\u00c7ekme dayan\u0131m\u0131n\u0131 ikiye katlay\u0131n ve gereken tonaj\u0131 da ikiye katlam\u0131\u015f olursunuz. Tablodaki ayn\u0131 V\u2019yi kullan\u0131rsan\u0131z, ilk domino ta\u015f\u0131n\u0131 devirdiniz demektir.<\/p>\n\n\n\n
Modern hassas tak\u0131mlar ak\u0131l almaz toleranslar i\u00e7inde \u00e7al\u0131\u015fabilir\u2014onda birlere kadar. \u0130yi makinelerde \u00b10.5\u00b0 a\u00e7\u0131 hassasiyeti normaldir. Ancak 10 ft boyunca sadece 0.06 mm\u2019lik tabla de\u011fi\u015fimi a\u00e7\u0131y\u0131 0.17\u00b0 kayd\u0131rabilir. Tablo d\u00fcz bir d\u00fcnya varsayar. Fakat sizin b\u00fck\u00fcm presiniz \u00f6yle bir d\u00fcnyada ya\u015fam\u0131yor.<\/p>\n\n\n\n
\u0130\u015fte tuzak: tabloyu bir cevap anahtar\u0131 san\u0131yorsunuz. De\u011fil. O sadece d\u00fczg\u00fcn davranan yumu\u015fak \u00e7eli\u011fe g\u00f6re haz\u0131rlanm\u0131\u015f bir temel.<\/p>\n\n\n\n
At\u00f6lye Kural\u0131: Her tak\u0131m tablosuna bir ba\u015flang\u0131\u00e7 tahmini olarak davran\u0131n, garanti olarak de\u011fil.<\/strong><\/p>\n\n\n\n Yeni ba\u015flad\u0131\u011f\u0131n\u0131zdan beri duydunuz: V kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131 = malzeme kal\u0131nl\u0131\u011f\u0131n\u0131n 8 kat\u0131.<\/p>\n\n\n\n Yani 0.125\u2033 malzeme mi? 1\u2033 V. 0.250\u2033 mi? 2\u2033 V.<\/p>\n\n\n\n Bu kural\u0131n asl\u0131nda vaat etti\u011fi \u015fey, hava b\u00fck\u00fcm s\u0131ras\u0131nda yumu\u015fak \u00e7elikte \u00f6ng\u00f6r\u00fclebilir bir i\u00e7 yar\u0131\u00e7apt\u0131r. Yakla\u015f\u0131k olarak:<\/p>\n\n\n\n \u0130\u00e7 Yar\u0131\u00e7ap \u2248 0.16 \u00d7 V a\u00e7\u0131kl\u0131\u011f\u0131<\/strong><\/p>\n\n\n\n 1\/4\u2033 yumu\u015fak \u00e7eli\u011fi 2\u2033 V i\u00e7inde \u00e7al\u0131\u015ft\u0131r\u0131rsan\u0131z, yakla\u015f\u0131k 0.32\u2033 i\u00e7 yar\u0131\u00e7ap g\u00f6r\u00fcrs\u00fcn\u00fcz. Bu, temel ald\u0131\u011f\u0131 matematik.<\/p>\n\n\n\n Ama sessizce \u00fc\u00e7 \u015feyi varsayar:<\/p>\n\n\n\n Bir de\u011fi\u015fkeni de\u011fi\u015ftir ve vaat buharla\u015f\u0131r.<\/p>\n\n\n\n Y\u00fcksek mukavemetli \u00e7elik \u015fekillendirmeye diren\u00e7 g\u00f6sterir. K\u0131sa flan\u015flar geni\u015f kal\u0131plarda sallan\u0131r. V a\u00e7\u0131kl\u0131\u011f\u0131nda kal\u0131nl\u0131\u011f\u0131n 5\u00d7 alt\u0131na inersen, \u00e7izelgenin ne s\u00f6yledi\u011fine bak\u0131lmaks\u0131z\u0131n a\u00e7\u0131sal karars\u0131zl\u0131k ve tak\u0131m gerilme riskiyle kar\u015f\u0131la\u015f\u0131rs\u0131n.<\/p>\n\n\n\n \u0130\u015fte tuzak, \u201c8 Kural\u0131\u201dn\u0131 bir yasa san\u0131yorsun. O, bir malzeme ailesi i\u00e7in yar\u0131\u00e7ap kontrol\u00fc, tonaj ve stabilite aras\u0131ndaki bir uzla\u015fmad\u0131r.<\/p>\n\n\n\n At\u00f6lye Kural\u0131: \u00d6nce malzeme mukavemeti ve flan\u015f geometrisine g\u00f6re V kal\u0131b\u0131n\u0131 se\u00e7\u2014sonra \u00e7izelgenin ne dedi\u011fini kontrol et.<\/strong><\/p>\n\n\n\n Diyelim ki \u00e7izelge sana o b\u00fckme i\u00e7in ayak ba\u015f\u0131na 50 ton s\u00f6yl\u00fcyor.<\/p>\n\n\n\n Sen 50 programl\u0131yorsun. 50\u2019ye g\u00fcveniyorsun.<\/p>\n\n\n\n Ama malzeme sertifikas\u0131nda 60 ksi de\u011fil, 100 ksi \u00e7ekme dayan\u0131m\u0131 yaz\u0131yor. Form\u00fcle geri d\u00f6n:<\/p>\n\n\n\n E\u011fer \u00e7ekme dayan\u0131m\u0131 % artarsa, gerekli tonaj da % artar. O ayak ba\u015f\u0131na 50 ton yakla\u015f\u0131k 83\u2019e \u00e7\u0131kt\u0131.<\/p>\n\n\n\n Yetersiz tonajdas\u0131n. Bu y\u00fczden daha derine bast\u0131r\u0131yorsun. Fazla b\u00fckme telafisi devreye giriyor. Makine gerekenden fazla \u00e7al\u0131\u015f\u0131yor. Operat\u00f6r yaylanmay\u0131 su\u00e7luyor.<\/p>\n\n\n\n Daha da k\u00f6t\u00fcs\u00fc\u2014zaten presin s\u0131n\u0131r\u0131na yak\u0131nd\u0131n. \u015eimdi, tablo resmi g\u00f6r\u00fcnd\u00fc\u011f\u00fc i\u00e7in tak\u0131mlar\u0131 a\u015f\u0131r\u0131 y\u00fckl\u00fcyorsun.<\/p>\n\n\n\n \u0130\u015fte tuzak, tablo m\u00fchendislik \u00fcr\u00fcn\u00fc gibi geliyor, bu y\u00fczden g\u00fcvenli hissediliyor. Ama senin s\u0131cak parti numaran\u0131, z\u0131mba yar\u0131\u00e7ap\u0131n\u0131 veya CNC malzeme k\u00fct\u00fcphanesi giri\u015fini bilmiyor.<\/p>\n\n\n\n Tonaj tablolar\u0131 do\u011fru veri giri\u015fi varsayar. Kontrol\u00fcn z\u0131mba yar\u0131\u00e7ap\u0131n\u0131 0.031\u2033 g\u00f6steriyor ama asl\u0131nda 0.062\u2033 ise, her b\u00fckme tahmin edilebilir \u015fekilde hatal\u0131 olur\u2014\u201c\u00e7izelgeyi izledin\u201d bile desen.\u201d<\/p>\n\n\n\n At\u00f6lye Kural\u0131: \u00c7ekme dayan\u0131m\u0131 veya z\u0131mba yar\u0131\u00e7ap\u0131 her de\u011fi\u015fti\u011finde tonaj\u0131 yeniden hesapla\u2014devral\u0131nm\u0131\u015f rakamlara asla g\u00fcvenme.<\/strong><\/p>\n\n\n\n Ayn\u0131 makinede, ayn\u0131 vardiyada bunun ya\u015fand\u0131\u011f\u0131n\u0131 g\u00f6rd\u00fcm.<\/p>\n\n\n\n Operat\u00f6r A 90\u00b0\u2019yi temiz tutturuyor. Operat\u00f6r B ise t\u00fcm \u00f6\u011fleden sonra 88\u00b0 ile 92\u00b0 aras\u0131nda u\u011fra\u015f\u0131yor.<\/p>\n\n\n\n Ayn\u0131 tablo. Ayn\u0131 V. Ayn\u0131 program.<\/p>\n\n\n\n Ne farkl\u0131?<\/p>\n\n\n\n Biri malzeme mukavemetini do\u011frulad\u0131 ve kontrol\u00fc g\u00fcncelledi. Di\u011feri son i\u015fin ayarlar\u0131na g\u00fcvendi. Biri tabla bombelenmesini kontrol etti. Di\u011feri d\u00fcz oldu\u011funu varsayd\u0131.<\/p>\n\n\n\n Presiniz a\u00e7\u0131 konusunda \u00b10,5\u00b0 toleransl\u0131 olabilir. S\u0131k\u0131 g\u00f6r\u00fcn\u00fcyor. Ama k\u00fc\u00e7\u00fck bir tabla d\u00fczg\u00fcnl\u00fck hatas\u0131n\u0131 (boy boyunca 0,06 mm), hafif bir malzeme varyasyonunu ve yanl\u0131\u015f bir z\u0131mba yar\u0131\u00e7ap\u0131 giri\u015fini \u00fcst \u00fcste koyarsan\u0131z\u2014g\u00f6zle fark edilir a\u00e7\u0131 sapmas\u0131na yetecek kadar sapma biriktirmi\u015f olursunuz.<\/p>\n\n\n\n Tablolar, m\u00fckemmel girdiler ve m\u00fckemmel geometri varsayar.<\/p>\n\n\n\n At\u00f6lyelerde ikisi de yoktur.<\/p>\n\n\n\n Ve de\u011fi\u015ftirmemi istedi\u011fim bak\u0131\u015f a\u00e7\u0131s\u0131 \u015fu: \u201cTablo ne diyor?\u201d diye sormay\u0131 b\u0131rak\u0131n, \u201cBu tablonun bug\u00fcn do\u011fru olmayan hangi varsay\u0131mlar\u0131 var?\u201d diye sormaya ba\u015flay\u0131n.\u201d<\/p>\n\n\n\n \u00c7\u00fcnk\u00fc ilk domino a\u00e7\u0131 de\u011fildir.<\/p>\n\n\n\n Yeniden hesaplama yapmadan se\u00e7ti\u011finiz V-kal\u0131pt\u0131r.<\/p>\n\n\n\n Ge\u00e7en k\u0131\u015f, \u201cdaha dar bir k\u00f6\u015fe\u201d gereken 1\/4\u2033 paslanmaz bir braketimiz vard\u0131. Operat\u00f6r 2\u2033 V\u2019yi \u00e7\u0131kard\u0131, yerine 1,5\u2033 V koydu. Ayn\u0131 z\u0131mba. Ayn\u0131 program. \u0130lk vuru\u015f farkl\u0131 bir ses \u00e7\u0131kard\u0131. \u00dc\u00e7\u00fcnc\u00fc par\u00e7aya gelindi\u011finde, pres maksimum tonaj\u0131n s\u0131n\u0131r\u0131nda dola\u015f\u0131yor ve a\u00e7\u0131 h\u00e2l\u00e2 tutars\u0131zd\u0131.<\/p>\n\n\n\n Ba\u015fka hi\u00e7bir \u015fey de\u011fi\u015fmedi.<\/p>\n\n\n\n \u0130\u015fte o zaman dank ediyor: V-kal\u0131p sadece malzemeyi b\u0131rakaca\u011f\u0131n\u0131z bir kanal de\u011fildir. O ilk dominodur. Onu devirirseniz, yar\u0131\u00e7ap de\u011fi\u015fir, tonaj artar, flan\u015f geometrisi de\u011fi\u015fir ve tak\u0131m \u00f6mr\u00fc k\u0131sal\u0131r\u2014t\u00fcm bunlar derinlik ayar\u0131na dokunmadan \u00f6nce olur.<\/p>\n\n\n\n Ad\u0131m ad\u0131m bir s\u00fcre\u00e7 mi istiyorsunuz? Tamam. \u015e\u00f6yle ba\u015flar:<\/p>\n\n\n\n Ad\u0131m iki atlan\u0131rsa, gerisi deneyim kisvesi alt\u0131nda tahmindir.<\/p>\n\n\n\n At\u00f6lye Kural\u0131:<\/strong> V kal\u0131b\u0131 se\u00e7imi bir detay de\u011fildir\u2014geri kalan her \u015feyin uydu\u011fu karard\u0131r.<\/p>\n\n\n\n Bana s\u00fcrekli diyorsun: \u201c\u00c7izim 0.250 i\u00e7 yar\u0131\u00e7ap istiyor.\u201d<\/p>\n\n\n\n Hay\u0131r. \u00c7izim bir sonu\u00e7 istiyor. Nas\u0131l ula\u015faca\u011f\u0131n\u0131 kal\u0131p belirler.<\/p>\n\n\n\n Hava b\u00fck\u00fcm\u00fcnde, i\u00e7 yar\u0131\u00e7ap acemi ki\u015filerin sand\u0131\u011f\u0131 gibi z\u0131mban\u0131n ucu taraf\u0131ndan belirlenmez. A\u011f\u0131rl\u0131kl\u0131 olarak V a\u00e7\u0131kl\u0131\u011f\u0131n\u0131n bir fonksiyonudur. Yumu\u015fak \u00e7elikte 90\u00b0 i\u00e7in \u00e7al\u0131\u015fma ili\u015fkisi \u015f\u00f6yledir:<\/p>\n\n\n\n \u0130\u00e7 Yar\u0131\u00e7ap \u2248 0.16 \u00d7 V a\u00e7\u0131kl\u0131\u011f\u0131<\/p>\n\n\n\n 2\u2033 V kal\u0131b\u0131na 1\/4\u2033 yumu\u015fak \u00e7elik koy:0.16 \u00d7 2.0 = 0.32\u2033 i\u00e7 yar\u0131\u00e7ap.<\/p>\n\n\n\n 0.25\u2033 de\u011fil. Kutudaki z\u0131mba ucunun dedi\u011fi ne olursa olsun de\u011fil. Yakla\u015f\u0131k 0.32\u2033.<\/p>\n\n\n\n \u015eimdi 1.5\u2033 V kal\u0131ba ge\u00e7erek \u201cdaha s\u0131k\u0131 hale getir\u201d:0.16 \u00d7 1.5 = 0.24\u2033.<\/p>\n\n\n\n Tek bir de\u011fi\u015fkeni oynatarak i\u00e7 yar\u0131\u00e7ap\u0131 0.08\u2033 de\u011fi\u015ftirdin.<\/p>\n\n\n\n \u0130\u015fte tuzak \u015fu: operat\u00f6rler i\u00e7 yar\u0131\u00e7ap\u0131 bir girdi ve V kal\u0131b\u0131n\u0131 yard\u0131mc\u0131 bir unsur gibi g\u00f6r\u00fcyor. Hava b\u00fck\u00fcm\u00fcnde tam tersi. Kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131 b\u00fcy\u00fck \u00f6l\u00e7\u00fcde malzemenin do\u011fal olarak ald\u0131\u011f\u0131 yar\u0131\u00e7ap\u0131 belirler. Z\u0131mba bunu sadece belli s\u0131n\u0131rlar i\u00e7inde hassasla\u015ft\u0131r\u0131r.<\/p>\n\n\n\n Ve bir kez V\u2019yi de\u011fi\u015ftirirsen, sadece yar\u0131\u00e7ap\u0131 de\u011fi\u015ftirmezsin. Tonaj form\u00fcl\u00fcne bak:<\/p>\n\n\n\n Ayak ba\u015f\u0131na tonaj = (\u00c7ekme Dayan\u0131m\u0131 \u00d7 Kal\u0131nl\u0131k\u00b2) \u00f7 (8 \u00d7 V a\u00e7\u0131kl\u0131\u011f\u0131)<\/p>\n\n\n\n Paydadakine dikkat et. V a\u00e7\u0131kl\u0131\u011f\u0131. V\u2019yi k\u00fc\u00e7\u00fclt, tonaj y\u00fckselir\u2014V ile do\u011frusal, ama kal\u0131nl\u0131kla \u00fcstel bi\u00e7imde \u00e7\u00fcnk\u00fc T\u00b2 terimi var.<\/p>\n\n\n\n Daha s\u0131k\u0131 bir yar\u0131\u00e7ap istedin. Ayn\u0131 zamanda daha fazla kuvvet talep ettin.<\/p>\n\n\n\n At\u00f6lye Kural\u0131:<\/strong> Hava b\u00fck\u00fcm\u00fcnde, ya\u015fayabilece\u011fin yar\u0131\u00e7ap i\u00e7in V\u2019yi se\u00e7\u2014sonra beraberinde gelen tonaj\u0131 kabul et.<\/p>\n\n\n\n \u0130lk g\u00fcnden beri Kitap Kural\u0131 olan 8\u2019i duydun: V a\u00e7\u0131kl\u0131\u011f\u0131 = 8 \u00d7 malzeme kal\u0131nl\u0131\u011f\u0131.<\/p>\n\n\n\n Bu\u2014yumu\u015fak \u00e7elik, 90\u00b0 hava b\u00fck\u00fcmleri ve \u201cnormal\u201d geometriler i\u00e7in\u2014uygundur.<\/p>\n\n\n\n 0.125\u2033 malzeme \u00e7al\u0131\u015ft\u0131r:8 \u00d7 0.125 = 1.0\u2033 V.<\/p>\n\n\n\n \u0130yi. \u00d6ng\u00f6r\u00fclebilir. Stabil.<\/p>\n\n\n\n Ama diyelim ki \u00e7izimde, 8\u00d7 kurulumun verdi\u011finden daha dar bir i\u00e7 yar\u0131\u00e7ap isteniyor. 6\u00d7\u2019e d\u00fc\u015f\u00fcr\u00fcyorsunuz:<\/p>\n\n\n\n 6 \u00d7 0,125 = 0,75\u2033 V.<\/p>\n\n\n\n Yar\u0131\u00e7ap buna g\u00f6re d\u00fc\u015fer: 0,16 \u00d7 0,75 = yakla\u015f\u0131k 0,12\u2033 i\u00e7 yar\u0131\u00e7ap.<\/p>\n\n\n\n Harika. Ama \u015fimdi tonaj\u0131 yeniden hesaplay\u0131n.<\/p>\n\n\n\n E\u011fer ba\u015flang\u0131\u00e7 tonaj\u0131 1,0\u2033 V\u2019de T idiyse, yeni tonaj \u015f\u00f6yle olur:<\/p>\n\n\n\n T_yeni = T \u00d7 (1,0 \u00f7 0,75) \u2248 1,33T<\/p>\n\n\n\n Sadece kal\u0131b\u0131 daraltarak \u2019l\u00fck bir art\u0131\u015f (%) elde ettiniz. Kal\u0131nl\u0131k de\u011fi\u015fmedi. Malzeme kalitesi de\u011fi\u015fmedi.<\/p>\n\n\n\n \u015eimdi di\u011fer y\u00f6ne gidin. A\u011f\u0131r sac. 1\/2\u2033 yumu\u015fak \u00e7elik.<\/p>\n\n\n\n 8 kural\u0131 diyor ki: 8 \u00d7 0,5 = 4\u2033 V.<\/p>\n\n\n\n Ama kal\u0131n sac genellikle stabilite ve tak\u0131m \u00f6mr\u00fc i\u00e7in 10\u00d7 veya 12\u00d7 ile daha iyi sonu\u00e7 verir.<\/p>\n\n\n\n 12 \u00d7 0,5 = 6\u2033 V.<\/p>\n\n\n\n V\u2019yi (%) geni\u015flettiniz. Bu tonaj\u0131 azalt\u0131r:<\/p>\n\n\n\n T_yeni = T \u00d7 (4 \u00f7 6) \u2248 0,67T<\/p>\n\n\n\n Daha az kuvvet. Daha b\u00fcy\u00fck i\u00e7 yar\u0131\u00e7ap: 0,16 \u00d7 6 = 0,96\u2033 yar\u0131\u00e7ap.<\/p>\n\n\n\n Tablolar\u0131n a\u00e7\u0131klamad\u0131\u011f\u0131 \u015fey \u015fu: \u00e7arpan, \u00fc\u00e7 kar\u015f\u0131t kuvveti dengeledi\u011finiz i\u00e7in de\u011fi\u015fir\u2014<\/p>\n\n\n\n V a\u00e7\u0131kl\u0131\u011f\u0131nda 5\u00d7 kal\u0131nl\u0131\u011f\u0131n alt\u0131na inerseniz, \u00e7izelge ne derse desin a\u00e7\u0131sal stabilite kayb\u0131 ve tak\u0131m gerilmesi riski olu\u015fur. Malzemenin temiz \u015fekilde akaca\u011f\u0131 bir alan kalmaz. Tak\u0131m omuzlar\u0131 zorlan\u0131r. A\u00e7\u0131lar dengesiz hale gelir.<\/p>\n\n\n\n \u0130\u015fte tuzak: Bask\u0131n\u0131n dar yar\u0131\u00e7ap\u0131n\u0131n pe\u015finden, tonaj\u0131 yeniden hesaplamadan ko\u015fars\u0131n\u0131z ve form\u00fclde kal\u0131nl\u0131\u011f\u0131n karesinin al\u0131nd\u0131\u011f\u0131n\u0131 unutursunuz. Kal\u0131nl\u0131\u011f\u0131 ikiye katlay\u0131n; gereken tonaj d\u00f6rt kat\u0131na \u00e7\u0131kar. Bu do\u011frusal bir ac\u0131 de\u011fil. Bu, \u00fcstel bir cezad\u0131r.<\/p>\n\n\n\n \u201c8\u00d7\u201de uymuyorsunuz.\u201d 6\u00d7, 8\u00d7 veya 12\u00d7\u2019i hangisi sizi en az incitiyorsa ona g\u00f6re se\u00e7ersiniz\u2014ve her seferinde matemati\u011fi do\u011frulars\u0131n\u0131z.<\/p>\n\n\n\n At\u00f6lye Kural\u0131:<\/strong> Geometri, mukavemet veya kal\u0131nl\u0131k bunu gerektirdi\u011finde 8\u00d7\u2019i derhal terk edin\u2014sonra yeni oran\u0131n\u0131z\u0131n freni a\u015f\u0131r\u0131 y\u00fcklemeyece\u011fini kan\u0131tlay\u0131n.<\/p>\n\n\n\n \u015eimdi m\u00fckemmel kurulumunuzu bozal\u0131m.<\/p>\n\n\n\n Diyelim ki 0,125\u2033 par\u00e7an\u0131zda 0,500\u2033 kenar var. 1,0\u2033 V (8\u00d7) \u00e7al\u0131\u015ft\u0131rmak istiyorsunuz. Kitap gibi g\u00f6r\u00fcn\u00fcyor.<\/p>\n\n\n\n Ama hava b\u00fckmede minimum kenar uzunlu\u011fu yakla\u015f\u0131k olarak:<\/p>\n\n\n\n Minimum Kenar \u2248 (V-a\u00e7\u0131l\u0131\u015f \u00f7 2) + malzeme kal\u0131nl\u0131\u011f\u0131<\/p>\n\n\n\n 1,0\u2033 V i\u00e7in: (1,0 \u00f7 2) + 0,125 = 0,625\u2033<\/p>\n\n\n\n Kenar\u0131n\u0131z 0,500\u2033. Fiziksel olarak bu kal\u0131pta V\u2019nin i\u00e7ine do\u011fru devrilmeden duramaz.<\/p>\n\n\n\n Peki ne yapars\u0131n\u0131z? Kal\u0131b\u0131 0,75\u2033\u2019e daralt\u0131rs\u0131n\u0131z:<\/p>\n\n\n\n (0,75 \u00f7 2) + 0,125 = 0,500\u2033<\/p>\n\n\n\n \u015eimdi tam olarak s\u0131\u011f\u0131yor.<\/p>\n\n\n\n Ama hat\u0131rlay\u0131n, bu ne yapt\u0131? Tonaj\u0131 yakla\u015f\u0131k art\u0131rd\u0131 ve i\u00e7 yar\u0131\u00e7ap\u0131 s\u0131k\u0131la\u015ft\u0131rd\u0131.<\/p>\n\n\n\n Bask\u0131y\u0131 de\u011fi\u015ftirmediniz. Kenar geometrisi V-kal\u0131p de\u011fi\u015fimini zorlad\u0131. V-kal\u0131p de\u011fi\u015fimi tonaj hesaplamas\u0131n\u0131 zorlad\u0131. Tonaj hesaplamas\u0131 \u015fimdi makinenizin g\u00fcvenli \u00e7al\u0131\u015fma y\u00fck\u00fcn\u00fc a\u015fabilir.<\/p>\n\n\n\n \u0130\u015fte bu zincirleme etkidir.<\/p>\n\n\n\n \u0130\u015fte tuzak: Kal\u0131nl\u0131\u011fa g\u00f6re bir V se\u00e7ersiniz ve kenar\u0131n kal\u0131p omuzlar\u0131n\u0131 fiziksel olarak ge\u00e7mesi gerekti\u011fini unutursunuz. Par\u00e7a, tablonun ne \u00f6nerdi\u011fini umursamaz. Geometriyle ilgilenir.<\/p>\n\n\n\n Ve bu geometriyi g\u00f6z ard\u0131 ederseniz, sallanan par\u00e7alar, tutars\u0131z a\u00e7\u0131lar veya ezilmi\u015f kenarlar g\u00f6r\u00fcrs\u00fcn\u00fcz\u2014ve ger\u00e7ek sorun destek oldu\u011funda, bahar\u0131 su\u00e7lars\u0131n\u0131z.<\/p>\n\n\n\n At\u00f6lye Kural\u0131:<\/strong> Bir V-a\u00e7\u0131l\u0131\u015fa karar vermeden \u00f6nce, kenar\u0131n fiziksel olarak s\u0131\u011fabilece\u011fini kan\u0131tlay\u0131n\u2014sonra pedala basmadan \u00f6nce tonaj\u0131 yeniden hesaplay\u0131n.**<\/p>\n\n\n\n Nereye varaca\u011f\u0131n\u0131 g\u00f6r\u00fcyorsunuz.<\/p>\n\n\n\n V kal\u0131p geni\u015fli\u011fi de\u011fi\u015fti\u011fi anda\u2014sebebi ne kadar iyi olursa olsun\u2014makineye yeni bir tonaj hesab\u0131 ve kapasiteye dikkatli bir bak\u0131\u015f bor\u00e7lusunuz. \u00c7\u00fcnk\u00fc kurulum s\u0131ras\u0131nda devirdi\u011finiz domino, presinizin y\u00fck limitine do\u011fru d\u00fc\u015fmek \u00fczere.<\/p>\n\n\n\n Ge\u00e7en ay bir operat\u00f6r bana bir kurulum formu getirdi: 1\/4\u2033 paslanmaz \u00e7elik, 10 fit uzunlukta, 2\u2033 V kal\u0131b\u0131. Tabloya g\u00f6re 2\u2033 V kal\u0131b\u0131nda 1\/4\u2033 yumu\u015fak \u00e7elik i\u00e7in ayak ba\u015f\u0131na 19,7 ton diyordu. O da bu de\u011feri 150 tonluk prese do\u011frudan uygulad\u0131 ve kendini g\u00fcvende sand\u0131.<\/p>\n\n\n\n \u0130\u015fte tuzak burada: Makinenin etiketindeki toplam tonaj\u0131 do\u011frulad\u0131 ama malzeme dayan\u0131m\u0131n\u0131 veya ayak ba\u015f\u0131na y\u00fcklemeyi yeniden hesaplamad\u0131.<\/p>\n\n\n\n Her seferinde \u00e7al\u0131\u015ft\u0131rman\u0131z gereken tonaj form\u00fcl\u00fc \u015fudur:<\/p>\n\n\n\n Ton\/ft = (\u00c7ekme Dayan\u0131m\u0131 \u00d7 Kal\u0131nl\u0131k\u00b2) \u00f7 (8 \u00d7 V-a\u00e7\u0131kl\u0131\u011f\u0131)<\/p>\n\n\n\n Tablo 60.000 PSI yumu\u015fak \u00e7eli\u011fi esas al\u0131r. O paslanmaz \u00e7elik ise 90.000 PSI \u00e7ekme dayan\u0131m\u0131na daha yak\u0131nd\u0131. \u00d6l\u00e7ekleme fakt\u00f6r\u00fc basit:<\/p>\n\n\n\n Malzeme \u00c7arpan\u0131 = Yeni \u00c7ekme Dayan\u0131m\u0131 \u00f7 60.000<\/p>\n\n\n\n Yani 90.000 \u00f7 60.000 = 1,5\u00d7.<\/p>\n\n\n\n O halde 19,7 ton\/ft temel de\u011ferini al\u0131p \u00e7arp\u0131n:<\/p>\n\n\n\n 19,7 \u00d7 1,5 \u2248 ayak ba\u015f\u0131na 29,6 ton.<\/p>\n\n\n\n 10 fit boyunca bu, 296 ton eder. 150 tonluk bir makinede.<\/p>\n\n\n\n Ve tam 10 fitlik bir b\u00fck\u00fcm yapmad\u0131\u011f\u0131n\u0131z\u0131 iddia etseniz bile, makine g\u00f6vdesi sizin iyimserli\u011finizle ilgilenmez. Onun i\u00e7in \u00f6nemli olan \u015fey, ayak ba\u015f\u0131na y\u00fck ve bu y\u00fck\u00fcn ne kadar e\u015fit da\u011f\u0131ld\u0131\u011f\u0131d\u0131r.<\/p>\n\n\n\n G\u00fcvenli\u011fi \u00fc\u00e7 ad\u0131mda do\u011frulars\u0131n\u0131z:<\/p>\n\n\n\n Bunlardan birini bile atlad\u0131\u011f\u0131n\u0131zda, alt\u0131 haneli bir yat\u0131r\u0131m\u0131 riske at\u0131yorsunuz demektir.<\/p>\n\n\n\n At\u00f6lye Kural\u0131: Ger\u00e7ek \u00e7ekme dayan\u0131m\u0131 ve ger\u00e7ek b\u00fck\u00fcm uzunlu\u011funa g\u00f6re \u00f6l\u00e7ekleme yapmad\u0131k\u00e7a tablo tonaj\u0131na asla g\u00fcvenmeyin.<\/strong><\/p>\n\n\n\n Elinizdeki her standart tablo, 60.000 PSI yumu\u015fak \u00e7eli\u011fe g\u00f6re sabitlenmi\u015ftir. Bu, rakamlar\u0131n i\u00e7ine gizlenmi\u015f varsay\u0131md\u0131r.<\/p>\n\n\n\n Her ala\u015f\u0131m i\u00e7in yeni bir tabloya ihtiyac\u0131n\u0131z yok. \u0130htiyac\u0131n\u0131z olan bir oran.<\/p>\n\n\n\n Ton\/ft_ger\u00e7ek = Ton\/ft_tablo \u00d7 (\u00c7ekme_ger\u00e7ek \u00f7 60.000)<\/p>\n\n\n\n Hepsi bu. Tahmine gerek yok.<\/p>\n\n\n\n 90.000 PSI paslanmaz \u00e7elik mi? 1,5 ile \u00e7arp\u0131n. 100.000 PSI y\u00fcksek dayan\u0131ml\u0131 d\u00fc\u015f\u00fck ala\u015f\u0131ml\u0131 \u00e7elik mi? 100.000 \u00f7 60.000 \u2248 1,67\u00d7. 38.000 PSI civar\u0131nda 5052 al\u00fcminyum mu? 38.000 \u00f7 60.000 \u2248 0,63\u00d7.<\/p>\n\n\n\n Ama flan\u015f sorununu \u00e7\u00f6zmek i\u00e7in V\u2019yi daraltt\u0131ysan\u0131z, 0,63 \u00e7arpan bile sizi yan\u0131ltabilir. \u00c7\u00fcnk\u00fc tonaj, V-a\u00e7\u0131kl\u0131\u011f\u0131 ile ters orant\u0131l\u0131d\u0131r:<\/p>\n\n\n\n T \u221d 1 \u00f7 V<\/p>\n\n\n\n V\u2019yi 2\u2033den 1,5\u2033e mi d\u00fc\u015f\u00fcrd\u00fcn\u00fcz? 2 \u00f7 1,5 \u2248 1,33\u00d7 art\u0131\u015f.<\/p>\n\n\n\n Yani 1,5\u2033 V i\u00e7inde 1\/4\u2033 al\u00fcminyum d\u00fc\u015f\u00fcn\u00fcn. Malzeme i\u00e7in tonaj\u0131 azaltt\u0131n\u0131z (0,63\u00d7) ama kal\u0131p geni\u015fli\u011fi i\u00e7in art\u0131rd\u0131n\u0131z (1,33\u00d7).<\/p>\n\n\n\n Net etki: 0,63 \u00d7 1,33 \u2248 0,84\u00d7 yumu\u015fak \u00e7elik baz\u0131na g\u00f6re.<\/p>\n\n\n\n Al\u00fcminyumun her zaman \u201ckolay\u201d oldu\u011funu san\u0131yorsunuz. De\u011fil. Bu matematik.<\/p>\n\n\n\n \u0130\u015fte tuzak: operat\u00f6rler ayn\u0131 i\u015fte malzemeyi ve kal\u0131p geni\u015fli\u011fini de\u011fi\u015ftiriyor, ama yaln\u0131zca birine g\u00f6re ayarlama yap\u0131yor. \u00c7arpanlar \u00fcst \u00fcste biner. Bazen birbirini dengeler. Bazen y\u00fck\u00fcn\u00fcz\u00fc ikiye katlar.<\/p>\n\n\n\n Ve bunlar\u0131n hi\u00e7biri genel bir tak\u0131m tablosunda g\u00f6r\u00fcnmez.<\/p>\n\n\n\n At\u00f6lye Kural\u0131: \u00d6nce tabloyu \u00e7ekme oran\u0131na g\u00f6re \u00f6l\u00e7eklendirin, ard\u0131ndan V-a\u00e7\u0131kl\u0131\u011f\u0131na g\u00f6re ayarlay\u0131n\u2014asla tersi de\u011fil.<\/strong><\/p>\n\n\n\n 150 tonluk bir abkant\u0131n, \u00e7er\u00e7eve kapasitesinden \u015fikayet etmeden \u00f6nce alt kal\u0131b\u0131n\u0131n \u00e7atlad\u0131\u011f\u0131n\u0131 g\u00f6rd\u00fcm.<\/p>\n\n\n\n Neden? \u00c7\u00fcnk\u00fc kal\u0131b\u0131n 20 ton\/ft derecesi vard\u0131 ve i\u015f 28 gerektiriyordu.<\/p>\n\n\n\n Yayg\u0131n bir 150 ton \u00d7 10\u2032 abkant, e\u015fit y\u00fcklendi\u011finde yakla\u015f\u0131k 15 ton\/ft da\u011f\u0131t\u0131lm\u0131\u015f derecenin sahibidir. Baz\u0131 a\u011f\u0131r g\u00f6vdeler 25 ton\/ft\u2019ye yakla\u015f\u0131r. Ama bu makine yap\u0131s\u0131d\u0131r. Tak\u0131mlar\u0131n\u0131z daha d\u00fc\u015f\u00fck de\u011ferlere sahip olabilir.<\/p>\n\n\n\n Bunu \u015f\u00f6yle kontrol edersiniz:<\/p>\n\n\n\n Hangisi daha k\u00fc\u00e7\u00fckse, ger\u00e7ek s\u0131n\u0131r\u0131n\u0131z odur.<\/p>\n\n\n\n \u0130\u015fte tuzak: insanlar \u201c150 ton\u201d de\u011ferine bak\u0131yor ve merkeze yak\u0131n 3 feet uzunlu\u011funda 45 ton toplam b\u00fckme yapt\u0131klar\u0131nda bunun yerel olarak 15 ton\/ft oldu\u011funu unutuyorlar. Bunu 2 feet\u2019e kayd\u0131r\u0131rsan\u0131z, o b\u00f6lgede 22,5 ton\/ft\u2019e \u00e7\u0131kars\u0131n\u0131z. Toplam tonaj ayn\u0131. Yerel gerilme daha y\u00fcksek.<\/p>\n\n\n\n G\u00f6vde burulur. Kal\u0131plar mantarla\u015f\u0131r. Z\u0131mba omuzlar\u0131 ufalan\u0131r.<\/p>\n\n\n\n Makinedeki etiket bir izin de\u011fil. \u0130deal da\u011f\u0131l\u0131m alt\u0131nda bir s\u0131n\u0131rd\u0131r.<\/p>\n\n\n\n At\u00f6lye Kural\u0131: \u0130zin verilen ton\/ft de\u011ferin, makine de\u011feri, tak\u0131m de\u011feri ve hesaplanan y\u00fck aras\u0131ndaki en k\u00fc\u00e7\u00fck olan\u0131d\u0131r \u2014 en zay\u0131f halkaya sayg\u0131 g\u00f6sterin.<\/strong><\/p>\n\n\n\n \u00c7izelgeler 90\u00b0 hava b\u00fckmeyi varsayar. Bu \u00f6nemlidir.<\/p>\n\n\n\n 30\u00b0 veya 45\u00b0\u2019ye b\u00fckme yapt\u0131\u011f\u0131n\u0131zda \u2014 kapatmadan \u00f6nceki keskin \u00f6n b\u00fckmede \u2014 malzeme hem z\u0131mba hem de kal\u0131p omuzlar\u0131na daha fazla temas etti\u011fi i\u00e7in kuvvet artar. Art\u0131k d\u00fczg\u00fcn \u00fc\u00e7 noktal\u0131 hava b\u00fckmede de\u011filsiniz. Alt b\u00fckmeye yakla\u015fm\u0131\u015f oluyorsunuz.<\/p>\n\n\n\n Kuvvet art\u0131\u015flar\u0131 \u00f6nemsiz de\u011fildir. Geometriye ba\u011fl\u0131 olarak, alt b\u00fckmeye ula\u015fmadan \u00f6nce 90\u00b0 \u00e7izelge de\u011ferinin \u201350 \u00fczerinde bir art\u0131\u015f g\u00f6rebilirsiniz.<\/p>\n\n\n\n Matematiksel mant\u0131k basittir, kesin katsay\u0131 de\u011fi\u015fse bile:<\/p>\n\n\n\n T_ger\u00e7ek \u2248 T_90\u00b0 \u00d7 A\u00e7\u0131_Fakt\u00f6r\u00fc<\/p>\n\n\n\n E\u011fer 90\u00b0 hesaplaman\u0131z 20 ton\/ft \u00e7\u0131kar\u0131yorsa ve keskin a\u00e7\u0131 fakt\u00f6r\u00fcn\u00fcz 1,3 ise, b\u00fckmeyi daha d\u00fczle\u015ftirmeden \u00f6nce 26 ton\/ft de\u011ferine ula\u015f\u0131rs\u0131n\u0131z.<\/p>\n\n\n\n \u015eimdi buna dar bir kal\u0131p ve paslanmaz \u00e7arpan\u0131n\u0131 da ekleyin.<\/p>\n\n\n\n Operat\u00f6rlerin \u201cRakamlara g\u00f6re sorun yoktu\u201d derken \u00e7atlam\u0131\u015f bir z\u0131mba ucunun yan\u0131nda durmalar\u0131n\u0131n nedeni budur.<\/p>\n\n\n\n \u0130\u015fte tuzak: k\u00e2\u011f\u0131t \u00fczerinde tonaj\u0131 90\u00b0\u2019de do\u011fruluyorsunuz ama ger\u00e7ekte en y\u00fcksek y\u00fck\u00fc 35\u00b0\u2019de uyguluyorsunuz. Makine nihai a\u00e7\u0131y\u0131 de\u011fil, tepe y\u00fck\u00fc hisseder.<\/p>\n\n\n\n V a\u00e7\u0131kl\u0131\u011f\u0131n\u0131 sac kal\u0131nl\u0131\u011f\u0131n\u0131n 5 kat\u0131n\u0131n alt\u0131na d\u00fc\u015f\u00fcr\u00fcrseniz, \u00e7izelge ne derse desin, a\u00e7\u0131sal karars\u0131zl\u0131k ve tak\u0131m gerilmesi riski do\u011far. Buna keskin a\u00e7\u0131lar\u0131 da ekleyin, bir gerilme yo\u011funla\u015ft\u0131r\u0131c\u0131s\u0131 olu\u015fturmu\u015f olursunuz.<\/p>\n\n\n\n Bu b\u00f6l\u00fcme g\u00fcvenli \u00e7al\u0131\u015fma s\u0131n\u0131rlar\u0131nda oldu\u011funuzu nas\u0131l do\u011frulayaca\u011f\u0131n\u0131z\u0131 sorarak ba\u015flad\u0131n\u0131z. Cevap tek bir kar\u015f\u0131la\u015ft\u0131rma de\u011fil. Bu, katmanl\u0131 bir hesaplamad\u0131r: malzeme oran\u0131, V a\u00e7\u0131kl\u0131\u011f\u0131 ayar\u0131, birim uzunluk ba\u015f\u0131na da\u011f\u0131l\u0131m ve a\u00e7\u0131 fakt\u00f6r\u00fc \u2014 hepsi makine ve tak\u0131m de\u011ferleriyle kar\u015f\u0131la\u015ft\u0131r\u0131larak kontrol edilir.<\/p>\n\n\n\n Ve t\u00fcm bunlar do\u011fru olsa bile, yine de ar\u0131zay\u0131 bekleyen bir zay\u0131f nokta daha vard\u0131r.<\/p>\n\n\n\n Z\u0131mba.<\/p>\n\n\n\n Y\u00fck\u00fcn bir sonraki yo\u011funla\u015ft\u0131\u011f\u0131 yer buras\u0131d\u0131r.<\/p>\n\n\n\n Ge\u00e7en k\u0131\u015f, 3\/16\u2033 paslanmaz \u00e7elikte bir z\u0131mba ucunu par\u00e7alad\u0131k. Fren a\u015f\u0131r\u0131 y\u00fcklenmi\u015f oldu\u011fu i\u00e7in de\u011fil. Kal\u0131p d\u00fc\u015f\u00fck kapasitede oldu\u011fu i\u00e7in de de\u011fil. Hesaplanan y\u00fck\u00fcn her aya\u011f\u0131na d\u00fc\u015fen 42 tonluk kuvvet, 0.031\u2033 z\u0131mba burnundan ge\u00e7iyordu ve kimse bunun temas gerilimine ne yapt\u0131\u011f\u0131n\u0131 sormay\u0131 durdurmad\u0131.<\/p>\n\n\n\n \u0130\u015fte tuzak bu: Toplam tonaj\u0131 ve ayak ba\u015f\u0131na d\u00fc\u015fen tonaj\u0131 do\u011frular, bunlar\u0131 makine ve kal\u0131p de\u011ferleriyle kar\u015f\u0131la\u015ft\u0131r\u0131rs\u0131n\u0131z ve z\u0131mba \u201csertle\u015ftirilmi\u015f tak\u0131m\u201d oldu\u011fu i\u00e7in iyi oldu\u011funu varsayars\u0131n\u0131z. Y\u00fck sertlikle ilgilenmez. Alanla ilgilenir.<\/p>\n\n\n\n Temas bas\u0131nc\u0131, kuvvetin temas geni\u015fli\u011fine b\u00f6l\u00fcnmesiyle orant\u0131l\u0131d\u0131r. Z\u0131mba burnu yar\u0131\u00e7ap\u0131n\u0131 k\u00fc\u00e7\u00fclt\u00fcrseniz temas alan\u0131n\u0131 da k\u00fc\u00e7\u00fclt\u00fcrs\u00fcn\u00fcz. Ayn\u0131 tonaj, u\u00e7ta daha y\u00fcksek gerilim. \u0130\u015fte bu nedenle, k\u00e2\u011f\u0131t \u00fczerinde g\u00fcvenli g\u00f6r\u00fcnen bir fren, $900 z\u0131mbay\u0131 tek vuru\u015fta par\u00e7alay\u0131verir.<\/p>\n\n\n\n Hava b\u00fckmede, i\u00e7 yar\u0131\u00e7ap\u0131n\u0131z kabaca kal\u0131ba ba\u011fl\u0131d\u0131r: \u0130\u00e7 Yar\u0131\u00e7ap \u2248 0.16 \u00d7 V a\u00e7\u0131kl\u0131\u011f\u0131 (yumu\u015fak \u00e7elik i\u00e7in temel de\u011fer). Fakat b\u00fckmeyi ba\u015flatan z\u0131mba burnu yar\u0131\u00e7ap\u0131d\u0131r. Kal\u0131b\u0131n\u0131z 1.5\u2033 V a\u00e7\u0131kl\u0131\u011f\u0131ndaysa, \u00f6ng\u00f6r\u00fclen i\u00e7 yar\u0131\u00e7ap yakla\u015f\u0131k 0.24\u2033 olur. Buna 1\/32\u2033 (0.031\u2033) z\u0131mba ucu ile girerseniz, ba\u015flang\u0131\u00e7taki temas b\u00f6lgesi sac sar\u0131lana kadar jilet gibi k\u00fc\u00e7\u00fckt\u00fcr. Y\u00fcksek \u00e7ekme mukavemetli malzemelerde o tepe noktas\u0131 \u015fiddetlidir.<\/p>\n\n\n\n Sadece ayak ba\u015f\u0131na tonaj\u0131 kontrol etmezsiniz. O tonaj\u0131n nerede yo\u011funla\u015ft\u0131\u011f\u0131n\u0131 kontrol edersiniz.<\/p>\n\n\n\n Ve tablo size bunu asla s\u00f6ylemez.<\/p>\n\n\n\n At\u00f6lye Kural\u0131: Ton\/ft hesaplad\u0131ktan sonra, bunu z\u0131mba burnu yar\u0131\u00e7ap\u0131 ve malzeme mukavemeti ile kar\u015f\u0131la\u015ft\u0131r\u0131n\u2014k\u00fc\u00e7\u00fck u\u00e7 art\u0131 y\u00fcksek \u00e7ekme mukavemeti e\u015fittir yo\u011funla\u015fm\u0131\u015f risk.<\/strong><\/p>\n\n\n\n Basit bir U-\u00e7ubu\u011fu hayal edin: 2\u2033 g\u00f6vde, 1\u2033 kenarlar, 14 kal\u0131nl\u0131kta sac. \u0130lk b\u00fck\u00fcm gayet iyi gider. \u0130kinci b\u00fck\u00fcmde par\u00e7ay\u0131 yukar\u0131 \u00e7evirirsiniz ve z\u0131mba g\u00f6vdesi\u2014ucu de\u011fil, omzu\u2014ilk kenara 62\u00b0\u2019de \u00e7arpar.<\/p>\n\n\n\n Tablo size V a\u00e7\u0131kl\u0131\u011f\u0131n\u0131 ve tonaj\u0131 verdi. Z\u0131mba g\u00f6vde geometrisi hakk\u0131nda hi\u00e7bir bilgi vermedi.<\/p>\n\n\n\n Kaz boynu z\u0131mbalar bu nedenle vard\u0131r. Ucun arkas\u0131nda bo\u015faltma yap\u0131larak \u00f6nceden b\u00fck\u00fclm\u00fc\u015f kenar\u0131n s\u0131\u011faca\u011f\u0131 yer b\u0131rak\u0131l\u0131r. Fakat i\u015fte tuzak \u015fu ki, operat\u00f6rler do\u011fru u\u00e7 a\u00e7\u0131s\u0131n\u0131 se\u00e7er ve z\u0131mba g\u00f6vde geni\u015fli\u011fini ile bo\u015faltma derinli\u011fini unuturlar.<\/p>\n\n\n\n Bo\u015fluk tahmin i\u015fi de\u011fildir. \u00d6l\u00e7\u00fclmelidir.<\/p>\n\n\n\n E\u011fer kenar y\u00fcksekli\u011fi H ve z\u0131mba omzu \u00e7al\u0131\u015fma derinli\u011finde u\u00e7tan S kadar geride duruyorsa, o zaman \u015funa ihtiyac\u0131n\u0131z vard\u0131r: H \u2265 S + malzeme kal\u0131nl\u0131\u011f\u0131 + g\u00fcvenlik pay\u0131.<\/p>\n\n\n\n S de\u011feri 0.75\u2033 ve kenar\u0131n\u0131z 0.70\u2033 ise, \u00e7arp\u0131\u015fma ka\u00e7\u0131n\u0131lmazd\u0131r. Tablo ne vaat ederse etsin fark etmez.<\/p>\n\n\n\n Ve vuru\u015f ortas\u0131nda \u00e7arp\u0131\u015ft\u0131\u011f\u0131n\u0131zda, fren tonaj zirve yapana kadar itmeye devam eder. Bu zirve hesaplaman\u0131zda yoktur. Bu bir geometrik kilitlenmedir. \u015eimdi yerel ton\/ft de\u011feriniz f\u0131rlar, z\u0131mban\u0131z \u015fok y\u00fck\u00fc g\u00f6r\u00fcr ve \u201cg\u00fcvenli\u201d hesaplaman\u0131z u\u00e7ar gider.<\/p>\n\n\n\n Bu nedenle \u00e7oklu b\u00fck\u00fcml\u00fc par\u00e7alarda bo\u015fluk, a\u00e7\u0131dan daha \u00f6nemlidir. Hava b\u00fckmede a\u00e7\u0131 derinlikle ayarlanabilir. Fiziksel \u00e7ak\u0131\u015fma ayarlanamaz.<\/p>\n\n\n\n At\u00f6lye Kural\u0131: Bir z\u0131mbay\u0131 onaylamadan \u00f6nce, geometrisini ka\u011f\u0131t \u00fczerinde kuru \u00e7al\u0131\u015ft\u0131r\u0131n\u2014omuz bo\u015flu\u011funu kenar y\u00fcksekli\u011fiyle kar\u015f\u0131la\u015ft\u0131r\u0131n ya da bir \u00e7arp\u0131\u015fma zirvesi bekleyin.<\/strong><\/p>\n\n\n\n Bir tak\u0131m tablosu, kal\u0131p geni\u015fli\u011finden i\u00e7 yar\u0131\u00e7ap\u0131 tahmin eder. Ancak malzemenizin dayanabilece\u011fi minimum b\u00fckme yar\u0131\u00e7ap\u0131n\u0131 size s\u00f6ylemez.<\/p>\n\n\n\n Bunlar ayn\u0131 say\u0131 de\u011fildir.<\/p>\n\n\n\n Yakla\u015f\u0131k 90.000 PSI \u00e7ekme dayan\u0131m\u0131na sahip 304 paslanmaz \u00e7eli\u011fi ele alal\u0131m. Yayg\u0131n bir minimum i\u00e7 b\u00fckme yar\u0131\u00e7ap\u0131 kural\u0131, 90\u00b0 hava b\u00fckmeleri i\u00e7in malzeme kal\u0131nl\u0131\u011f\u0131n\u0131n yakla\u015f\u0131k 1\u00d7\u2019i kadard\u0131r. 0.125\u2033 kal\u0131nl\u0131\u011f\u0131ndaki paslanmaz\u0131 0.125\u2033 i\u00e7 yar\u0131\u00e7aptan daha dar \u015fekilde b\u00fckerseniz, tane y\u00f6n\u00fc boyunca \u00e7atlama riskiyle kar\u015f\u0131la\u015f\u0131rs\u0131n\u0131z.<\/p>\n\n\n\n \u015eimdi kal\u0131p form\u00fcl\u00fcn\u00fc uygulayal\u0131m: \u0130\u00e7 Yar\u0131\u00e7ap \u2248 0,16 \u00d7 V. E\u011fer yar\u0131\u00e7ap\u0131 \u201cdaraltmak\u201d i\u00e7in 0.5\u2033 V se\u00e7erseniz, 0.16 \u00d7 0.5 = 0.08\u2033 i\u00e7 yar\u0131\u00e7ap elde edersiniz.<\/p>\n\n\n\n 0.08\u2033 < 0.125\u2033. Malzemeyi minimum g\u00fcvenli b\u00fckme yar\u0131\u00e7ap\u0131n\u0131n alt\u0131na zorlad\u0131n\u0131z.<\/p>\n\n\n\n \u0130\u015fte tuzak \u015fu: z\u0131mba burun yar\u0131\u00e7ap\u0131n\u0131 de\u011fi\u015ftirmenin, hava b\u00fckmede nihai i\u00e7 yar\u0131\u00e7ap\u0131 kontrol etti\u011fini zannedersiniz. Etmez. Kontrol\u00fc kal\u0131p sa\u011flar. Z\u0131mba b\u00fckmeyi ba\u015flat\u0131r, ancak yay\u0131 kal\u0131p geni\u015fli\u011fi belirler.<\/p>\n\n\n\n Alt b\u00fckmede ise durum farkl\u0131d\u0131r. Orada, z\u0131mba burnu yar\u0131\u00e7ap\u0131 malzeme \u00fczerine iz yapmak i\u00e7in kal\u0131p yar\u0131\u00e7ap\u0131yla e\u015fle\u015fmelidir. Ancak alt b\u00fckme, hava b\u00fckmeden 2\u20134\u00d7 daha fazla tonaj gerektirir. Bu \u00e7arpan, zaten hesaplad\u0131\u011f\u0131m\u0131z her \u015feyin \u00fczerine eklenir. Art\u0131k z\u0131mban\u0131z sadece \u015fekil vermiyor\u2014damgalama yap\u0131yor.<\/p>\n\n\n\n Yani iki ayr\u0131 kontrol\u00fcn\u00fcz olmal\u0131:<\/p>\n\n\n\n Bunlardan birini ka\u00e7\u0131r\u0131rsan\u0131z, par\u00e7a pres freninden \u00e7\u0131kmadan \u00f6nce b\u00fckmenin d\u0131\u015f y\u00fczeyinde mikro \u00e7atlaklar g\u00f6receksiniz.<\/p>\n\n\n\n At\u00f6lye Kural\u0131: Z\u0131mba u\u00e7lar\u0131 hakk\u0131nda tart\u0131\u015fmaya girmeden \u00f6nce tahmini i\u00e7 yar\u0131\u00e7ap\u0131 (0.16 \u00d7 V) malzemenin minimum b\u00fckme yar\u0131\u00e7ap\u0131yla kar\u015f\u0131la\u015ft\u0131r\u0131n.<\/strong><\/p>\n\n\n\n Size a\u00e7\u0131lar e\u015fle\u015ftirilmeli denmi\u015ftir: 90\u00b0 b\u00fckme i\u00e7in 90\u00b0 z\u0131mba ve 90\u00b0 kal\u0131p. Basit ve temiz.<\/p>\n\n\n\n Hava b\u00fckmede bunun sadece yar\u0131s\u0131 do\u011frudur.<\/p>\n\n\n\n Son b\u00fckme a\u00e7\u0131s\u0131, kesin olarak z\u0131mba a\u00e7\u0131s\u0131yla de\u011fil, kal\u0131ba n\u00fcfuz etme derinli\u011fiyle kontrol edilir. 90\u00b0\u2019lik bir kal\u0131pta 88\u00b0 z\u0131mba kullanarak, derinli\u011fi do\u011fru ayarlarsan\u0131z m\u00fckemmel bir 90\u00b0 b\u00fckme elde edebilirsiniz. Sac\u0131n \u00e7o\u011fu strok boyunca yaln\u0131zca z\u0131mba ucu ve kal\u0131p omuzlar\u0131yla temas halinde olur.<\/p>\n\n\n\n Yani a\u00e7\u0131 uyumsuzlu\u011fu su\u00e7lu mu?<\/p>\n\n\n\n Her zaman de\u011fil.<\/p>\n\n\n\n Tuzak burada: ger\u00e7ek tehlike hava b\u00fckmede k\u00fc\u00e7\u00fck a\u00e7\u0131 uyumsuzlu\u011fu de\u011fildir\u2014hedef derinli\u011fe ula\u015fmadan bo\u015fluk t\u00fckenmesidir. Z\u0131mba a\u00e7\u0131n\u0131z hedefe g\u00f6re fazla a\u00e7\u0131ksa, a\u00e7\u0131y\u0131 yakalamaya \u00e7al\u0131\u015f\u0131rken z\u0131mba omuzlar\u0131 malzemeye temas edebilir. Bu da sizi, planlamadan \u00fc\u00e7 noktal\u0131 hava b\u00fckmeden alt b\u00fckme davran\u0131\u015f\u0131na ge\u00e7irir.<\/p>\n\n\n\n Ve bu oldu\u011funda, tonaj f\u0131rl\u0131yor.<\/p>\n\n\n\n \u00d6nceden hat\u0131rlay\u0131n: T_ger\u00e7ek \u2248 T_90\u00b0 \u00d7 A\u00e7\u0131_Fakt\u00f6r\u00fc.<\/p>\n\n\n\n Keskin a\u00e7\u0131lara yakla\u015ft\u0131k\u00e7a temas alan\u0131 artar ve kuvvet y\u00fckselir\u2014ger\u00e7ek dip noktas\u0131na ula\u015fmadan \u00f6nce 20\u201350\u202fT pek al\u0131\u015f\u0131lmad\u0131k de\u011fildir. Z\u0131mban\u0131z ve kal\u0131p a\u00e7\u0131lar\u0131n\u0131z erken omuz temas\u0131na zorlad\u0131\u011f\u0131nda, matemati\u011finizi g\u00fcncellemeden A\u00e7\u0131_Fakt\u00f6r\u00fcn\u00fc fiilen art\u0131rm\u0131\u015f olursunuz.<\/p>\n\n\n\n \u015eimdi bunu y\u00fcksek \u00e7ekme dayan\u0131m\u0131 ve dar V ile \u00fcst \u00fcste koyun.<\/p>\n\n\n\n Domino ta\u015flar\u0131 h\u0131zl\u0131 d\u00fc\u015fer.<\/p>\n\n\n\n A\u00e7\u0131 uyumsuzlu\u011fu otomatik olarak yanl\u0131\u015f de\u011fildir. Planlanmam\u0131\u015f temas yanl\u0131\u015f oland\u0131r.<\/p>\n\n\n\n Z\u0131mba g\u00fcvenli\u011fini katalog a\u00e7\u0131lar\u0131yla e\u015fle\u015ftirerek do\u011frulamazs\u0131n\u0131z. Hedef a\u00e7\u0131n\u0131z i\u00e7in gereken tam strok boyunca temas\u0131n yaln\u0131zca bekledi\u011finiz yerde kald\u0131\u011f\u0131n\u0131\u2014u\u00e7 ve kal\u0131p omuzlar\u0131\u2014ve hesaplanan tepe tonaj\u0131n hem tak\u0131mlama hem de z\u0131mba gerilme s\u0131n\u0131rlar\u0131n\u0131n alt\u0131nda oldu\u011funu do\u011frulayarak do\u011frulars\u0131n\u0131z.<\/p>\n\n\n\n Bu bizi ka\u00e7\u0131nd\u0131\u011f\u0131n\u0131z disipline getiriyor.<\/p>\n\n\n\n Bu de\u011fi\u015fkenlerin t\u00fcm\u00fc\u2014malzeme dayan\u0131m\u0131, V-a\u00e7\u0131l\u0131\u015f, ayak ba\u015f\u0131na y\u00fck, a\u00e7\u0131 fakt\u00f6r\u00fc, z\u0131mba bo\u015flu\u011fu, minimum yar\u0131\u00e7ap\u2014\u00f6nseziyle de\u011fil, s\u0131rayla kontrol edilmelidir. Bir domino ta\u015f\u0131 kural\u0131.<\/p>\n\n\n\n At\u00f6lye Kural\u0131: Havada b\u00fckmede, sadece a\u00e7\u0131y\u0131 de\u011fil, derinli\u011fi y\u00f6netin ve tonaj matemati\u011finize g\u00fcvenmeden \u00f6nce istenmeyen omuz temas\u0131n\u0131n olmad\u0131\u011f\u0131n\u0131 do\u011frulay\u0131n.<\/strong><\/p>\n\n\n\n S\u0131ralamay\u0131 istiyorsunuz. Teoriyi de\u011fil. \u201cDuruma g\u00f6re de\u011fi\u015fir\u201di de\u011fil. Z\u0131mban\u0131z\u0131 koruyan ve hurda kutunuzu bo\u015f tutan kesin ad\u0131mlar.<\/p>\n\n\n\n G\u00fczel.<\/p>\n\n\n\n \u00c7\u00fcnk\u00fc z\u0131mba g\u00fcvenli\u011fi bir katalog numaras\u0131 de\u011fildir\u2014karar zinciridir. \u0130lk domino ta\u015f\u0131 yanl\u0131\u015f d\u00fc\u015ferse di\u011ferleri h\u0131zla d\u00fc\u015fer: yar\u0131\u00e7ap de\u011fi\u015fir, tonaj f\u0131rlar, flan\u015flar \u00e7arp\u0131\u015f\u0131r, omuzlar temas eder ve pres hesaplamad\u0131\u011f\u0131n\u0131z bir y\u00fck verir.<\/p>\n\n\n\n Grafik ba\u015flang\u0131\u00e7 karo ta\u015f\u0131n\u0131zd\u0131r. Cevab\u0131n\u0131z de\u011fildir.<\/p>\n\n\n\n \u0130\u015fte tuzak: metali tan\u0131mlamadan grafi\u011fi a\u00e7ars\u0131n\u0131z.<\/p>\n\n\n\n Tak\u0131mlama grafikleri 60.000 PSI civar\u0131nda \u00e7ekme dayan\u0131m\u0131na sahip yumu\u015fak \u00e7elik varsayar. Bu, \u00e7o\u011fu temel tonaj form\u00fcl\u00fcn\u00fcn arkas\u0131ndaki sessiz varsay\u0131md\u0131r. Yayg\u0131n bir form:<\/p>\n\n\n\n P = (650 \u00d7 S\u00b2 \u00d7 L) \/ V<\/p>\n\n\n\n Burada: 650 sabiti, havada b\u00fckmede yumu\u015fak \u00e7elik varsay\u0131m\u0131na dayan\u0131r.<\/p>\n\n\n\n \u015eimdi 90.000 PSI paslanmaza ge\u00e7in. Dayan\u0131m \u00e7arpan\u0131n\u0131z:<\/p>\n\n\n\n \u00c7arpan = 90.000 \/ 60.000 = 1,5<\/p>\n\n\n\n Her tonaj de\u011feri, ba\u015fka bir \u015fey yapmadan \u00f6nce 1,5 ile \u00e7arp\u0131lmal\u0131d\u0131r.<\/p>\n\n\n\n E\u011fer havada b\u00fckme yerine tabana oturtma yap\u0131yorsan\u0131z, n\u00fcfuziyet oran\u0131na ba\u011fl\u0131 olarak 2\u00d7 ile 4\u00d7 aras\u0131nda ekleyin. Ayn\u0131 geometriden olsa bile havada b\u00fckme genellikle tabana oturtmaya g\u00f6re \u201330 daha az kuvvet gerektirir.<\/p>\n\n\n\n Yani d\u00fczeltilmi\u015f tonaj\u0131n\u0131z \u015f\u00f6yle olur:<\/p>\n\n\n\n P_d\u00fczeltilmi\u015f = P_tablo \u00d7 Malzeme \u00c7arpan\u0131 \u00d7 Y\u00f6ntem \u00c7arpan\u0131<\/p>\n\n\n\n Bunu V kal\u0131b\u0131n\u0131 se\u00e7meden \u00f6nce yapars\u0131n\u0131z, \u00e7\u00fcnk\u00fc bu \u00e7arpan sonraki her kararda sizinle birlikte gelir.<\/p>\n\n\n\n \u00c7ekme dayan\u0131m\u0131n\u0131 tan\u0131mlay\u0131n. B\u00fckme y\u00f6ntemini tan\u0131mlay\u0131n. Kurulum \u00e7izelgenizin \u00fcst\u00fcne \u00e7arpan\u0131 yaz\u0131n.<\/p>\n\n\n\n At\u00f6lye Kural\u0131: Yaz\u0131lm\u0131\u015f malzeme \u00e7arpan\u0131 yoksa, tablo a\u00e7\u0131lmaz.<\/strong><\/p>\n\n\n\n Art\u0131k metalin bir karakteri oldu\u011funa g\u00f6re, hangi V a\u00e7\u0131kl\u0131\u011f\u0131 ger\u00e7ekten mant\u0131kl\u0131?<\/p>\n\n\n\n V kal\u0131b\u0131 ilk domino ta\u015f\u0131d\u0131r.<\/p>\n\n\n\n Kitaplarda ge\u00e7en 8 kural\u0131, V \u2248 8 \u00d7 kal\u0131nl\u0131k (yumu\u015fak \u00e7elik havada b\u00fckme) der. Bu bir temel de\u011ferdir, emir de\u011fil.<\/p>\n\n\n\n \u00c7\u00fcnk\u00fc V ayn\u0131 anda \u00fc\u00e7 \u015feyi kontrol eder:<\/p>\n\n\n\n Havada b\u00fckmede i\u00e7 yar\u0131\u00e7ap kabaca:<\/p>\n\n\n\n \u0130\u00e7 Yar\u0131\u00e7ap \u2248 0,16 \u00d7 V<\/p>\n\n\n\n E\u011fer \u00e7iziminiz 0.125\u2033 i\u00e7 yar\u0131\u00e7ap gerektiriyorsa, o zaman:<\/p>\n\n\n\n V = 0.125 \/ 0.16 = 0.78\u2033<\/p>\n\n\n\n Yani yakla\u015f\u0131k olarak 3\/4\u2033 bir V kullanman\u0131z gerekiyor.<\/p>\n\n\n\n Fakat ayn\u0131 V, minimum flan\u015f uzunlu\u011funu da belirler. Hava b\u00fckmede minimum flan\u015f i\u00e7in pratik bir kural yakla\u015f\u0131k olarak:<\/p>\n\n\n\n Min Flan\u015f \u2248 V \/ 2<\/p>\n\n\n\n 1\u2033 V mi kullan\u0131yorsunuz? Par\u00e7an\u0131n do\u011fru oturmas\u0131 i\u00e7in yakla\u015f\u0131k 0.5\u2033 flan\u015f gerekir. O kal\u0131pta 0.4\u2033 flan\u015f b\u00fckmeye \u00e7al\u0131\u015f\u0131rsan\u0131z, par\u00e7a a\u00e7\u0131kl\u0131\u011f\u0131n i\u00e7ine d\u00fc\u015fer. A\u00e7\u0131 tekrarlanmaz. Tonaj e\u015fit da\u011f\u0131lmaz.<\/p>\n\n\n\n V-a\u00e7\u0131kl\u0131\u011f\u0131n\u0131 malzeme kal\u0131nl\u0131\u011f\u0131n\u0131n 5 kat\u0131n\u0131n alt\u0131na d\u00fc\u015f\u00fcr\u00fcrseniz, \u00e7izelge ne derse desin a\u00e7\u0131sal karars\u0131zl\u0131k ve tak\u0131m gerilmesi riski olu\u015fur.<\/p>\n\n\n\n \u0130\u015fte tuzak \u015fu: operat\u00f6rler V'yi kal\u0131nl\u0131k kural\u0131na g\u00f6re se\u00e7er ve ancak daha sonra flan\u015f\u0131n \u00e7ok k\u0131sa veya yar\u0131\u00e7ap\u0131n \u00e7ok dar oldu\u011funu fark eder. Sonra tonaj\u0131 yeniden hesaplamadan V'yi daraltarak \u201ci\u015fi y\u00fcr\u00fctmeye\u201d \u00e7al\u0131\u015f\u0131rlar.<\/p>\n\n\n\n Daha dar V, daha y\u00fcksek kuvvet demektir \u00e7\u00fcnk\u00fc tonaj V\u2019ye ters orant\u0131l\u0131d\u0131r:<\/p>\n\n\n\n P \u221d 1 \/ V<\/p>\n\n\n\n V\u2019yi 1\u2033\u2019den 0.5\u2033\u2019e d\u00fc\u015f\u00fcrd\u00fcn\u00fcz m\u00fc? \u00c7arpanlar eklenmeden \u00f6nce temel kuvveti ikiye katlad\u0131n\u0131z demektir.<\/p>\n\n\n\n Bu y\u00fczden, \u00f6nce yar\u0131\u00e7ap ve flan\u015f geometrisine g\u00f6re V\u2019yi sabitleyin. Sonra ger\u00e7ek \u00e7arpanlar\u0131n\u0131zla tonaj\u0131 yeniden hesaplay\u0131n. Tam tersi \u015fekilde yapmay\u0131n.<\/p>\n\n\n\n At\u00f6lye Kural\u0131: V\u2019yi yar\u0131\u00e7ap ve flan\u015f\u0131n ger\u00e7eklerine g\u00f6re se\u00e7in, sonra tonaj sonucunu kabul edin.<\/strong><\/p>\n\n\n\n V sabitlendi\u011finde, matematik ciddile\u015fir.<\/p>\n\n\n\n \u015eimdi her \u015feyi birle\u015ftiriyoruz.<\/p>\n\n\n\n Form\u00fclle ba\u015fla:<\/p>\n\n\n\n P = (650 \u00d7 S\u00b2 \u00d7 L) \/ V<\/p>\n\n\n\n Sonra uygulay\u0131n:<\/p>\n\n\n\n P_total = P \u00d7 Malzeme \u00c7arpan\u0131 \u00d7 Metot \u00c7arpan\u0131<\/p>\n\n\n\n Gerekirse fit ba\u015f\u0131na tona \u00e7evirin:<\/p>\n\n\n\n Ton\/ft = P_total \/ L (fit cinsinden)<\/p>\n\n\n\n Makinenizin iki s\u0131n\u0131r\u0131 vard\u0131r: toplam tonaj ve metrekare ba\u015f\u0131na tonaj. Tak\u0131m\u0131n\u0131z\u0131n da ayak ba\u015f\u0131na ton cinsinden bir derecelendirmesi vard\u0131r. Bu zincirdeki en d\u00fc\u015f\u00fck de\u011fer sizin tavan\u0131n\u0131zd\u0131r.<\/p>\n\n\n\n Ancak 0,031\u2033 z\u0131mba ucu bile y\u00fck\u00fc son derece yo\u011funla\u015ft\u0131r\u0131r. Ayak ba\u015f\u0131na tonaj, z\u0131mba g\u00f6vdesi boyunca e\u015fit da\u011f\u0131lmaz\u2014y\u00fck o k\u00fc\u00e7\u00fcc\u00fck temas hatt\u0131 boyunca yo\u011funla\u015f\u0131r. \u00c7atlama i\u015fte orada ba\u015flar.<\/p>\n\n\n\n Tuzak \u015fudur: makine veya tak\u0131m derecelendirmesini kontrol etmeden geli\u015fig\u00fczel bir 20% \u201cg\u00fcvenlik pay\u0131\u201d eklemek. 40 ton\/ft hesaplay\u0131p, 25% \u201cemin olmak i\u00e7in\u201d ekleyen ve sessizce 50 ton\/ft tak\u0131m derecesinin \u00fczerine \u00e7\u0131kan operat\u00f6rler g\u00f6rd\u00fcm.<\/p>\n\n\n\n G\u00fcvenlik paylar\u0131 s\u0131n\u0131rlar\u0131n yerini almaz. Onlar bu s\u0131n\u0131rlar\u0131n i\u00e7inde olmal\u0131d\u0131r.<\/p>\n\n\n\n Bu y\u00fczden do\u011frulama kontrol listeniz \u015fu \u015fekilde g\u00f6r\u00fcn\u00fcr:<\/p>\n\n\n\n Herhangi bir cevab\u0131n\u0131z \u201cyak\u0131n\u201d ise, hen\u00fcz g\u00fcvenli de\u011fildir.<\/p>\n\n\n\n At\u00f6lye Kural\u0131: G\u00fcvenli olan\u0131 en d\u00fc\u015f\u00fck dereceli bile\u015fen belirler\u2014iyimserli\u011finiz de\u011fil.<\/strong><\/p>\n\n\n\n Matematik bunun i\u015fe yarad\u0131\u011f\u0131n\u0131 s\u00f6yl\u00fcyor. Geometri bunun s\u0131\u011fd\u0131\u011f\u0131n\u0131 s\u00f6yl\u00fcyor. \u015eimdi bunu \u00e7elikte kan\u0131tlay\u0131n.<\/p>\n\n\n\n \u0130lk darbe \u00fcretim de\u011fildir. Bu bir te\u015fhistir.<\/p>\n\n\n\n D\u00f6rt \u015feyi \u00f6l\u00e7ersiniz:<\/p>\n\n\n\n Tahmini yar\u0131\u00e7ap 0,16 \u00d7 V ise ve beklenenden daha s\u0131k\u0131 \u00f6l\u00e7\u00fcyorsan\u0131z, alt\u0131na do\u011fru sap\u0131yor olabilirsiniz. Bu, hesaplanandan daha y\u00fcksek ger\u00e7ek tonaj anlam\u0131na gelir.<\/p>\n\n\n\n E\u011fer a\u00e7\u0131 nihai derinli\u011fe yakla\u015f\u0131rken h\u0131zla art\u0131yorsa, omuzlar erken temas ediyor olabilir. Bu istenmeyen temast\u0131r. Bu, olu\u015fmay\u0131 bekleyen bir s\u0131\u00e7ramad\u0131r.<\/p>\n\n\n\n E\u011fer flan\u015f kal\u0131b\u0131n i\u00e7ine sallan\u0131yor veya g\u00f6m\u00fcl\u00fcyorsa, V geometriniz i\u00e7in fazla geni\u015f\u2014grafik onaylam\u0131\u015f olsa bile.<\/p>\n\n\n\n Ve e\u011fer sadece u\u00e7 yerine z\u0131mba omuzlar\u0131nda parlak izler g\u00f6r\u00fcrseniz, durun. Bu, geometrinin tonaj hesaplar\u0131n\u0131z\u0131 ger\u00e7ek zamanl\u0131 olarak yeniden yazd\u0131\u011f\u0131 anlam\u0131na gelir.<\/p>\n\n\n\n Bu d\u00f6ng\u00fc basittir:<\/p>\n\n\n\n Tahmin Et \u2192 Hafif\u00e7e Vur \u2192 \u00d6l\u00e7 \u2192 Kar\u015f\u0131la\u015ft\u0131r \u2192 Ayarla \u2192 Yeniden Hesapla.<\/p>\n\n\n\n \u201cTahmin et ve umut et\u201d de\u011fil.\u201d<\/p>\n\n\n\n Siz grafi\u011fi do\u011frulam\u0131yorsunuz. Metalin, geometrinin ve y\u00fck\u00fcn varsay\u0131mlar\u0131n\u0131zla uyumlu oldu\u011funu do\u011fruluyorsunuz.<\/p>\n\n\n\n \u00c7\u00fcnk\u00fc \u00f6nemli olan tek grafik, elinizdeki metalle uyumlu oland\u0131r.<\/p>\n\n\n\n At\u00f6lye Kural\u0131: \u0130lk vuru\u015f Kan\u0131t i\u00e7indir, par\u00e7alar i\u00e7in de\u011fil\u2014seriyi ba\u015flatmadan \u00f6nce her \u015feyi \u00f6l\u00e7\u00fcn.<\/strong><\/p>\n\n\n\n 1\/4 in\u00e7lik plakay\u0131 2 in\u00e7lik V-kal\u0131b\u0131 ile b\u00fck\u00fcyorsunuz. Ders kitab\u0131 8 Kural\u0131. A\u00e7\u0131 90\u00b0'yi buluyor, flan\u015f \u00f6l\u00e7\u00fcleri tam, herkes memnun. Bir sonraki i\u015f, ayn\u0131 kal\u0131nl\u0131k. Farkl\u0131 bir d\u00f6k\u00fcm partisi. Daha y\u00fcksek \u00e7ekme mukavemeti. Ayn\u0131 kurulum. Ram inliyor. A\u00e7\u0131 k\u0131sa kal\u0131yor. Tonaj\u0131 art\u0131r\u0131yorsunuz. \u015eimdi maksimum y\u00fckle fl\u00f6rt ediyorsunuz ve nedenini bilmiyorsunuz. [\u2026]<\/p>","protected":false},"author":3,"featured_media":922,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_breakdance_hide_in_design_set":false,"_breakdance_tags":"","footnotes":""},"categories":[1],"tags":[],"class_list":["post-917","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-uncategorized"],"_links":{"self":[{"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/posts\/917","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/comments?post=917"}],"version-history":[{"count":2,"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/posts\/917\/revisions"}],"predecessor-version":[{"id":923,"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/posts\/917\/revisions\/923"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/media\/922"}],"wp:attachment":[{"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/media?parent=917"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/categories?post=917"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/cn-hawe.com\/tr\/wp-json\/wp\/v2\/tags?post=917"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}\u201c8 Kural\u0131\u201dn\u0131n asl\u0131nda vadetti\u011fi \u015fey\u2014ve sessizce varsayd\u0131klar\u0131<\/h3>\n\n\n\n
![\""8](\"https:\/\/cn-hawe.com\/wp-content\/uploads\/2026\/03\/What-the-Rule-of-8-actually-promises\u2014and-what-it-silently-assumes_w1200_w1200.jpg\")
<\/figure>\n\n\n\n\n
Tonaj tuza\u011f\u0131: Referans tablolar\u0131n\u0131 garanti gibi kabul etti\u011finde ne olur<\/h3>\n\n\n\n
![\"Tonaj](\"https:\/\/cn-hawe.com\/wp-content\/uploads\/2026\/03\/The-tonnage-trap_w1200.jpg\")
<\/figure>\n\n\n\nNeden ayn\u0131 \u00e7izelgeyi kullanan iki operat\u00f6r tamamen farkl\u0131 sonu\u00e7lar al\u0131r<\/h3>\n\n\n\n
![\"Neden](\"https:\/\/cn-hawe.com\/wp-content\/uploads\/2026\/03\/Why-two-operators-using-the-exact-same-chart-get-completely-different-results_w1200_w1200.jpg\")
<\/figure>\n\n\n\nGizli Zincirleme Etki: V-Kal\u0131p Geni\u015fli\u011fi A\u015fa\u011f\u0131daki Her \u015eeyi Nas\u0131l Belirler<\/h2>\n\n\n\n
\n
\u0130\u00e7 b\u00fck\u00fclme yar\u0131\u00e7ap\u0131n\u0131n sabit bir girdi de\u011fil, V kal\u0131b\u0131 geni\u015fli\u011finin bir yan \u00fcr\u00fcn olmas\u0131n\u0131n nedeni<\/h3>\n\n\n\n
\u00c7arpan de\u011fi\u015fimi: 8\u00d7 kural\u0131n\u0131 ne zaman b\u0131rakmal\u0131\u20146\u00d7 (dar yar\u0131\u00e7aplar) veya 12\u00d7 (kal\u0131n levhalar) i\u00e7in<\/h3>\n\n\n\n
\n
Minimum kenar uzunlu\u011fu: \u0130deal V-a\u00e7\u0131l\u0131\u015f\u0131n\u0131z\u0131 ge\u00e7ersiz k\u0131lan sessiz geometri k\u0131s\u0131t\u0131<\/h3>\n\n\n\n
Tonaj\u0131 Yeniden Hesaplama: Makinenizi ve Tak\u0131mlar\u0131n\u0131z\u0131 Korumak<\/h2>\n\n\n\n
\n
Yumu\u015fak \u00e7elik varsay\u0131lan\u0131: Paslanmaz \u00e7elik ve al\u00fcminyum i\u00e7in tonaj\u0131 tahminden uzak bir \u015fekilde nas\u0131l \u00f6l\u00e7eklendirece\u011finiz.<\/h3>\n\n\n\n
Tak\u0131m y\u00fck limitleri ile makine kapasitesi: \u00d6nce hangi darbo\u011faza \u00e7arpacaks\u0131n\u0131z?<\/h3>\n\n\n\n
\n
Neden \u00e7izelgedeki ton\/ft de\u011feri keskin a\u00e7\u0131lar i\u00e7in at\u00f6lye ger\u00e7e\u011fiyle nadiren uyu\u015fur<\/h3>\n\n\n\n
Z\u0131mba Se\u00e7imi: \u00c7o\u011fu Tabloyun G\u00f6z Ard\u0131 Etti\u011fi Kritik De\u011fi\u015fken<\/h2>\n\n\n\n
Se\u00e7ti\u011finiz z\u0131mba, fiziksel olarak kenar\u0131 ve d\u00f6n\u00fc\u015f baca\u011f\u0131n\u0131 ge\u00e7ebilecek mi?<\/h3>\n\n\n\n
Minimum b\u00fckme yar\u0131\u00e7ap\u0131 ile i\u00e7 yar\u0131\u00e7ap: Malzeme \u00e7atlamas\u0131n\u0131 \u00f6nleyen fark<\/h3>\n\n\n\n
\n
Peki, z\u0131mba a\u00e7\u0131s\u0131 ve kal\u0131p a\u00e7\u0131s\u0131 hedef b\u00fckmenizle e\u015fle\u015fmedi\u011finde ne olur?<\/h3>\n\n\n\n
\u201cGrafik-Art\u0131\u201d S\u0131f\u0131r-Hurda B\u00fckme Kurulum \u0130\u015f Ak\u0131\u015f\u0131<\/h2>\n\n\n\n
Ad\u0131m 1: Grafi\u011fe dokunmadan \u00f6nce malzeme davran\u0131\u015f\u0131n\u0131 ve \u00e7arpanlar\u0131n\u0131 tan\u0131mlay\u0131n<\/h3>\n\n\n\n
P = ton cinsinden kuvvet
S = kal\u0131nl\u0131k (in\u00e7)
L = b\u00fckme uzunlu\u011fu (in\u00e7)
V = kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131 (in\u00e7)<\/p>\n\n\n\nAd\u0131m 2: Yar\u0131\u00e7ap hedeflerine ve flan\u015f ger\u00e7eklerine g\u00f6re V kal\u0131b\u0131n\u0131 belirleyin<\/h3>\n\n\n\n
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Ad\u0131m 3: Toplam tonaj\u0131 hem makine s\u0131n\u0131rlar\u0131na hem de tak\u0131m de\u011ferlerine g\u00f6re do\u011frulay\u0131n<\/h3>\n\n\n\n
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Ad\u0131m 4: Do\u011frulama d\u00f6ng\u00fcs\u00fc\u2014ilk test darbesinde ne \u00f6l\u00e7\u00fcl\u00fcr<\/h3>\n\n\n\n
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Ad\u0131m<\/th> Ba\u015fl\u0131k<\/th> Ana \u0130\u00e7erik<\/th> Form\u00fcller<\/th> At\u00f6lye Kural\u0131<\/th><\/tr><\/thead> Ad\u0131m 1<\/td> Grafi\u011fe dokunmadan \u00f6nce malzeme davran\u0131\u015f\u0131n\u0131 ve \u00e7arpanlar\u0131n\u0131 tan\u0131mlay\u0131n<\/td> Tak\u0131m grafikleri yumu\u015fak \u00e7eli\u011fi varsayar (~60.000 PSI \u00e7ekme dayan\u0131m\u0131). Malzeme de\u011fi\u015ftirmek dayan\u0131m \u00e7arpan\u0131 uygulamay\u0131 gerektirir. Dip b\u00fckme, hava b\u00fckmeden 2\u20134 kat daha fazla kuvvet gerektirir. Tak\u0131m se\u00e7meden \u00f6nce \u00e7ekme dayan\u0131m\u0131n\u0131 ve b\u00fckme y\u00f6ntemini tan\u0131mlay\u0131n.<\/td> Temel form\u00fcl:<\/strong>
P = (650 \u00d7 S\u00b2 \u00d7 L) \/ V
P = kuvvet (ton)
S = kal\u0131nl\u0131k (in\u00e7)
L = b\u00fckme uzunlu\u011fu (in\u00e7)
V = kal\u0131p a\u00e7\u0131kl\u0131\u011f\u0131 (in\u00e7)
Malzeme \u00c7arpan\u0131:<\/strong>
\u00c7arpan = \u00c7ekme \/ 60.000
D\u00fczeltilmi\u015f tonaj:<\/strong>
P_d\u00fczeltilmi\u015f = P_tablo \u00d7 Malzeme \u00c7arpan\u0131 \u00d7 Y\u00f6ntem \u00c7arpan\u0131<\/td>Malzeme \u00e7arpan\u0131 yaz\u0131lmam\u0131\u015f, tablo a\u00e7\u0131lmam\u0131\u015f.<\/td><\/tr> Ad\u0131m 2<\/td> V kanal\u0131n\u0131, yar\u0131\u00e7ap hedefleri ve flan\u015f ger\u00e7ekli\u011fine g\u00f6re sabitle<\/td> V kanal se\u00e7imi i\u00e7 yar\u0131\u00e7ap\u0131, tonaj\u0131 ve minimum flan\u015f uzunlu\u011funu kontrol eder. 8 kural\u0131 (V \u2248 8 \u00d7 kal\u0131nl\u0131k) sadece bir ba\u015flang\u0131\u00e7 noktas\u0131d\u0131r. V\u2019yi daraltmak kuvveti art\u0131r\u0131r. Her zaman \u00f6nce yar\u0131\u00e7ap ve flan\u015f gereksinimlerine g\u00f6re V se\u00e7in, ard\u0131ndan tonaj\u0131 yeniden hesaplay\u0131n.<\/td> \u0130\u00e7 yar\u0131\u00e7ap (hava b\u00fckme):<\/strong>
\u0130\u00e7 Yar\u0131\u00e7ap \u2248 0,16 \u00d7 V
Minimum flan\u015f:<\/strong>
Min Flan\u015f \u2248 V \/ 2
Tonaj ili\u015fkisi:<\/strong>
P \u221d 1 \/ V<\/td>Yar\u0131\u00e7ap ve flan\u015f ger\u00e7ekli\u011fi i\u00e7in V\u2019yi se\u00e7in, sonra tonaj sonucunu kabul edin.<\/td><\/tr> Ad\u0131m 3<\/td> Toplam tonaj\u0131 makine ve tak\u0131m limitlerine kar\u015f\u0131 do\u011frulay\u0131n<\/td> \u00c7arpanlar dahil toplam tonaj\u0131 hesaplay\u0131n. Hem toplam makine kapasitesini hem de ayak ba\u015f\u0131na ton de\u011ferlerini kontrol edin. Tak\u0131m derecelendirmeleri ve z\u0131mba ucundaki y\u00fck yo\u011funla\u015fmas\u0131 kritiktir. G\u00fcvenlik paylar\u0131 ekipman limitleri i\u00e7inde kalmal\u0131d\u0131r.<\/td> Toplam tonaj:<\/strong>
P_total = P \u00d7 Malzeme \u00c7arpan\u0131 \u00d7 Metot \u00c7arpan\u0131
Ayak ba\u015f\u0131na ton:<\/strong>
Ton\/ft = P_toplam \/ L (ft)<\/td>En d\u00fc\u015f\u00fck derecelendirmeye sahip bile\u015fen, neyin g\u00fcvenli oldu\u011funu belirler\u2014iyimserli\u011finiz de\u011fil.<\/td><\/tr> Ad\u0131m 4<\/td> Do\u011frulama d\u00f6ng\u00fcs\u00fc\u2014ilk test vuru\u015funda ne \u00f6l\u00e7\u00fclmeli<\/td> \u0130lk vuru\u015f te\u015fhis ama\u00e7l\u0131d\u0131r. \u0130\u00e7 yar\u0131\u00e7ap\u0131, k\u0131smi strokta b\u00fckme a\u00e7\u0131s\u0131n\u0131, flan\u015f stabilitesini ve temas desenini \u00f6l\u00e7\u00fcn. Alt oturma veya istenmeyen temas belirtilerine dikkat edin. \u00dcretimden \u00f6nce yap\u0131land\u0131r\u0131lm\u0131\u015f bir do\u011frulama d\u00f6ng\u00fcs\u00fcn\u00fc izleyin.<\/td> Do\u011frulama d\u00f6ng\u00fcs\u00fc:<\/strong>
Tahmin et \u2192 Hafif vur \u2192 \u00d6l\u00e7 \u2192 Kar\u015f\u0131la\u015ft\u0131r \u2192 Ayarla \u2192 Yeniden hesapla<\/td>\u0130lk vuru\u015f kan\u0131t i\u00e7indir, par\u00e7a i\u00e7in de\u011fil\u2014\u00fcretime ba\u015flamadan \u00f6nce her \u015feyi \u00f6l\u00e7\u00fcn.<\/td><\/tr><\/tbody><\/table><\/figure>","protected":false},"excerpt":{"rendered":"