt\u0131\u011f\u0131n\u0131 g\u00f6rd\u00fcm.<\/p>\n\n\n\n

Makine daha iyi oldu\u011fu i\u00e7in de\u011fil.<\/p>\n\n\n\n

S\u00fcre\u00e7 daha s\u0131k\u0131 oldu\u011fu i\u00e7in.<\/p>\n\n\n\n

Pratikte bu \u015f\u00f6yle g\u00f6r\u00fcn\u00fcr:<\/p>\n\n\n\n